Chapter 15 of 30 — the last of Part 3
- What a complete switched-mode power supply contains beyond the converter itself — and why most of a schematic is not the topology.
- Why a converter is a non-linear, time-varying system, and how averaging turns it into one a Bode plot can describe.
- Voltage-mode versus current-mode control: what each senses, what each fixes, and the \( D > 0.5 \) instability that forces slope compensation.
- How to design a Type II or Type III compensator by placing poles and zeros, and what phase margin actually buys.
- A complete loss budget: conduction, switching, gate drive, core, copper and control — and which one to attack first.
- Protection: current limit, overvoltage, thermal shutdown, soft start, and why the order they act in matters.
- The EMI problem a switching converter creates, and the standard remedies.
What Is Actually in a Power Supply
Open a real SMPS schematic after studying Chapters 12 to 14 and the first impression is disorientating: the converter you recognise occupies perhaps a fifth of the page. The rest is everything that makes it survivable, compliant and controllable.
Making a Switching Circuit Analysable
There is a difficulty to confront before any control design can begin. A converter has no fixed circuit — it has two circuits, alternating tens of thousands of times a second. Its describing equations are non-linear and time-varying, and none of the frequency-domain machinery of control theory applies to such a thing directly.
The resolution is state-space averaging, and its central idea is simple enough to state in one line: if the switching is much faster than anything the loop cares about, replace the two circuits with their weighted average.
A second-order low-pass with a resonance at \( f_0 = 1/(2\pi\sqrt{LC}) \), plus a zero at \( f_{ESR} = 1/(2\pi R_{ESR}C) \) contributed by the output capacitor's resistance.
Two features of that expression govern everything that follows.
- The \( LC \) double pole contributes −40 dB/decade of gain and, worse, up to −180° of phase above resonance. A loop crossing over above \( f_0 \) with no compensation would have essentially zero phase margin, which is to say it would oscillate.
- The ESR zero adds back up to +90°, which is genuinely helpful. This is why replacing a "poor" electrolytic with an excellent low-ESR ceramic has destabilised more than one working supply — the fix removed the phase the loop was relying on.
Voltage Mode and Current Mode
Every converter controller answers one question every cycle: when do I turn the switch off? There are two families of answer, and the choice shapes almost everything else about the supply.
- What is sensed: the output voltage only.
- How the pulse ends: a fixed-frequency sawtooth is compared with the error amplifier's output. The pulse ends when the ramp crosses it.
- The plant the loop sees: the full second-order \( LC \) response, so the compensator must supply a lot of phase — usually a Type III network.
- Strengths: a single feedback path, good noise immunity, works at any duty ratio, and behaves well at very light load.
- Weaknesses: no cycle-by-cycle current information, so current limiting must be added separately; input voltage changes are not seen until the output has already moved.
- What is sensed: the output voltage and the switch or inductor current.
- How the pulse ends: the sensed current is compared with the error amplifier's output. The pulse ends when the current reaches that level.
- The plant the loop sees: the inner current loop makes the inductor behave as a controlled current source, so the \( LC \) double pole becomes a single pole. First-order plant, much easier compensation — usually Type II.
- Strengths: inherent cycle-by-cycle current limit; immediate response to input voltage changes; automatic flux balancing in push–pull and bridge converters; easy current sharing between paralleled supplies.
- Weaknesses: needs a clean current signal in an electrically hostile place; requires slope compensation above \( D = 0.5 \); noise on the sense signal can terminate a pulse prematurely.
A perturbation is injected into the inductor current at the start of cycle 1, and the plot shows the error at the start of each subsequent cycle. Raise the duty ratio past 0.5 and watch it grow; then add slope compensation and watch it collapse.
—
| Criterion | Voltage mode | Current mode |
|---|---|---|
| Plant order seen by the loop | Second (\(LC\) double pole) | First |
| Compensator needed | Type III | Type II |
| Cycle-by-cycle current limit | Must be added | Inherent |
| Response to input step | Only after \(V_o\) moves | Immediate (feed-forward) |
| Flux balancing in bridges | No | Automatic |
| Paralleling and current share | Difficult | Easy |
| Above \(D = 0.5\) | No issue | Needs slope compensation |
| Noise sensitivity | Low | Higher — needs careful sensing |
| Very light load | Well behaved | Current signal becomes tiny |
Designing the Compensator
The compensator's task is to shape the loop gain so that it is large at low frequency (for accuracy), crosses unity at a chosen frequency (for speed), and has adequate phase margin there (for stability).
- Choose the crossover frequency Take \( f_c \approx f_s/10 \) as a starting point. If the converter is indirect, cap it instead at \( f_{RHPZ}/5 \) — whichever is lower governs.
- Plot the plant's gain and phase at \(f_c\) From the averaged model of Section 15-2. The compensator must supply exactly the gain needed to bring the loop to 0 dB at \( f_c \).
- Work out the phase you must add
The \( 90^\circ \) accounts for the integrator every compensator has at the origin. Target \( \phi_{margin} = 45^\circ \) to \( 60^\circ \).Working\[ \phi_{boost} = \phi_{margin} - \phi_{plant} - 90^\circ \]
- Pick the network from the phase required Up to about 90° of boost calls for a Type II network (one pole at the origin, one zero, one pole). Beyond that — which a voltage-mode buck always needs — use Type III (one pole at the origin, two zeros, two poles).
- Place the zeros and poles Put the zeros at or just below the \( LC \) resonance, so their phase lead arrives where the double pole's lag does. Put the high-frequency poles at the ESR zero and at about \( f_s/2 \), to roll the gain off before the switching frequency.
More phase margin is not always better: beyond about 70° the response becomes sluggish, and the transient dip that the loop was supposed to correct simply lasts longer. 45–60° is the practical window.
Where the Power Goes
A 90% efficient 100 W supply dissipates 11 W. Knowing which 11 W is the difference between improving it and guessing.
| Loss | Expression | Scales with | Reduce by |
|---|---|---|---|
| Switch conduction | \(I_{rms}^2 R_{DS(on)}\) | Load² | Larger die, parallel devices, lower \(V_{BR}\) |
| Switching | \(\tfrac12 V I (t_r + t_f) f\) | \(f\), load | Faster gate drive, soft switching, lower \(f\) |
| Gate drive | \(Q_g V_g f\) | \(f\) | Lower \(Q_g\) device, resonant gate drive |
| Diode conduction | \(V_F I_{avg}\) | Load | Schottky, or synchronous rectification |
| Reverse recovery | \(Q_{rr}V f\) | \(f\) | Schottky or SiC diode, slower \(di/dt\) |
| Core loss | \(k f^\alpha B^\beta\) | \(f^{1.3}\), \(B^{2.5}\) | Better material, lower \(B\), more turns |
| Copper loss | \(I_{rms}^2 R_{dc}\,F_R\) | Load² | Litz wire, interleaving, thicker copper |
| Capacitor ESR | \(I_{ripple(rms)}^2 R_{ESR}\) | Ripple² | Parallel capacitors, ceramics |
| Control and bias | \(V_{cc}I_{cc}\) | Fixed | Matters only at light load — but then it dominates |
Protection and Start-Up
A power supply must fail safely — into a controlled shutdown, never into a fire or an overvoltage that destroys everything downstream. Five mechanisms do this work, and the order in which they act is part of the design.
- The problem: at power-up the output capacitor is at zero, so the error is maximal and the loop demands maximum duty ratio. The inrush is limited only by the inductor.
- The mechanism: ramp the reference, not the output, over 1–20 ms. The loop then sees a small error throughout and behaves normally.
- A subtlety worth knowing: the soft-start time must exceed the loop's settling time, or the loop chases a reference moving faster than it can follow and saturates — producing an overshoot at the end of the ramp, which is exactly what soft start existed to prevent.
- Cycle-by-cycle limiting: terminate each pulse when the current reaches a threshold. Fast, and inherent in current-mode control.
- Hiccup mode: on a persistent fault, shut down for tens of milliseconds and retry. Average dissipation into a short falls to a few percent, so nothing overheats while the fault persists.
- Latch-off: shut down until power is cycled. Safest, but requires user intervention — used where a repeated retry could itself be hazardous.
- Foldback: reduce the current limit as the output voltage falls, so a hard short draws less than a mild overload. Effective, but it can prevent start-up into a large capacitive load — a classic and frustrating fault.
- OVP: guards against a broken feedback path. If the optocoupler fails open, the controller sees zero output and goes to maximum duty ratio — so OVP must sense the output independently of the normal feedback, or it protects nothing.
- OTP: shuts down at a measured die or heatsink temperature, with hysteresis so it does not chatter. Usually restarts automatically once cool.
- UVLO: holds the controller off until its bias supply is high enough to drive the gates properly. Without it, at low bias the switch turns on only partially and dissipates enormously — a common cause of failures at power-up and during brownouts.
Worked Examples
Problem. A buck converter has \( V_s = 12 \) V, \( V_o = 3.3 \) V, \( L = 4.7\ \mu\text{H} \), \( C = 100\ \mu\text{F} \), \( R_{ESR} = 5\ \text{m}\Omega \), \( R = 3.3\ \Omega \), \( f_s = 500 \) kHz. Find the plant's resonance, the ESR zero, and a sensible crossover frequency.
What the numbers are telling you. Crossover at 50 kHz is nearly seven times above the \( LC \) resonance, so the plant is well into its −40 dB/decade region and contributing close to −180° of phase. The ESR zero is at 318 kHz — far too high to help at crossover.
Consequence: a Type III compensator is required. Type II cannot supply the ~110° of boost this needs. Place the two zeros near 7 kHz to counter the double pole, one pole at the ESR zero (318 kHz) and one at \( f_s/2 \) (250 kHz).
Note the modern-ceramic effect. With a 5 mΩ ceramic the ESR zero is out of reach. An older design using a 100 mΩ electrolytic would have had its zero at 16 kHz — right where it helps — and could have used a simpler Type II network. Better capacitors made the compensator harder, which is a genuinely counter-intuitive consequence worth remembering.
Problem. A current-mode boost converter runs at \( V_s = 12 \) V, \( V_o = 48 \) V, \( L = 33\ \mu\text{H} \), \( f_s = 250 \) kHz. Determine whether slope compensation is needed and, if so, how much.
\( D = 0.75 > 0.5 \), so compensation is mandatory. Without it the growth factor is \( m_2/m_1 = 3.0 \) — a disturbance triples every cycle, and the converter reaches full sub-harmonic oscillation within four or five cycles.
Choose the 50% value. It gives a per-cycle multiplier of \( -(1.09-0.545)/(0.364+0.545) = -0.60 \) — comfortably stable, and stable at every duty ratio this converter can reach, without discarding all the current information that made current mode worth choosing.
Turning that into a circuit. With a 50 mΩ sense resistor the ramp must be \( 0.545 \times 0.05 = 27 \) mV/μs added to the sense signal, or 109 mV over one 4 μs period. Most controller ICs provide an internal ramp; where it is insufficient, the standard method is a resistor from the oscillator ramp into the current-sense node.
Confirm with the explorer above: set D = 0.75 and slide the compensation to 0.50 — the growth factor reads 0.60. Push it to 1.00 and it falls to zero.
Problem. A 12 V to 5 V, 10 A synchronous buck runs at 300 kHz. High-side \( R_{DS(on)} = 8\ \text{m}\Omega \), low-side \( 4\ \text{m}\Omega \), \( Q_g = 15 \) nC each at 8 V, \( t_r + t_f = 20 \) ns, inductor DCR \( = 3\ \text{m}\Omega \), core loss 250 mW, controller 15 mA at 12 V. Find each loss and the efficiency.
\( D = 5/12 = 0.417 \), \( P_o = 50 \) W.
Reading the budget. Switching loss (0.36 W) and high-side conduction (0.33 W) lead, with inductor DCR close behind. No single term dominates, which is the signature of a balanced design — and it means no single change will improve it much.
Now change the load and watch the answer invert. At 1 A output the \( I^2 \) terms fall by 100× to about 9 mW total, while gate drive, core and controller stay at 0.5 W. Efficiency drops to roughly 91%, and the fix is no longer better silicon — it is burst mode.
Problem. A 5 V supply is stable at full load but oscillates at about 2 kHz below 10% load. It switches at 200 kHz. What is happening, and what would you do?
First, read the frequency. 2 kHz is far below \( f_s \), so this is not sub-harmonic oscillation (which would appear at \( f_s/2 = 100 \) kHz). A low-frequency oscillation is a loop instability, and 2 kHz is very likely near the loop's crossover frequency.
Why light load specifically? Three plausible mechanisms, and they can be separated by measurement:
- Reduced damping of the \( LC \) resonance. The load resistance damps the double pole. At 10% load, \( R \) is ten times higher, the \( Q \) rises sharply, and the resonance peak can push the gain above unity where the phase has already passed −180°.
- Entry into DCM. The plant changes from second order to first, so the crossover frequency moves and the compensator's carefully placed zeros are now in the wrong places.
- Loss of the ESR zero's help. If the design relied on the ESR zero for phase margin and the ripple current has fallen, the effective ESR contribution changes.
How to distinguish them. Look at the inductor current with a current probe. If it reaches zero, it is DCM (mechanism 2). If it does not, and the oscillation frequency matches \( 1/(2\pi\sqrt{LC}) \), it is the undamped resonance (mechanism 1).
The remedies, in increasing order of intervention:
- Reduce the crossover frequency so there is margin at the worst case. Costs transient performance, but it is one component change.
- Force continuous conduction using the synchronous FET, so the plant never changes order. Costs light-load efficiency.
- Add a minimum load — a bleed resistor. Crude, wasteful, and sometimes the pragmatic answer late in a project.
- Add series damping — a resistor and capacitor across the output — to damp the resonance without dissipating at DC.
- Switch to current-mode control, which removes the double pole entirely. The best answer, and the most disruptive.
The lesson. This is the failure the "verify across the whole envelope" warning in Section 15-4 exists to prevent — and it is why loop gain should be measured at light load, not just at full load.
Summary & Formula Sheet
Chapter 15, and Part 3, in five sentences:
- A power supply is a converter plus an EMI filter, bulk storage, a feedback loop, soft start and protection — and the converter is the smallest part of the effort.
- Averaging the two switch states and linearising gives an ordinary transfer function, valid up to about \( f_s/3 \), on which normal control design works.
- Current-mode control collapses the plant to first order and brings an inherent current limit, flux balancing and current sharing — at the price of slope compensation above \( D = 0.5 \).
- Design the compensator for 45–60° of phase margin at \( f_c \approx f_s/10 \), then verify it at every corner of the input, load and temperature envelope.
- Full-load efficiency is a conduction problem and light-load efficiency is a frequency problem; the remedies are completely different.
Key terms
- State-space averaging
- Replacing the two switch-state circuits with their duty-weighted average, then linearising, to obtain a transfer function.
- Voltage-mode control
- The pulse ends when a fixed ramp crosses the error voltage. Second-order plant; needs Type III compensation.
- Current-mode control
- The pulse ends when the sensed current reaches the error voltage. First-order plant; inherent current limit.
- Sub-harmonic oscillation
- Alternating wide and narrow pulses at \(f_s/2\), occurring in peak-current mode above \(D = 0.5\).
- Slope compensation
- An artificial ramp added to the sensed current. \(m_a = m_2/2\) is stable at any duty ratio; \(m_a = m_2\) gives deadbeat response.
- Type II / Type III compensator
- Networks providing up to about 90° and 180° of phase boost respectively. Type II suits current mode; Type III is needed for voltage mode.
- Phase margin
- How far the loop phase is from −180° at unity gain. 45–60° gives a well-damped response without sluggishness.
- Soft start
- Ramping the reference at power-up so the loop is never saturated and the inrush is controlled.
- Hiccup mode
- Shutting down and retrying periodically during a persistent fault, so average dissipation stays low.
- UVLO
- Under-voltage lockout: holding the controller off until its bias is sufficient to drive the gates fully.
- Burst mode
- Delivering groups of pulses separated by idle intervals at light load, cutting all frequency-dependent losses.
- Hold-up time
- How long the output stays in regulation after the input is removed. Set by the bulk capacitor's stored energy.
Test Yourself
A designer replaces a supply's electrolytic output capacitor with a ceramic of the same value and better ESR. The supply now oscillates. Why did an improvement break it?
Because the loop was relying on the electrolytic's ESR zero for its phase margin, and the "improvement" removed it.
The plant's zero. The buck's control-to-output response contains a zero at \( f_{ESR} = 1/(2\pi R_{ESR}C) \), contributed by the capacitor's resistance. A zero adds up to +90° of phase — genuinely useful help against the \( LC \) double pole's −180°.
Put numbers on the change. With \( C = 220\ \mu\text{F} \):
- Electrolytic, \( R_{ESR} = 80\ \text{m}\Omega \): \( f_{ESR} = 9 \) kHz — right at a typical crossover, contributing 40–50° of phase.
- Ceramic, \( R_{ESR} = 3\ \text{m}\Omega \): \( f_{ESR} = 241 \) kHz — far above crossover, contributing essentially nothing.
So the loop lost about 45° of phase margin overnight. If it had 50° before, it now has 5°, which is oscillation.
And a second effect compounds it. The ESR also damped the \( LC \) resonance. Removing it raises the \( Q \) sharply, producing a tall gain peak at \( f_0 \) that can push the loop above unity gain where the phase is already through −180°.
Two more traps in the same substitution:
- DC bias. A Class-II ceramic marked 220 μF may deliver 80 μF at its working voltage. So \( f_0 \) moves too, and not in a helpful direction.
- Undamped input filter. Ceramics on the input can resonate with the supply-lead inductance with almost no damping, producing a peak that violates the Middlebrook criterion and destabilises the loop from the input side.
The correct procedure: re-derive the plant with the new capacitor, redesign the compensator (usually adding phase boost to replace what the ESR provided), and add explicit damping — either a small series resistor or a parallel electrolytic acting purely as a damper. Capacitors are not interchangeable on capacitance alone.
Why does current-mode control automatically prevent flux walking, when voltage-mode control cannot?
Because the primary current is a proxy for the flux, and current-mode control regulates it directly.
The flux-walking mechanism (Chapter 14): in a push–pull or bridge converter, if one half-cycle applies more volt-seconds than the other, the core does not return to its starting flux. The offset accumulates until it saturates.
Voltage mode is blind to it. The pulse ends when the sawtooth crosses the error voltage — a timing decision that carries no information about the core's state. A systematic asymmetry stays systematic.
Current mode measures the thing that matters. In a transformer, \( i_{primary} = i_{magnetising} + i_{load,reflected} \), and \( i_{magnetising} \propto \) flux. So the sensed current contains the flux information. The pulse ends when that current reaches a threshold, which means:
- A half-cycle that starts from an elevated flux reaches the threshold sooner.
- Its pulse is therefore shorter, applying fewer volt-seconds.
- The flux is pushed back toward centre — automatically, every cycle, with no extra components.
This is negative feedback on the flux itself, and it is the main reason current-mode control dominates isolated converter design. The loop-shaping advantages usually cited first are real but secondary.
Two limits worth knowing:
- It corrects volt-second asymmetry, not asymmetry in the sensing. A current transformer that behaves differently on the two half-cycles introduces its own walk.
- Above \( D = 0.5 \) it needs slope compensation, and heavy compensation dilutes the flux information — so a heavily compensated current-mode controller balances flux less effectively.
Production practice is to use both defences: current-mode control and a DC blocking capacitor in series with the primary. Neither is expensive, and the failure they prevent destroys the converter.
A supply must maintain its output for 20 ms after a mains dropout. How does that requirement size the bulk capacitor, and what else does it affect?
The energy argument. During the dropout the converter draws its power entirely from the bulk capacitor, whose voltage falls from the nominal rectified value \( V_1 \) to the lowest input the converter can still regulate from, \( V_2 \):
\[ \tfrac12 C(V_1^2 - V_2^2) = P_o\,t_{hold} \;\Longrightarrow\; C = \frac{2P_o t_{hold}}{V_1^2 - V_2^2} \]
A worked instance. A 200 W supply on 230 V AC has \( V_1 \approx 325 \) V. If the converter regulates down to 200 V:
\[ C = \frac{2(200)(0.02)}{325^2 - 200^2} = \frac{8}{65625} = 122\ \mu\text{F} \]
Add 20% for tolerance and end-of-life capacitance loss, and specify 150 μF, 450 V.
What else the requirement affects — and this is the part usually missed:
- The converter's input range must be wide. Regulating down to 200 V from a 325 V nominal is a 1.6:1 range that exists solely for hold-up. Design the duty ratio and turns ratio accordingly.
- Inrush current. A 150 μF capacitor charging from a cold mains connection draws hundreds of amps unless limited. An NTC thermistor or a relay-bypassed resistor becomes mandatory.
- Physical size. A 150 μF, 450 V electrolytic is one of the largest components in the supply and often dictates the enclosure height.
- Lifetime. Electrolytics age, losing capacitance and gaining ESR. A supply that just meets 20 ms when new may fail at 15 ms after five years — so the design must allow margin, and lifetime calculation at the operating temperature is part of the work.
The design lever. Note that \( C \propto 1/(V_1^2 - V_2^2) \), so widening the converter's input range is far more effective than adding capacitance. Dropping \( V_2 \) from 250 V to 150 V nearly halves the capacitor. This is why hold-up requirements and converter input range are decided together, not separately.
Why is 90° of phase margin worse than 60°, when more margin sounds like more stability?
Because phase margin buys damping, and past a certain point extra damping is simply slowness.
The mapping between phase margin and transient response:
- 30°: \( \zeta \approx 0.3 \). Several cycles of ringing, 30–40% overshoot. Marginal.
- 45°: \( \zeta \approx 0.45 \). One small overshoot, quick settling. Acceptable.
- 60°: \( \zeta \approx 0.6 \). Almost no overshoot, fastest overall settling. Optimal.
- 90°: \( \zeta \approx 1 \). No overshoot at all, but a slow exponential approach.
Why 90° hurts in a converter specifically. Achieving it requires rolling the loop gain off much earlier, which lowers the crossover frequency — often by a factor of two or three. And crossover frequency is what determines how fast the loop can correct a load transient.
Follow a 5 A load step through both designs. The output capacitor supplies the step alone until the loop responds. With a 50 kHz crossover the loop reacts in roughly 20 μs; at 15 kHz it takes 70 μs. The voltage dip is more than three times deeper — and the dip is what the specification limits, not the phase margin.
So the objective is not maximum phase margin. It is the highest crossover frequency consistent with adequate margin across the whole operating envelope. Excess margin at nominal is wasted bandwidth.
The one legitimate reason to take more margin is uncertainty. If the plant moves substantially — a wide input range, high-tolerance capacitors, a converter that enters DCM — designing for 60° at nominal may leave only 35° at the corners. Then the extra margin is not conservatism; it is a correct allowance for a plant you cannot pin down. The distinction is whether you have measured the envelope or are guessing at it.
A supply passes efficiency tests at full load but fails a standard at 10% load. What is going wrong, and what would you change first?
Fixed losses that do not scale with load are now a large fraction of a small output.
Split the losses. At 10% load the current is a tenth, so every \( I^2R \) term is a hundredth of what it was. What remains is everything that runs regardless:
- Gate drive: \( Q_gV_gf \) — the same charge every cycle, whatever the switch carries.
- Switching loss: reduced but not proportionally, since the voltage transitions still happen \( f \) times a second.
- Core loss: set by flux swing, which follows the input voltage and duty ratio, not the load.
- Controller bias, feedback divider, snubbers, bleed resistors: all constant.
- Circulating current if the synchronous rectifier is in forced-CCM mode — actively wasteful at light load.
Every one of those is proportional to \( f \) or is a fixed drain, so the answer is to switch less often. In order of what to try first:
- Enable diode emulation. Usually a single pin or register change, and it stops the reverse circulating current immediately. Try this first because it costs nothing.
- Enable burst mode or pulse skipping. Deliver a group of pulses, then idle. The effective frequency falls by orders of magnitude, and 10%-load efficiency typically rises 10–20 points.
- Frequency foldback if burst mode produces audible or ripple problems — a smooth reduction of \( f \) with load.
- Reduce the fixed drains: raise the feedback divider's resistance, remove unnecessary bleed resistors, use a controller with a low-power sleep state.
- Shed phases in a multiphase design — run one instead of four.
The trade to watch. Burst mode increases output ripple, since the output droops between bursts. If the load cannot tolerate that, frequency foldback is the compromise. And burst repetition rates in the audible band can make ceramic capacitors sing — so the burst frequency is chosen deliberately, usually above 20 kHz or below 20 Hz.
Part 3 has covered eight topologies. Given a new specification, what is the order of questions that leads to the right one?
Five questions, in this order. Each one eliminates a class of answers, so the order matters.
1. Is isolation required?
- Yes — mains-connected, or a safety standard demands it: Chapter 14. Everything non-isolated is eliminated immediately.
- No — a low-voltage rail from a low-voltage source: Chapters 12 and 13.
2. Up, down, or both?
- Down only: buck — the simplest, most efficient, and the only one with no RHP zero.
- Up only: boost.
- Both: buck–boost, Ćuk, SEPIC, Zeta, or a four-switch buck–boost.
3. What power level? This is where isolated designs separate:
- Below 150 W: flyback.
- 150–500 W: forward, preferably two-switch.
- 500 W–2 kW: half-bridge or full-bridge.
- Above 2 kW: full-bridge, phase-shifted for soft switching.
4. Which port must be quiet?
- Input (battery, PV panel, strict conducted-emissions limit): boost or SEPIC — continuous input current.
- Output (sensitive analogue load, LED string): buck, forward or Zeta — continuous output current.
- Both: Ćuk, or accept two stages.
5. How fast must it respond?
- Fast (a processor rail, a servo): it must be a direct converter — buck or forward. Indirect topologies are capped by their RHP zero.
- Slow is fine (a battery charger, an LED driver): anything.
Why this order. Question 1 is a legal constraint, so it is absolute. Question 2 is arithmetic. Questions 3 and 4 are engineering economics. Question 5 is a control-theory limit that no amount of design effort will circumvent — so it belongs last, where it eliminates what remains rather than everything.
And when the answers conflict — a fast response from a wide-ranging isolated input, say — the resolution is almost always two stages: an indirect stage to make an intermediate bus, then a direct stage to regulate it quickly. Recognising when a single stage cannot satisfy the specification is the most useful judgement in this chapter.
Problems
Three habits for the whole of Part 3:
- Establish the conduction mode before using any gain formula.
- Verify at the corners of the envelope, never at the nominal point alone.
- Separate load-dependent from frequency-dependent losses before trying to improve an efficiency figure.
Problems 1–5 are direct application; 6–9 need judgement; 10–12 are design questions worth discussing in a tutorial.
- A buck converter has \( L = 10\ \mu\text{H} \), \( C = 220\ \mu\text{F} \), \( R_{ESR} = 25\ \text{m}\Omega \), \( f_s = 400 \) kHz. Find the \( LC \) resonance, the ESR zero, and a sensible crossover frequency. State whether Type II or Type III compensation is needed.
- A current-mode buck runs at \( V_s = 24 \) V, \( V_o = 15 \) V, \( L = 22\ \mu\text{H} \). Determine whether slope compensation is required and, if so, find the minimum, the 50% and the deadbeat values of \( m_a \).
- A 150 W supply must hold up for 16 ms after mains loss. The rectified link is 325 V and the converter regulates down to 180 V. Find the required bulk capacitance, and state two other design consequences.
- For the synchronous buck of Worked Example 3, recompute the efficiency at 1 A output and identify the dominant loss.
- A boost converter has \( R = 25\ \Omega \), \( L = 68\ \mu\text{H} \), \( D = 0.55 \), \( f_s = 150 \) kHz. Find the RHP zero, the maximum usable crossover frequency, and compare it with \( f_s/10 \).
- Explain why an optocoupler's current transfer ratio degrading by 40% over ten years affects loop stability, and how a design should allow for it.
- A current-mode flyback shows alternating wide and narrow pulses at high line but not at low line. Explain the observation and give the fix.
- A converter is stable at 25 °C and oscillates at −20 °C. List three temperature-dependent mechanisms that could explain it, and the measurement that would identify each.
- Compare voltage-mode and current-mode control for (a) a 2 kW full-bridge welding supply and (b) a 5 V, 1 A auxiliary rail that must run at very light load most of the time. Recommend one for each with reasons.
- Design the complete control loop for a 12 V, 5 A synchronous buck from 24 V at 300 kHz with \( L = 15\ \mu\text{H} \) and \( C = 200\ \mu\text{F} \) (ESR 4 mΩ). Choose a control mode, a crossover frequency and a compensator type, place the poles and zeros, and state the phase margin you expect.
- A 500 W supply achieves 94% at full load, 89% at 20% load and 71% at 5% load. Produce a loss model consistent with these three points, separating fixed and load-dependent terms, and propose the two changes most likely to improve the 5% figure.
- An engineer must select a topology for a 300 W supply from a 200–400 V DC source to a 48 V output, with isolation required, a 100 μs response to a 50% load step, and conducted-emissions limits at the input. Work through the five selection questions of the last quick-check, state where the requirements conflict, and propose an architecture that satisfies all of them.