Wave Propagation on Transmission Lines
A line by itself merely carries a wave; the drama begins at the far end. If the load does not match the line's characteristic impedance, some of the wave bounces back, and the forward and reflected waves interfere into a standing pattern that makes the impedance look different at every point. This chapter works out exactly how: the reflection coefficient set by the load, the way its phase winds as you move along the line, the input impedance you measure looking in, and the standing-wave ratio you read on a meter. From these come the two most useful tricks on any line — the quarter-wave transformer and the half-wave repeater — and the groundwork for the Smith chart that comes next.
- The load reflection coefficient \(\Gamma_L=(Z_L-Z_0)/(Z_L+Z_0)\) and what its size and sign mean.
- How the reflection coefficient's phase rotates as you move back along the line.
- The master input-impedance formula and its lossless \(\tan\beta\ell\) form.
- Short-circuit, open-circuit, and matched lines, and how shorted lines synthesize reactances.
- Standing waves, voltage maxima and minima, and the standing-wave ratio \(s\).
- The quarter-wave transformer \(Z_0'=\sqrt{Z_0 Z_L}\) and the half-wave repeater.
The Terminated Line
Take the lossless line of Chapter 23, characteristic impedance \(Z_0\), and connect a load \(Z_L\) at its far end. A source launches a forward wave toward the load; whatever the load cannot absorb it sends back as a reflected wave. We measure position by the distance \(\ell\) from the load back toward the generator, so the load sits at \(\ell=0\) and the generator at \(\ell=\) (line length). The total voltage and current are the sum of the two travelling waves:
Reflection Coefficient at the Load
At the load the ratio of voltage to current must equal \(Z_L\). Imposing \(V(0)/I(0)=Z_L\) on the expressions above solves immediately for the ratio of reflected to incident voltage — the load reflection coefficient:
This is the same formula as the plane-wave reflection coefficient at a boundary in Chapter 22, with \(Z_L\) and \(Z_0\) playing the roles of \(\eta_2\) and \(\eta_1\) — transmission-line reflection is boundary reflection, dressed in circuit language. Its value tells the whole story of the termination: a matched load (\(Z_L=Z_0\)) gives \(\Gamma_L=0\) and no reflection; a short (\(Z_L=0\)) gives \(\Gamma_L=-1\); an open (\(Z_L\to\infty\)) gives \(\Gamma_L=+1\). For any passive load \(|\Gamma_L|\le1\). A complex \(Z_L\) makes \(\Gamma_L\) complex, with a phase angle \(\theta_\Gamma\) that we will need in a moment.
Reflection Along the Line
The reflection coefficient is not confined to the load — we can define it at any point as the ratio of the reflected to the incident voltage there. Moving a distance \(\ell\) back toward the generator, the forward wave gains phase \(e^{j\beta\ell}\) and the reflected wave loses it, so their ratio winds by \(e^{-2j\beta\ell}\):
On a lossless line the magnitude \(|\Gamma(\ell)|=|\Gamma_L|\) never changes — only the phase rotates, completing a full turn every half wavelength (since \(2\beta\cdot\tfrac{\lambda}{2}=2\pi\)). That periodicity is why everything on a line repeats every \(\lambda/2\), and it is the kinematic heart of the Smith chart. On a lossy line the factor \(e^{-2\alpha\ell}\) also shrinks the magnitude as you retreat from the load, spiralling \(\Gamma\) inward.
Input Impedance
The impedance seen looking into the line at distance \(\ell\) is \(Z_{\text{in}}(\ell)=V(\ell)/I(\ell)\). Writing it through the local reflection coefficient gives a compact form, and substituting \(\Gamma(\ell)\) yields the celebrated input-impedance equation:
For the lossless line \(\gamma=j\beta\) and \(\tanh(j\beta\ell)=j\tan\beta\ell\), giving the form used in nearly every problem:
This one equation replaces a whole network of reactances: knowing \(Z_0\), the load, and how many wavelengths of line stand between you and it, you can read off the impedance the generator actually drives. It is periodic in \(\ell\) with period \(\lambda/2\) — the same repetition the reflection coefficient showed — and it is the formula behind every length the rest of the chapter chooses on purpose.
Short, Open, and Matched Lines
Three terminations are worth singling out, both because they are common and because they reveal what a length of line can do on its own. Setting \(Z_L=0\), \(Z_L\to\infty\), and \(Z_L=Z_0\) in the lossless formula gives:
| Termination | \(\Gamma_L\) | Input impedance \(Z_{\text{in}}(\ell)\) | Behaviour |
|---|---|---|---|
| Matched (\(Z_L=Z_0\)) | \(0\) | \(Z_0\) at every \(\ell\) | no reflection, flat line |
| Short circuit (\(Z_L=0\)) | \(-1\) | \(jZ_0\tan\beta\ell\) | pure reactance |
| Open circuit (\(Z_L\to\infty\)) | \(+1\) | \(-jZ_0\cot\beta\ell\) | pure reactance |
Both the shorted and open lines look purely reactive from the input — no power is dissipated, so all of it returns. By choosing the length \(\ell\), a shorted stub can be made to present any inductance or capacitance you like, which is how reactive elements are built at microwave frequencies where lumped coils and capacitors fail. A neat by-product: measuring the shorted and open input impedances of an unknown line at the same length gives its characteristic impedance directly, \(Z_0=\sqrt{Z_{\text{sc}}\,Z_{\text{oc}}}\).
Standing Waves and SWR
Wherever a reflection exists, the forward and backward waves interfere. Their sum has a magnitude that varies with position: \(|V(\ell)|=|V_0^{+}|\,|1+\Gamma_L e^{-2j\beta\ell}|\). It peaks where the two waves add in phase and dips where they oppose, producing a fixed standing-wave pattern:
The ratio of these is the standing-wave ratio — identical to the one defined for plane waves in Chapter 22, and the single number most often used to judge a match:
A matched line has \(s=1\) (flat, no standing wave); a short or open has \(s\to\infty\). The pattern carries usable information: at a voltage maximum the line impedance is purely real and equal to \(sZ_0\); at a voltage minimum it is \(Z_0/s\). Sliding a probe along a slotted line to find these extrema was the classic way to measure an unknown load before network analysers — and the voltage minima, sharp and easy to locate, were the preferred reference points.
Quarter-Wave and Half-Wave Lines
Two special lengths drop out of the input-impedance formula and are used constantly. A half-wavelength of line (\(\beta\ell=\pi\), so \(\tan\beta\ell=0\)) returns the load impedance unchanged — the line is invisible, repeating whatever it is terminated in every \(\lambda/2\):
A quarter-wavelength (\(\beta\ell=\pi/2\), so \(\tan\beta\ell\to\infty\)) does the opposite — it inverts the load about \(Z_0\), turning a high impedance into a low one and vice versa:
That inversion is a ready-made matching tool. To match a real load \(R_L\) to a line of impedance \(Z_0\), splice in a quarter-wave section whose own impedance is the geometric mean of the two — a quarter-wave transformer:
It is exact only at the frequency where the section is precisely \(\lambda/4\), so it is inherently narrowband — but simple, lossless, and everywhere in antenna feeds and microwave circuits. Matching a complex load, or doing it over a band, is the broader problem the next chapter solves graphically with the Smith chart.
Worked Examples
Problem. A \(50\,\Omega\) line is terminated in \(Z_L=100\,\Omega\). Find \(\Gamma_L\) and the standing-wave ratio.
Solution. Apply \(\Gamma_L=(Z_L-Z_0)/(Z_L+Z_0)\), then \(s=(1+|\Gamma_L|)/(1-|\Gamma_L|)\):
Problem. For the \(50\,\Omega\) line with \(Z_L=100\,\Omega\), find \(Z_{\text{in}}\) at \(\ell=\lambda/8\) (so \(\beta\ell=\pi/4\), \(\tan\beta\ell=1\)).
Solution. Use the lossless formula with \(\tan\beta\ell=1\):
Problem. A \(50\,\Omega\) short-circuited line of length \(\lambda/8\) operates at \(1\,\text{GHz}\). What reactance does it present, and what inductance is that?
Solution. With \(Z_{\text{sc}}=jZ_0\tan\beta\ell\) and \(\tan(\pi/4)=1\):
Problem. Match a \(100\,\Omega\) resistive load to a \(50\,\Omega\) line with a quarter-wave section. Find its impedance \(Z_0'\).
Solution. Use \(Z_0'=\sqrt{Z_0 R_L}\):
Problem. A \(73\,\Omega\) antenna is fed through exactly a half wavelength of \(50\,\Omega\) line. What input impedance does the transmitter see?
Solution. At \(\ell=\lambda/2\), \(\tan\beta\ell=0\), so the line repeats the load regardless of \(Z_0\):
Problem. A line of unknown \(Z_0\) reads \(Z_{\text{sc}}=j100\,\Omega\) shorted and \(Z_{\text{oc}}=-j25\,\Omega\) open, at the same length. Find \(Z_0\).
Solution. Use \(Z_0=\sqrt{Z_{\text{sc}}Z_{\text{oc}}}\):
Chapter Summary
\(\Gamma_L=\dfrac{Z_L-Z_0}{Z_L+Z_0}\); \(0\) matched, \(-1\) short, \(+1\) open.
\(\Gamma(\ell)=\Gamma_L e^{-2j\beta\ell}\); phase turns once per \(\lambda/2\), \(|\Gamma|\) fixed if lossless.
\(Z_{\text{in}}=Z_0\dfrac{Z_L+jZ_0\tan\beta\ell}{Z_0+jZ_L\tan\beta\ell}\).
\(Z_{\text{sc}}=jZ_0\tan\beta\ell\), \(Z_{\text{oc}}=-jZ_0\cot\beta\ell\); pure reactances.
\(s=\dfrac{1+|\Gamma_L|}{1-|\Gamma_L|}\); maxima see \(sZ_0\), minima \(Z_0/s\).
\(\lambda/2\): \(Z_{\text{in}}=Z_L\). \(\lambda/4\): \(Z_{\text{in}}=Z_0^2/Z_L\), match with \(\sqrt{Z_0 R_L}\).
Problems
For each item, find \(\Gamma_L\) first — it fixes the SWR and feeds the input-impedance formula. Watch the line length in wavelengths, since \(\tan\beta\ell\) is what does the work. Difficulty rises down the list.
- A \(50\,\Omega\) line ends in \(Z_L=25\,\Omega\). Find \(\Gamma_L\) and \(s\).
- A \(75\,\Omega\) line ends in \(Z_L=300\,\Omega\). Find \(\Gamma_L\) and \(s\).
- What load gives \(s=1\) on a \(50\,\Omega\) line? What loads give \(s=\infty\)?
- An SWR of \(s=2.5\) is measured. Find \(|\Gamma_L|\).
- Find the input impedance of a \(50\,\Omega\) line of length \(\lambda/4\) terminated in \(200\,\Omega\).
- A \(50\,\Omega\) line with \(Z_L=50+j50\,\Omega\) is \(\lambda/8\) long. Find \(\Gamma_L\) and \(Z_{\text{in}}\).
- Design a quarter-wave transformer to match a \(200\,\Omega\) load to a \(75\,\Omega\) line.
- A short-circuited \(50\,\Omega\) stub must present \(+j75\,\Omega\) at \(2\,\text{GHz}\). Find its length in wavelengths.
- Show that an open-circuited \(\lambda/4\) line looks like a short circuit at its input.
- A line reads \(Z_{\text{sc}}=j40\,\Omega\) and \(Z_{\text{oc}}=-j90\,\Omega\). Find \(Z_0\).
- At a voltage minimum on a \(50\,\Omega\) line, the impedance is \(20\,\Omega\). Find \(s\) and \(|\Gamma_L|\).
- Explain why the quarter-wave transformer is narrowband, in terms of how \(\beta\ell\) drifts from \(\pi/2\) as frequency changes.