Phase-Controlled DC Drives — Lecture 4

Three-Phase Phase-Controlled DC Drives

Lecture 4: Three-Phase Semiconverter, Full-Converter & Dual-Converter Drives

Instructor: Prof. Mithun Mondal Institute: BITS Pilani, Hyderabad Campus Semester: Second Semester, 2025–2026

Introduction to Three-Phase Drives

Why Three-Phase Drives?

Three-phase phase-controlled drives offer significant advantages over their single-phase counterparts, making them the industry standard for medium- to high-power DC motor applications. The key advantages are:

  1. Higher Power Ratings: Suitable for $100\;\text{kW}$ to $1500\;\text{kW}$ and beyond.
  2. Higher Ripple Frequency:
    • Single-phase full-bridge: ripple at $2f$ (e.g. $120\;\text{Hz}$ for a $60\;\text{Hz}$ supply).
    • Three-phase full-bridge (6-pulse): ripple at $6f$ (e.g. $360\;\text{Hz}$ for a $60\;\text{Hz}$ supply).
  3. Lower Filtering Requirements: Smaller smoothing inductor required for the same current-ripple specification.
  4. Better Motor Performance: More continuous armature current leads to smoother torque.
  5. Lower Torque Pulsation: Smoother shaft torque reduces mechanical stress.
  6. Higher Efficiency: Better utilisation of transformer and supply capacity.

Power Ranges for Different DC Drive Topologies

Table 1: Power ranges for different DC-drive topologies
Drive TypeTypical Power RangeApplications
Single-Phase Full-BridgeUp to $100\;\text{kW}$Small drives
Three-Phase SemiconverterUp to $115\;\text{kW}$Medium drives
Three-Phase Full-ConverterUp to $1500\;\text{kW}$Large drives
Three-Phase Dual-ConverterUp to $1500\;\text{kW}$High-performance drives
12-Pulse (Series/Parallel)Above $1\;\text{MW}$Very large drives

Industrial Standard

Three-phase phase-controlled drives are the industry standard for medium- to high-power DC-motor applications.

Classification of Three-Phase Drives

Based on converter configuration, three-phase drives are classified as follows:

  1. Three-Phase Half-Wave (3-pulse) Converter: Requires a neutral connection; rarely used industrially.
  2. Three-Phase Semiconverter (half-controlled bridge): One-quadrant operation (forward motoring only); up to $115\;\text{kW}$.
  3. Three-Phase Full-Converter (fully-controlled bridge): Two-quadrant operation (motoring + regenerative braking); up to $1500\;\text{kW}$.
  4. Three-Phase Dual-Converter: Four-quadrant operation; up to $1500\;\text{kW}$.

Three-Phase Supply — Notation

The standard three-phase system with phase sequence $a$-$b$-$c$ is described by the phase voltages of a Y-connected supply:

$$v_a = V_m \sin\omega t$$ $$v_b = V_m \sin\!\bigl(\omega t - 120°\bigr)$$ $$v_c = V_m \sin\!\bigl(\omega t - 240°\bigr)$$

where $V_m = \sqrt{2}\,V_p$ is the peak phase voltage and $V_{Lm} = \sqrt{2}\,V_L = \sqrt{3}\,V_m$ is the peak line-to-line voltage. The fundamental relation is $V_L = \sqrt{3}\,V_p$.

Three-phase supply phasor diagram showing phase voltages Va, Vb, Vc
Figure 1: Three-phase supply phasor diagram

Ripple Frequency Comparison

Output-voltage ripple comparison: single-phase 2-pulse vs three-phase 6-pulse converter
Figure 2: Output-voltage ripple — single-phase vs. three-phase

Key Observation:

  • Single-phase bridge (2-pulse): ripple period $= T/2$, ripple frequency $= 2f$
  • Three-phase bridge (6-pulse): ripple period $= T/6$, ripple frequency $= 6f$

Consequence

A six times higher ripple frequency means the peak-to-peak voltage ripple is much smaller, so a smaller smoothing inductor $L_a$ is needed for the same current-ripple specification.

Three-Phase Semiconverter Drives

The three-phase semiconverter (half-controlled bridge) is a one-quadrant drive suitable for forward motoring only. It is used for power ranges up to $115\;\text{kW}$ and is less expensive than a full-converter due to a lower device count.

The circuit consists of:

  • 3 thyristors forming the positive (controlled) group
  • 3 diodes forming the negative (uncontrolled) group
  • 1 freewheeling diode $D_F$

The output voltage is always $\geq 0$, which means regenerative braking is not possible.

Field Supply

Typically a single-phase semiconverter or full-converter is used for the field circuit.

Limitation

Cannot perform regenerative braking or electronic speed reversal.

Circuit Diagram

Three-phase semiconverter (half-controlled bridge) drive circuit showing thyristors T1,T3,T5, diodes D4,D6,D2, freewheeling diode DF and DC motor armature
Figure 3: Three-phase semiconverter (half-controlled bridge) drive circuit

Operating Principle

Positive Group — Thyristors $T_1, T_3, T_5$:

  • Each thyristor is fired with a common delay angle $\alpha$ after its respective phase voltage becomes the most positive.
  • Provides the high-potential rail of the output.

Negative Group — Diodes $D_4, D_6, D_2$:

  • Diodes conduct naturally (no delay) on the most negative phase.
  • Provides the low-potential rail.

Freewheeling Diode $D_F$:

  • Conducts whenever the instantaneous converter output would go negative.
  • Clamps $v_o \geq 0$ and maintains continuous armature current.
  • Reduces current ripple and protects the motor from negative voltage transients.

Voltage and Current Waveforms

Output voltage and armature current waveforms for three-phase semiconverter with freewheeling diode
Figure 4: Output voltage and armature current waveforms (semiconverter with freewheeling)

Average Output Voltage

The average armature voltage for a three-phase semiconverter is given by:

Key Equation — Semiconverter

$$V_a = \frac{3\sqrt{3}\,V_m}{2\pi}\bigl(1 + \cos\alpha\bigr), \qquad 0 \leq \alpha \leq \pi$$

where $V_m = \sqrt{2}\,V_p$ is the peak phase voltage. An equivalent expression in terms of the line voltage $V_L$ is:

$$V_a = \frac{3\sqrt{2}\,V_L}{2\pi}\bigl(1 + \cos\alpha\bigr) = \frac{3\,V_{Lm}}{2\pi}\bigl(1 + \cos\alpha\bigr)$$

since $\sqrt{3}\,V_m = V_{Lm} = \sqrt{2}\,V_L$.

Voltage Range

  • $\alpha = 0°$: $\quad V_a = \dfrac{3\sqrt{3}\,V_m}{\pi}$ (maximum; equals the full-converter $V_{a,\max}$)
  • $\alpha = 180°$: $\quad V_a = 0$ (minimum)

Advantages and Disadvantages

Advantages:

  • Simpler gate-drive logic than full-converter
  • Lower device count and cost
  • Freewheeling diode reduces current ripple
  • Good for constant-speed or unidirectional loads
  • Suitable for medium power levels

Disadvantages:

  • One-quadrant operation only
  • No regenerative braking
  • Speed reversal requires mechanical contactors
  • Less flexible than a full-converter

Typical Applications

Pumps, fans, conveyors, and other unidirectional loads up to $115\;\text{kW}$ that do not require regeneration.

Three-Phase Full-Converter Drives

The three-phase full-converter (fully-controlled bridge) is the most widely used three-phase DC-drive topology in industry. It provides two-quadrant operation — forward motoring and forward regenerative braking — and handles power up to $1500\;\text{kW}$.

The circuit consists entirely of six thyristors (three in the positive group, three in the negative group) with no diodes in the main power path, allowing bidirectional voltage control.

Quadrant Capability

  • Without field reversal: Quadrants I and II (forward motoring + forward regeneration)
  • With field reversal: access to all four quadrants

Circuit Diagram

Three-phase fully-controlled bridge converter drive circuit with six thyristors T1 through T6 and DC motor
Figure 5: Three-phase fully-controlled bridge converter drive circuit

Thyristor Firing and Conduction

The bridge structure consists of:

  • Positive group: $T_1$ (phase $a$), $T_3$ (phase $b$), $T_5$ (phase $c$)
  • Negative group: $T_4$ (phase $a$), $T_6$ (phase $b$), $T_2$ (phase $c$)

The firing sequence is $T_1$–$T_2$–$T_3$–$T_4$–$T_5$–$T_6$, with each thyristor separated by $60°$ and conducting for $120°$.

Table 2: Conducting pairs in temporal order
PairPhase (+)Phase (−)Output Voltage
$T_1$–$T_6$$a$$b$$v_{ab}$
$T_1$–$T_2$$a$$c$$v_{ac}$
$T_3$–$T_2$$b$$c$$v_{bc}$
$T_3$–$T_4$$b$$a$$v_{ba}$
$T_5$–$T_4$$c$$a$$v_{ca}$
$T_5$–$T_6$$c$$b$$v_{cb}$

Output Voltage Waveforms

Full-converter output voltage waveform in rectification mode, alpha less than 90 degrees, Quadrant I
Figure 6: Rectification mode ($\alpha < 90°$, Quadrant I)
Full-converter output voltage waveform in inversion mode, alpha greater than 90 degrees, Quadrant II
Figure 7: Inversion mode ($\alpha > 90°$, Quadrant II)

Average Output Voltage

Key Equation — Full-Converter

$$V_a = \frac{3\sqrt{3}\,V_m}{\pi}\,\cos\alpha = \frac{3\,V_{Lm}}{\pi}\,\cos\alpha, \qquad 0 \leq \alpha \leq 180°$$

In terms of the RMS line voltage $V_L$:

$$V_a = \frac{3\sqrt{2}\,V_L}{\pi}\,\cos\alpha = 1.35\,V_L\,\cos\alpha$$

Voltage Polarity vs. Delay Angle

  • $0° \leq \alpha < 90°$: $\;V_a > 0$ ⟹ Rectification (motoring mode)
  • $\alpha = 90°$: $\;V_a = 0$
  • $90° < \alpha \leq 180°$: $\;V_a < 0$ ⟹ Inversion (regeneration mode)

Two-Quadrant Operation

Quadrant I — Forward Motoring:

  • $\alpha < 90° \Rightarrow V_a > 0$, $\;I_a > 0$
  • $V_a > E_b$ (back-EMF)
  • Power flow: Supply → Motor

Quadrant II — Forward Regenerative Braking:

  • $\alpha > 90° \Rightarrow V_a < 0$, $\;I_a > 0$
  • Motor still rotates forward ($E_b > 0$)
  • $E_b > |V_a|$ drives current in the same direction
  • Power flow: Motor → Supply

Important Note

Thyristors carry current in one direction only; it is the voltage $V_a$ that reverses, not $I_a$.
Two-quadrant operation diagram showing Quadrant I motoring and Quadrant II regeneration
Figure 8: Two-quadrant operation of the full-converter drive

Regenerative Braking

Physical Mechanism:

  • Motor is running forward; the load (or flywheel) has stored kinetic energy.
  • Delay angle is increased beyond $90°$: converter output voltage $V_a$ becomes negative.
  • Back-EMF $E_b$ (still positive) now exceeds $|V_a|$.
  • Armature current $I_a$ continues to flow in the same (positive) direction.
  • Instantaneous power $P = V_a \cdot I_a < 0$: energy flows from motor back to the AC supply.
  • Motor decelerates — kinetic energy is returned to the grid.

Circuit Equation During Regeneration

$$E_b - v_a(t) = i_a(t)\,R_a + L_a\,\frac{di_a}{dt}$$

where $v_a < 0$ and $E_b > 0$. The motor acts as a generator feeding power back through the converter (operating as an inverter) to the AC supply.

Requirement

The AC supply must be receptive (able to absorb power) for regeneration to succeed.

Step-by-Step Transition from Motoring to Regeneration:

  1. Motor running in forward motoring mode: $\alpha < 90°$
  2. Controller gradually increases $\alpha$ toward $90°$
  3. At $\alpha = 90°$: $V_a = 0$; motor runs on stored energy
  4. $\alpha$ is further increased beyond $90°$: $V_a$ becomes negative
  5. Back-EMF $E_b$ (still positive) drives $I_a$ in the original direction
  6. Power reverses — motor begins to decelerate; energy returns to supply

Smooth Transition

Because $I_a$ never drops to zero during the changeover, the transition from motoring to regenerative braking is smooth and continuous — a major advantage of the full-converter topology.

Input Power Factor

For perfectly smooth (continuous) armature current $I_a$, each supply line carries $+I_a$ for $120°$ and $-I_a$ for $120°$ per cycle, giving an RMS line current of:

$$I_s = \sqrt{\frac{2}{3}}\;I_a$$

The input displacement power factor is then:

Input Power Factor

$$PF = \frac{P_{\text{dc}}}{\sqrt{3}\,V_L\,I_s} = \frac{3}{\pi}\,\cos\alpha = 0.955\,\cos\alpha$$
Table 3: Power factor at selected firing angles
$\alpha$$\cos\alpha$Power Factor ($PF$)
$0°$$1.00$$0.955$
$30°$$0.866$$0.827$
$60°$$0.50$$0.478$
$90°$$0.00$$0.000$
$>90°$$< 0$Regenerative mode

Field Circuit

The field circuit of a DC motor has a large time constant $\tau_f = L_f / R_f$. Using a full-converter for the field supply enables the following:

  • A full-converter can apply negative voltage across the field winding, actively forcing the field current down faster.
  • This reduces the time required for field reversal (important for four-quadrant drives) and for field weakening at high speed.

The field voltage supplied by a three-phase full-converter is:

$$V_f = \frac{3\sqrt{3}\,V_{mf}}{\pi}\,\cos\alpha_f$$

Practical Choice

A single-phase full-converter is often sufficient for the field because the field power is typically only $1$–$5\%$ of the armature power.

Speed Control Regions

Region 1 — Below Base Speed ($0$ to $N_{\text{base}}$):

  • Field current held at rated value $I_{f,\text{rated}}$.
  • Speed is varied by changing $\alpha_a$ — armature voltage control.
  • Torque capability: constant (rated torque).

Region 2 — Above Base Speed ($N > N_{\text{base}}$):

  • Armature voltage at maximum ($\alpha_a = 0°$).
  • Speed is increased by reducing field current — field weakening.
  • Torque capability: inversely proportional to speed (constant power operation).
Speed-torque-power characteristics showing constant torque below base speed and field weakening above base speed
Figure 9: Speed control regions — constant torque and field weakening

Typical Applications

The full-converter drive is used in industrial applications that require two-quadrant control:

  • Rolling mills
  • Paper machines
  • Textile machinery
  • Cranes and hoists
  • Elevators and lifts
  • Machine tools (lathes, milling machines)
  • Mining equipment
  • Printing presses
  • Extruders
  • Winding and unwinding drives

Why Full-Converter?

These applications demand precise speed control, regenerative braking for energy recovery (especially cranes and hoists), and the ability to handle high power levels efficiently.

Three-Phase Dual-Converter Drives

The three-phase dual-converter provides complete four-quadrant operation by connecting two three-phase full-converters in anti-parallel (back-to-back). This eliminates the need for mechanical contactors when reversing the motor direction, enabling fast, smooth, electronic reversal.

Converter Roles

  • Converter P (positive): supplies positive armature voltage — operates in Quadrants I and II.
  • Converter N (negative): supplies negative armature voltage — operates in Quadrants III and IV.

Cost and Complexity

The dual-converter is the most expensive and complex single-stage phase-controlled drive, requiring 12 thyristors in the armature circuit. It is justified only when frequent, fast reversals are required.

Circuit Diagram

Three-phase dual-converter drive circuit showing two anti-parallel full-converters connected to DC motor armature
Figure 10: Three-phase dual-converter drive circuit (anti-parallel full-converters)

Operating Principle

  • Converter P active ⟹ Quadrants I and II
    • Forward motoring (Q-I): $\;\alpha_P < 90° \Rightarrow V_a > 0$
    • Forward regeneration (Q-II): $\;\alpha_P > 90° \Rightarrow V_a < 0$
  • Converter N active ⟹ Quadrants III and IV
    • Reverse motoring (Q-III): $\;\alpha_N < 90° \Rightarrow V_a < 0$
    • Reverse regeneration (Q-IV): $\;\alpha_N > 90° \Rightarrow V_a > 0$

Two Operating Modes

  • Non-circulating current mode — preferred in practice; only one converter conducts at a time.
  • Circulating current mode — both converters enabled simultaneously; requires an inter-group reactor.

Voltage Equations and Constraint

The average output voltage of each converter is:

$$V_P = \frac{3\sqrt{3}\,V_m}{\pi}\,\cos\alpha_P \qquad V_N = \frac{3\sqrt{3}\,V_m}{\pi}\,\cos\alpha_N$$

For simultaneous operation without short-circuit, the following constraint must be maintained:

Anti-Parallel Constraint

$$\alpha_P + \alpha_N = 180° \quad\Longrightarrow\quad \cos\alpha_N = -\cos\alpha_P$$

This ensures $V_N = -V_P$, so the motor terminal voltage (which is $-V_N$ for Converter N) equals $V_P$. Both converters therefore agree on the motor terminal voltage in the average sense, while only one carries the load current at any time.

Result

Only one converter carries the load current at any time; the constraint prevents a short-circuit between the two converters.

Four-Quadrant Summary

Table 4: Four-quadrant operation of the dual-converter drive
QuadrantOperationActive ConverterDelay AngleSign of $V_a,\; I_a$
IForward MotoringP$\alpha_P < 90°$$V_a > 0,\; I_a > 0$
IIForward RegenerationP$\alpha_P > 90°$$V_a < 0,\; I_a > 0$
IIIReverse MotoringN$\alpha_N < 90°$$V_a < 0,\; I_a < 0$
IVReverse RegenerationN$\alpha_N > 90°$$V_a > 0,\; I_a < 0$

Convention

$V_a$ is the voltage across the motor terminals (positive in the forward-motoring direction); $I_a$ is positive in the forward direction.

Non-Circulating Current Mode

This is the preferred operating mode in modern drives:

  • Only one converter conducts at a time; the other is fully blocked (all gate pulses removed).
  • A dead time (typically $2$–$10\;\text{ms}$) is inserted between switching to allow the outgoing converter's current to fall to zero.
  • No inter-group reactor is needed.

Switching Sequence (Converter P → Converter N):

  1. Ramp $\alpha_P$ to reduce $I_a$ smoothly toward zero.
  2. Wait for dead time; detect zero current.
  3. Block all gate pulses to Converter P.
  4. Enable gate pulses to Converter N with appropriate $\alpha_N$.

Advantages

No circulating-current losses; simpler reactor-free circuit; most commonly used mode in industry.

Circulating Current Mode

In this mode, both converters are enabled simultaneously at all times with the constraint $\alpha_P + \alpha_N = 180°$ maintained. An inter-group reactor $L_r$ is connected between the two converter outputs to limit the circulating current.

Because $v_P + v_N \neq 0$ at every instant (only the averages cancel), a time-varying voltage appears across $L_r$, driving a circulating current:

$$i_{\text{circ}}(t) = \frac{1}{2L_r}\int\!\bigl[v_P(t) + v_N(t)\bigr]\,dt$$

Disadvantages

Continuous power loss in $L_r$; reactor is bulky and expensive; more complex control circuitry. Seldom used in modern drives.

Field Circuit for Dual-Converter Drives

A single-phase or three-phase full-converter is recommended for the field supply:

  • Provides two-quadrant field control (positive and negative $V_f$).
  • Enables fast field reversal — essential for four-quadrant reversing drives.
  • A single-phase full-converter is usually adequate (field power ≪ armature power).

Do Not Use a Semiconverter for the Field

A semiconverter cannot reverse $V_f$; field reversal would then rely on the slow natural decay of $I_f$ through $R_f$, making the overall drive sluggish.

Advantages and Disadvantages

Advantages:

  • Full four-quadrant operation
  • Fast, smooth, electronic reversal — no contactors
  • Regenerative braking in both directions
  • High-performance dynamic response

Disadvantages:

  • Highest device count: 12 thyristors (armature circuit)
  • Most expensive and complex control
  • Dead-time delay in non-circulating mode
  • Higher harmonic injection into the supply

Typical Applications

Reversing rolling mills, mine hoists, machine-tool drives, and any process requiring frequent, rapid direction changes.

Comparison and Selection

Single-Phase vs. Three-Phase DC Drives

Table 5: Single-phase vs. three-phase DC drive comparison
FeatureSingle-PhaseThree-Phase
Typical Power RangeUp to $100\;\text{kW}$$100\;\text{kW}$ – $1500\;\text{kW}$
Ripple Frequency$2f$$6f$
Smoothing InductorLargerSmaller
Motor PerformanceGoodExcellent
Torque PulsationHigherLower
EfficiencyGoodBetter
Cost per kWHigherLower
Armature CurrentMore ripple; possibly discontinuousSmoother; more continuous

Comparison of Three-Phase Converter Types

Table 6: Comparison of three-phase DC drive topologies
FeatureSemiconverterFull-ConverterDual-Converter
Quadrants124
Thyristors (armature)3612
Diodes (armature)3 + FWD00
RegenerationNoYes (1 direction)Yes (both directions)
Reversal MethodMechanicalWith field reversalElectronic
Power RangeUp to $115\;\text{kW}$Up to $1500\;\text{kW}$Up to $1500\;\text{kW}$
$V_{a,\max}$$\dfrac{3\,V_{Lm}}{\pi}$ — identical for all three topologies
CostLowMediumHigh
ComplexityLowMediumHigh

Drive Selection Guide

Choose Semiconverter if:

  • Unidirectional load only
  • No regeneration needed
  • Cost must be minimised
  • Power $\leq 115\;\text{kW}$

Choose Full-Converter if:

  • Regenerative braking is needed
  • Medium to high power requirement
  • Best cost-performance trade-off is required
  • Most common industrial choice

Choose Dual-Converter if:

  • Frequent, fast reversals are required
  • Four-quadrant operation is essential
  • High dynamic performance is critical
  • Cost can be justified by the application

General Rule

Start with the simplest topology that meets the application requirements — upgrade only if performance demands it.

Summary

Key Equations at a Glance

Table 7: Average output voltage for three-phase converters
ConverterAverage Output VoltageIn terms of $V_L$
Semiconverter $\dfrac{3\sqrt{3}\,V_m}{2\pi}(1+\cos\alpha)$ $\dfrac{3\sqrt{2}\,V_L}{2\pi}(1+\cos\alpha)$
Full-Converter $\dfrac{3\sqrt{3}\,V_m}{\pi}\cos\alpha$ $1.35\,V_L\cos\alpha$

Notation and Input Power Factor

$V_m = \sqrt{2}\,V_p$ (peak phase voltage), $\quad V_{Lm} = \sqrt{2}\,V_L = \sqrt{3}\,V_m$ (peak line voltage), $\quad \alpha$ = firing-delay angle.

Full-converter input power factor (continuous armature current):

$$\text{PF} = \frac{3}{\pi}\cos\alpha = 0.955\,\cos\alpha$$

Summary Points

  1. Three-phase converters offer higher power capacity, lower ripple ($6f$), and better efficiency than single-phase counterparts, making them the industry standard for medium- to high-power DC drives.
  2. Semiconverter: One-quadrant operation ($V_a \geq 0$ always); uses a freewheeling diode; suitable for simple unidirectional loads with no regeneration requirement.
  3. Full-converter: Two-quadrant operation (motoring + regenerative braking); the workhorse of industrial DC drives; $V_a$ can be positive or negative by varying $\alpha$ from $0°$ to $180°$.
  4. Dual-converter: Four-quadrant operation by anti-parallel connection of two full-converters; enables fast electronic reversal; non-circulating current mode is preferred.
  5. Speed control: Below base speed uses armature voltage control (constant torque region); above base speed uses field weakening (constant power region).
  6. Field converter: Should be a full-converter (or better) for any drive that requires fast field reversal or field weakening above base speed.