Bridge Rectifier:
Lower peak diode voltage.
Suitable for high-voltage applications.
Center-Tapped Transformer Rectifier:
Provides electrical isolation.
Only one diode voltage drop between source and load.
Desirable for low-voltage, high-current applications.
Full-Wave Bridge Rectifier:
Diode Conducting Pairs:
D1 & D2 conduct together.
D3 & D4 conduct together.
Kirchhoff’s Voltage Law (KVL):
D1 & D3 cannot be on simultaneously.
D2 & D4 cannot conduct simultaneously.
Load Current:
Positive or zero.
Never negative.
Load Voltage:
+\(v_s\) when D1 & D2 are on.
+\(v_s\) when D3 & D4 are on.
Reverse-Biased Diode Voltage:
Maximum is the peak value of the source.
With D1 on, the voltage across D3 is -\(v_s\).
Source Current:
Current entering the bridge: \(i_{D1} - i_{D4}\).
Symmetric about zero.
Average source current: zero.
RMS source current = RMS load current.
Source current = load current for half the period.
Source current = -load current for the other half.
Squares of load and source currents are equal, so RMS currents are equal.
Output Voltage Frequency:
Fundamental frequency: \(2\omega\) (twice the AC input frequency).
Output Voltage Fourier Series:
Consists of a DC term and even harmonics of the source frequency.
The Center-Tapped Transformer Rectifier
Kirchhoff’s Voltage Law (KVL):
Only one diode can conduct at a time.
Load Current:
Positive or zero.
Never negative.
Output Voltage:
+\(v_{s1}\) when D1 conducts.
-\(v_{s2}\) when D2 conducts.
Transformer Secondary Voltages:
Related to the source voltage by \(v_{s1} = v_{s2} = v_s \left(\frac{N_2}{2N_1}\right)\).
Reverse-Biased Diode Voltage:
Maximum is twice the peak value of the load voltage.
Shown by KVL around the transformer secondary windings, D1, and D2.
Source Current:
Current in each half of the transformer secondary is reflected to the primary.
Average source current: zero.
Transformer Function:
Provides electrical isolation between the source and the load.
Output Voltage Frequency:
Fundamental frequency: \(2\omega\) (twice the AC input frequency).
Resistive Load
Power absorbed by the load resistor \(= I_{\mathrm{rms}}^2 \cdot R\), where \(I_{\mathrm{rms}} = \dfrac{I_m}{\sqrt{2}}\)
Power factor \(= 1\)
RL-Load
Load Current (\(i_o\)):
Reaches a periodic steady-state condition after a start-up transient.
Full-Wave Rectified Sinusoidal Voltage Across the Load:
Can be expressed as a Fourier series.
Consists of a DC term and the even harmonics.
Current in the RL Load:
Computed using superposition.
Each frequency is considered separately and results are combined.
DC Current and Current Amplitude:
Harmonic (\(n\)) Effects:
\(n~\uparrow~\Rightarrow~V_n~\downarrow\).
For an RL load, as \(n~\uparrow ~\Rightarrow ~Z_n~\uparrow\).
Combination of \(V_n~\downarrow ~ + ~Z_n~\uparrow~\Rightarrow ~I_n~\downarrow\) rapidly with \(n~\uparrow\).
Significance in RL Load:
DC term and only a few AC terms are usually necessary to describe the current in an RL load.
RLE-Load
Applications:
DC motor drive circuit.
Battery charger.
Modes of Operation:
Continuous-current mode.
Discontinuous-current mode.
Continuous-Current Mode:
Load current is always positive for steady-state operation.
One pair of diodes is always conducting.
Voltage across the load is a full-wave rectified sine wave.
Only modification to the RL load analysis is in the DC term of the Fourier series.
Discontinuous-Current Mode:
Load current returns to zero during every period.
Capacitance Output Filter
Produces an output voltage that is essentially DC.
Analysis similar to that of the half-wave rectifier with a capacitance filter.
Capacitor discharge time is smaller than in the half-wave circuit due to the rectified sine wave in the second half of each period.
Output voltage ripple for the full-wave rectifier is approximately half that of the half-wave rectifier.
Peak output voltage is less in the full-wave circuit due to two diode voltage drops rather than one.
Output voltage is a positive sine function when one of the diode pairs is conducting.
Output voltage is a decaying exponential otherwise.
The diodes become reverse biased at \(\theta\)
The maximum output voltage (\(V_m\)) , and the minimum output voltage is determined by evaluating \(\nu_o\) at the angle at which the second pair of diodes turns on, which is at \(\omega t = \pi + \alpha\). At that boundary point
\(\alpha\) is larger for the full-wave rectifier and the ripple is smaller for a given load
The peak-to-peak ripple
Note that the approximate peak-to-peak ripple voltage for the full-wave rectifier is one-half that of the half-wave rectifier