Three Phase Fully Controlled Converter


Demonstrative Video



Introduction to the Experiment

This experiment is aimed at converting AC (Three phase) to DC using a fully controlled converter. The circuit is implemented in simulation as well as hardware and the performance is studied.

Learning Outcomes:

Circuit Diagram:

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Theory:

The three-phase bridge rectifier circuit has three legs, each phase connected to one of the three phase voltages. Alternatively, it can be seen that the bridge circuit has two halves, the positive half consisting of the SCRs S1, S3, and S5 and the negative half consisting of the SCRs S2, S4, and S6. At any time when there is current flow, one SCR from each half conducts. If the phase sequence of the source be RYB, the SCRs are triggered in the sequence S1, S2, S3, S4, S5, S6, and S1 and so on.

The operation of the circuit is first explained with the assumption that diodes are used in place of the SCRs. The three-phase voltages vary as shown below. Let the three-phase voltages be defined as shown below.

It can be seen that the R-phase voltage is the highest of the three-phase voltages when q is in the range from 30° to 150°. It can also be seen that Y-phase voltage is the highest of the three-phase voltages when q is in the range from 150° to 270° and that B-phase voltage is the highest of the three-phase voltages when q is in the range from 270° to 390° or 30° in the next cycle. We also find that R-phase voltage is the lowest of the three-phase voltages when q is in the range from 210° to 330°. It can also be seen that Y-phase voltage is the lowest of the three-phase voltages when q is in the range from 330° to 450° or 90° in the next cycle, and that B-phase voltage is the lowest when q is in the range from 90° to 210°. If diodes are used, diode D1 in place of S1 would conduct from 30° to 150°, diode D3 would conduct from 150° to 270°, and diode D5 from 270° to 390° or 30° in the next cycle. In the same way, diode D4 would conduct from 210° to 330°, diode D6 from 330° to 450° or 90° in the next cycle, and diode D2 would conduct from 90° to 210°. The positive rail of output voltage of the bridge is connected to the topmost segments of the envelope of three-phase voltages and the negative rail of the output voltage to the lowest segments of the envelope.

Simulation of Full Wave Three Phase Fully Controlled Converter in MATLAB Simulink

Aim:

To simulate the converter in MATLAB Simulink

Problem 1:

Implement the 3-phase fully controlled full wave converter with an R load of 100 Ω. (Input voltage: Phase-to-phase rms voltage (V) = 61.2 V, 50Hz)

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Hardware Implementation of 3-Phase (R Load)

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Procedure:

  1. Connect the circuit as shown in Fig. 3 (with R load (R=100 ohms), Connect CRO probes across the R load to measure the output voltage.
  2. Switch ON the MCB of 3Ø supply on the Left hand side of your Experimental Table.
  3. Switch ON the MCB on the POWER MODULE kit.
  4. Switch ON the MCB on the SCR-Diode Power module and slowly increase the Voltage to reach up to 61.2 V in RMS using + symbol Push Button in the Power Module kit.
  5. Note: The Voltage Adjustment Controls are a pair of push buttons to finely adjust the voltage to required value.
  6. Switch on the driver power switch.
  7. Connect DSO probes across the R Load to measure the output voltage.
  8. Vary the firing angle as mentioned and note down the results.
  9. Observe the Output voltage waveforms in the DSO.

Conclusion:

Obtain the results following:

I) R-Load

  1. Attach the circuit diagram for a three phase controlled bridge rectifier with R load (\(100~\Omega\)).
  2. Attach the circuit diagram for the gate triggering sub-circuit.
  3. Attach the waveforms of a) Output Voltage b) Output Current c) Input voltages d) Input Currents and (for triggering angle \(45^{\circ}\))
  4. Attach the waveforms of a) Output Voltage (for \(45^{\circ}\), experimentally from the DSO)
  5. Calculate Performance parameters (Simulink)
  6. S. no

    Firing angle

    (measured in time )

    Firing angle

    (measured in time converted into angle )

    Ave rage Output voltage

    Ave rage Output

    current

    1

    0 ms

    00

    2

    2.5ms

    (2.5/10*1800)=450

    3

    5 ms

    900

  7. Calculate Performance parameters (Experimental)
  8. S. no

    Firing angle

    (measured in time )

    Firing angle

    (measured in time converted into angle )

    Ave rage Output voltage

    1

    0 ms

    00

    2

    2.5ms

    (2.5/10*1800)=450

    3

    5 ms

    900