Breakdown in Solid Dielectrics
A gas heals; a liquid mostly heals; a solid does neither. When solid insulation fails, the puncture is permanent — a carbonised channel that never closes — so the whole engineering of solid dielectrics is about never reaching breakdown over a service life of decades. That makes time the hidden variable: a solid that shrugs off a microsecond impulse may be killed by the same field held for twenty years. This chapter is the hierarchy of mechanisms behind that fact.
- Why solid failure is irreversible, and why the measured strength falls the longer the stress is applied — the time-scale hierarchy.
- Intrinsic breakdown: the electronic ceiling, the highest strength a flawless solid could reach.
- Electromechanical breakdown: Maxwell stress \(\tfrac12\varepsilon_0\varepsilon_r E^2\) crushing the solid, and the Stark–Garton collapse at \(d/d_0 = 0.6\).
- Thermal breakdown: dielectric loss \(\propto f\,\varepsilon_r\tan\delta\,E^2\) heating the solid into runaway.
- Partial discharge in cavities — the enhanced void field that erodes a solid from the inside, and links straight to Chapter 8's bubble.
- Treeing, electrochemical ageing, and surface tracking — the slow killers of cables and outdoor insulators.
The Permanence of Solid Failure
The crucial difference between a solid and the fluids of the last two chapters is that a solid cannot flow back together. A gas re-mixes, a liquid closes over a discharge channel and recovers most of its strength, but a punctured solid carries a permanent carbonised track that short-circuits it forever. A single breakdown is the end of the component's life. The design goal is therefore not "survive one breakdown" but "never break down at all", across thirty or forty years of continuous stress.
That long horizon exposes the central subtlety: a solid does not have one breakdown strength, it has many, depending on how long the voltage is applied. Under a microsecond impulse the only mechanism fast enough to act is the electronic intrinsic one, and the strength is at its highest. Stretch the time to milliseconds and electromechanical and thermal processes get their chance; stretch it to hours and years and slow discharge, treeing and ageing processes dominate, and the strength falls dramatically. Plotting strength against time-to-breakdown gives a descending staircase — the single most important picture in the chapter.
Intrinsic Breakdown
Intrinsic breakdown is the purely electronic limit, reached only in a flawless sample, at low temperature, under a fast-rising voltage that gives no slower mechanism time to intervene. A few conduction electrons, present even in a good insulator, are accelerated by the field; if they gain energy from the field faster than they lose it to the lattice, their energy climbs until they ionize the lattice by collision, and an avalanche multiplies through the solid in nanoseconds — the same runaway condition we have now met in gases and liquids.
Because the process is electronic and the lattice is dense, intrinsic strengths are enormous — of the order of \(10^{6}\text{–}10^{7}~\mathrm{V/cm}\) (hundreds of \(\mathrm{kV/mm}\) to a few \(\mathrm{MV/mm}\)) — and they represent the ceiling a perfect solid could reach. No practical insulation gets near it: a real component always carries a flaw that one of the slower mechanisms exploits at a far lower field. Intrinsic strength is thus a benchmark, not a service value, and the rest of the chapter is about why service values are so much lower.
Electromechanical Breakdown
A charged capacitor's plates attract one another, and when the dielectric between them is a soft solid, that attraction physically squeezes it. The compressive electrostatic (Maxwell) stress on a slab of permittivity \(\varepsilon_r\) under field \(E = V/d\) is:
The solid resists with its mechanical (Young's-modulus) stiffness. As the slab thins, the field \(V/d\) rises, so the squeezing stress rises faster than the restoring stress — a positive feedback. Stark and Garton showed this becomes unstable once the slab has been compressed to a definite fraction of its original thickness:
Here \(Y\) is Young's modulus. The mechanism matters most for soft polymers and at higher temperature, where \(Y\) falls; a stiffer or cooler material resists longer. It is one of the medium-speed rungs on the staircase — slower than intrinsic, faster than thermal.
Thermal Breakdown
No real dielectric is perfectly lossless; under AC each cycle dissipates a little energy as heat, set by the loss tangent \(\tan\delta\). The power generated per unit volume is:
This heat must be conducted away to the surfaces. The danger is that the loss usually rises with temperature (conductivity and \(\tan\delta\) climb), while the cooling — proportional to the temperature difference — rises only linearly. If at some point the heat generated grows faster with temperature than the heat removed, equilibrium is lost: the temperature, and with it the loss, runs away until the material melts or chars. That is thermal runaway.
Three consequences follow for design. Thermal strength falls as frequency and \(\tan\delta\) rise, so AC and high-frequency stress are far more punishing than DC. It falls as the insulation gets thicker, because the heat at the centre has farther to travel out — making thermal breakdown the limiting mechanism for bulky insulation like large bushings and thick cables. And it is the reason a low loss tangent is prized: every reduction in \(\tan\delta\) buys margin against runaway.
Partial Discharge in Cavities
The mechanism that kills most solid insulation in service is none of the above acting on the bulk, but a slow erosion that begins in a tiny gas-filled cavity — a void left by imperfect manufacture, a delamination, a gas pocket. The cavity is the solid's version of Chapter 8's bubble, and it is dangerous for exactly the same two reasons: the field inside it is enhanced, and the gas it contains is weak.
Once the cavity field reaches the gas's breakdown value, a small spark — a partial discharge (PD) — fires inside the void, again and again, on every voltage cycle. Each tiny discharge is harmless in itself, but its ions and ultraviolet bombard the cavity walls, slowly eroding and chemically degrading the surrounding polymer. Over months and years the cavity grows, the erosion concentrates the field at its tip, and a conducting channel begins to push into the solid — which is treeing, the next section. PD is therefore both a destroyer and a diagnostic: because each discharge injects a measurable charge pulse, detecting and quantifying PD is the single most powerful way to find ailing insulation before it fails, the subject of Chapter 19.
Treeing and Electrochemical Ageing
An electrical tree is a branching, hollow, carbonised channel that grows through a solid under prolonged stress, almost always starting from a PD site, a sharp contaminant, or a field-concentrating defect. Each branch advances by partial discharges at its tip, which erode fresh polymer and extend the channel a little further; under a microscope the result looks startlingly like a bush or a lightning bolt frozen in the plastic. Once a tree bridges the insulation, breakdown follows. Trees can take years to cross thick insulation, which is precisely why they are the dominant ageing mechanism of cables and machine insulation.
A subtler relative haunts polymer cables in wet environments: the water tree. Where moisture and an electric field act together on polyethylene, diffuse, fan-shaped trees of water-filled micro-channels grow at fields far below those needed for electrical trees. Water trees do not themselves puncture the insulation, but they degrade it and seed the electrical trees that eventually do — the chief reason early XLPE cables failed and why modern cables use water-tree-retardant compounds and tight moisture control.
Tracking and Surface Flashover
Not every solid failure happens in the bulk; many occur along the surface, especially for outdoor insulators exposed to pollution and damp. A film of contamination — salt, dust, industrial deposit — wetted by dew or drizzle becomes weakly conducting, and the leakage current it carries heats the surface unevenly. Where the film dries fastest, a dry band forms; almost the whole voltage then appears across this narrow band, igniting small arcs across it. These arcs carbonise organic surfaces into a permanent conducting track, which extends with each event until a continuous path flashes the insulator over. A material's resistance to this is graded by its comparative tracking index (CTI).
Surface flashover is doubly important because the flashover voltage of a contaminated surface can be a small fraction of the bulk strength, so for outdoor apparatus the surface, not the volume, sets the rating. The defence is partly geometric — long creepage paths, sheds that shelter dry zones — and partly material: hydrophobic surfaces that bead water into isolated droplets rather than letting it form a continuous conducting film. Silicone-rubber housings, whose hydrophobicity recovers even after pollution, have become the modern answer, and assessing that hydrophobicity is itself an active diagnostic field.
Worked Examples
Problem. A soft polymer has Young's modulus \(Y = 1\times10^{8}~\mathrm{Pa}\) and \(\varepsilon_r = 2.3\). Estimate its apparent electromechanical strength, and state the thickness at which it collapses.
Solution. Use \(E_a = 0.6\sqrt{Y/(\varepsilon_0\varepsilon_r)}\) with \(\varepsilon_0 = 8.85\times10^{-12}\):
About \(1.3~\mathrm{GV/m}\) — a theoretical upper bound reached only if nothing else fails first; the slab becomes unstable once squeezed to \(d = 0.6\,d_0\) (a 40% thinning). In practice thermal or discharge mechanisms cut in well below this.
Problem. A dielectric with \(\varepsilon_r = 3\), \(\tan\delta = 0.01\) carries a \(50~\mathrm{Hz}\) field of \(10~\mathrm{MV/m}\). Find the heat generated per unit volume.
Solution. Use \(p = 2\pi f\,\varepsilon_0\varepsilon_r\tan\delta\,E^2\):
About \(8.3~\mathrm{kW/m^3}\) must be conducted to the surfaces. Double the frequency or \(\tan\delta\) and it doubles — which is why low-loss materials and DC stress are so much safer against thermal runaway.
Problem. A solid (\(\varepsilon_r = 4\)) under a bulk field of \(5~\mathrm{kV/mm}\) contains a small void. Find the field inside the void for (a) a spherical and (b) a flat disc-shaped cavity.
Solution. Apply the cavity-field formulas with \(\varepsilon_2 = 1\):
A flat void normal to the field is stressed four times the bulk — and the gas inside is far weaker — so it discharges long before the solid is anywhere near its own strength. The worst-case (disc) void is what makes voids so destructive.
Problem. For the flat void of Example 3 (\(\varepsilon_r = 4\)), the trapped gas breaks down at \(E_g = 3~\mathrm{kV/mm}\). At what bulk field does partial discharge begin?
Solution. PD starts when \(E_{\text{cav}} = \varepsilon_r E_{\text{solid}}\) reaches \(E_g\):
PD ignites at a bulk stress of only \(0.75~\mathrm{kV/mm}\) — perhaps a hundredth of the solid's own strength. A void thus starts eroding the insulation at a voltage the bulk would shrug off, which is why void-free manufacture is non-negotiable for HV solids.
Chapter Summary
Solid failure is irreversible, and strength falls the longer the stress is held — a descending staircase from intrinsic to ageing.
The electronic ceiling, \(10^6\text{–}10^7~\mathrm{V/cm}\), reached only in flawless samples under fast voltage. A benchmark, not a service value.
Maxwell stress \(\tfrac12\varepsilon_0\varepsilon_r E^2\) crushes soft solids; collapse at \(d/d_0 = 0.6\), \(E_a = 0.6\sqrt{Y/\varepsilon_0\varepsilon_r}\).
Loss \(p = 2\pi f\varepsilon_0\varepsilon_r\tan\delta E^2\) heats the bulk; runaway when generation outpaces cooling. Worse at high \(f\), \(\tan\delta\), thickness.
Voids are stressed above the bulk and discharge internally, eroding the solid. \(E_{\text{cav}}=\varepsilon_r E_{\text{solid}}\) for the worst-case disc.
PD grows electrical (and water) trees through the bulk; surface contamination tracks and flashes over. The slow killers of cables and insulators.
Problems
For each item, first name the mechanism it tests — intrinsic, electromechanical, thermal, partial discharge, treeing, or tracking — then work it through. Difficulty rises down the list.
- Explain why a solid dielectric has no single breakdown strength, and sketch how strength varies with time-to-breakdown.
- Why is intrinsic strength called a "benchmark, not a service value"? What prevents real insulation from reaching it?
- Write the Maxwell compressive stress on a slab, and explain the positive feedback that drives electromechanical collapse.
- A polymer has \(Y = 2\times10^{8}~\mathrm{Pa}\), \(\varepsilon_r = 2.5\). Estimate its apparent electromechanical strength and the collapse thickness ratio.
- Find the AC dielectric loss density for \(\varepsilon_r = 4\), \(\tan\delta = 0.02\), \(f = 60~\mathrm{Hz}\), \(E = 8~\mathrm{MV/m}\).
- Explain why thermal breakdown is more severe for thick insulation, high frequency, and a large loss tangent.
- A spherical void sits in a solid (\(\varepsilon_r = 3\)) under a bulk field of \(4~\mathrm{kV/mm}\). Find the field inside the void.
- For a flat disc void in a solid (\(\varepsilon_r = 5\)) whose trapped gas breaks down at \(2.8~\mathrm{kV/mm}\), find the bulk field at which PD begins.
- Describe how an electrical tree grows, why it can take years, and the role partial discharge plays at each tip.
- Explain dry-band arcing and tracking on a polluted outdoor insulator, and why a hydrophobic silicone surface resists it.