Part 2 · Chapter 4

Conduction and Ionization in Gases

Part 1 mapped the field; now we ask what the field does to the air it sits in. A gas is one of the finest insulators we have — until it isn't. This chapter is the physics of that change of heart: the handful of elementary processes that breed free electrons inside a gas and the rival processes that mop them up, the bookkeeping that turns those events into a coefficient, and the simple current–voltage curve in which the whole story is already written.

High-Voltage Engineering Prof. Mithun Mondal Reading time ≈ 40 min
i What you'll learn
  • Why a clean gas barely conducts at all, and what it takes to change that — the difference between a gas that insulates and one that ionizes.
  • The kinetic picture: mean free path, drift, the energy \(eE\lambda\) an electron wins between collisions, and why the reduced field \(E/p\) — not \(E\) alone — is the master variable.
  • The four ways to free an electron — impact, photo, thermal, and metastable (Penning) ionization — and which one drives breakdown.
  • Townsend's first ionization coefficient \(\alpha\) and the exponential growth \(n = n_0 e^{\alpha x}\) that is the seed of every avalanche.
  • The processes that fight back — recombination, attachment, diffusion — and the effective ionization coefficient \(\bar{\alpha}=\alpha-\eta\) that decides who wins.
  • Why SF₆ is so strong, and how the three regions of the gas-gap I–V curve already contain the whole chapter.
Section 4-1

The Gas as an Insulator

Begin with a fact that is easy to take for granted: at ordinary pressure, a gas is one of the best insulators we own. Its molecules are electrically neutral, spaced far apart, and carry no loose charge to ferry a current across a gap. Left entirely to itself, an air gap is not perfectly empty of carriers — cosmic rays and the natural radioactivity of the surroundings knock loose on the order of ten ion pairs in every cubic centimetre each second — but those few are swept up or recombine almost as fast as they appear, and the current that crosses even a strongly charged gap is vanishingly small, a matter of microamperes or less.

So the interesting question is not why a gas insulates, but how it ever stops. The answer, and the subject of this entire part of the course, is ionization: the wholesale manufacture of free electrons and positive ions inside the gas itself. Once the gas begins to breed its own carriers faster than they are lost, the trickle of current turns into a flood, and what was an insulator becomes, abruptly, a conductor. Townsend's avalanche, the streamer, the spark, the arc — all the dramatic chapters ahead — are just successive stages of that runaway. This chapter lays the groundwork by examining the elementary events one at a time, before the next chapters assemble them into a criterion for breakdown.

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A gas conducts only when its carriers multiply
\[ \text{neutral gas (insulator)} \;\;\xrightarrow{\;\text{ionization}\;}\;\; \text{free electrons + ions (conductor)} \]

Breakdown is not a property the gas possesses; it is a process the field provokes. Everything that follows is an accounting of how carriers are created and how they are lost.

Section 4-2

Electrons, Fields and Free Paths

To see how ionization gets started, follow a single free electron through the gap. It does not glide smoothly to the anode; it ricochets, colliding with gas molecules and travelling on average only a short distance — the mean free path \(\lambda\) — between one impact and the next. The denser the gas, the more often it collides, so the free path shrinks as pressure rises:

Mean free path (kinetic theory)
\[ \lambda = \frac{kT}{\sqrt{2}\,\pi d^{2}\,p} \quad\Longrightarrow\quad \lambda \propto \frac{1}{p} \]

Superimposed on this random buffeting, the applied field \(E\) drags the electron steadily toward the anode at a drift velocity \(v_d=\mu E\), and along the way it does work on the electron. Between two collisions the energy gained is roughly the force times the distance travelled along the field:

Energy won between collisions
\[ W = eE\lambda \]
cathode (−) anode (+) field E → e⁻ λ (free path)
An electron drifts toward the anode in short hops, gaining energy \(eE\lambda\) on each free path and giving it up at each collision

Now the crucial deduction. If that energy \(eE\lambda\) reaches the molecule's ionization energy, the next collision can knock a second electron free; if it falls short, the energy is mostly surrendered as heat or excitation and the electron must build up again. But \(\lambda\propto 1/p\), so the energy won per free path scales as \(eE\lambda \propto E/p\). It is therefore the ratio \(E/p\) — the field per unit pressure, the reduced field — and not the field alone that decides whether ionization can happen. Double the pressure and you must double the field to keep the electron equally energetic. This single grouping, \(E/p\), will turn out to be the master variable of every gas-discharge law in the chapters ahead, from Townsend's coefficient to Paschen's curve.

Why \(E/p\), not \(E\). An electron must arrive at a collision already carrying the ionization energy. How much it carries depends on how hard the field pulls (\(E\)) and how far it can run before being stopped (\(\lambda\propto 1/p\)). Their product is what matters — which is exactly why high-pressure gases like SF₆ in a GIS need such enormous fields to break down, and why thin air at altitude breaks down so easily.
Section 4-3

Ionization Processes

An electron can be torn from a molecule in several distinct ways, and a high-voltage engineer should know all four — but should also know which one does the heavy lifting. By far the most important for breakdown is ionization by electron impact, also called collision ionization. A drifting electron that has gathered at least the ionization energy \(eV_i\) strikes a neutral molecule and ejects one of its bound electrons, leaving behind a positive ion and now two free electrons where there was one:

Ionization by electron impact (the multiplying process)
\[ e^{-} + A \;\longrightarrow\; A^{+} + 2e^{-}, \qquad \tfrac{1}{2}m v^{2} \ge eV_i \]
e⁻ energy ≥ eVᵢ A A⁺ e⁻ e⁻ two electrons → avalanche
Impact ionization doubles the electron count — one in, two out — which is precisely why it can run away into an avalanche

Because every freed electron can repeat the act, impact ionization is the one process capable of multiplying, and so it sits at the heart of the avalanche. The other three matter at the margins:

Photoionization. A sufficiently energetic photon absorbed by a molecule can itself eject an electron, \(h\nu + A \to A^{+} + e^{-}\), provided \(h\nu \ge eV_i\). This demands short-wavelength ultraviolet light, and it is the mechanism by which a streamer leaps ahead of its own avalanche by seeding fresh electrons in the gas in front of it — central to Chapter 6.

Thermal ionization. At the temperatures of an arc — several thousand kelvin — the sheer violence of thermal agitation, a blend of energetic collisions, radiation and excitation, ionizes the gas in bulk. Its equilibrium degree of ionization is set by the Saha equation, and it is what keeps an established arc conducting.

Ionization by metastables (the Penning effect). Some excited atoms cannot easily shed their energy by radiating; they are metastable and may live long enough to collide with a second species and ionize it — but only if the energy they carry exceeds that species' ionization energy. A trace of argon in neon is the textbook case: neon's metastables (≈ 16.6 eV) comfortably ionize argon (≈ 15.7 eV), and the breakdown voltage of the mixture collapses well below that of either pure gas.

Section 4-4

The First Ionization Coefficient α

Microscopic events are vivid but hard to compute with. Townsend's contribution was to wrap them in a single bookkeeping quantity, the first ionization coefficient \(\alpha\): the average number of ionizing collisions one electron makes per unit distance as it drifts along the field. If a slab of thickness \(dx\) contains \(n\) electrons, they create \(\alpha\,n\,dx\) new ones in crossing it, so the population obeys a simple growth law that integrates to an exponential:

Electron multiplication along the gap
\[ dn = \alpha\,n\,dx \quad\Longrightarrow\quad n = n_{0}\,e^{\alpha x} \]
cathode anode n₀ = 1 n = n₀ eᵅᵈ
One seed electron becomes \(e^{\alpha d}\) electrons across a gap of length \(d\) — the electron avalanche in embryo

A single electron leaving the cathode therefore becomes \(e^{\alpha d}\) electrons by the time it reaches the anode of a gap \(d\) wide — an avalanche. And because \(\alpha\) counts ionizing collisions, and those depend on the energy harvested per free path, \(\alpha\) inherits the same dependence on the reduced field we met in §4-2. Experiment is well fitted by a relation of the form

The coefficient depends on the reduced field
\[ \frac{\alpha}{p} = A\,\exp\!\left(-\frac{B\,p}{E}\right) = A\,\exp\!\left(-\frac{B}{E/p}\right) \]

where \(A\) and \(B\) are gas constants. The full consequences of this exponential growth — the breakdown criterion itself, and the indispensable role of secondary electrons at the cathode — are the business of Chapter 5. Here it is enough to see where \(\alpha\) comes from and why it lives or dies on \(E/p\).

Section 4-5

Loss Processes: Recombination, Attachment, Diffusion

Creation does not go unopposed. Three processes continually drain free charge from the gas, and each one raises the field required to sustain a discharge.

Recombination. A positive ion meeting an electron — or a negative ion — can neutralise it, \(e^{-} + A^{+} \to A\), frequently releasing a photon in the bargain. Because it needs two carriers to meet, its rate grows with the product of the carrier densities, so recombination bites hardest where the discharge is most intense.

Attachment. In certain gases a neutral molecule will readily capture a passing electron to form a negative ion, \(e^{-} + A \to A^{-}\). This is the most consequential of the three, because the negative ion it creates is thousands of times heavier than an electron; it drifts sluggishly, gains almost no energy between collisions, and is hopeless at ionizing. An electron lost to attachment is, for the purposes of multiplication, simply removed from the game.

Diffusion. Quite apart from any reaction, carriers wander down their own density gradient and stray out of the high-field region altogether — a steady leak that matters most at low pressure, where free paths are long.

Not all losses are equal. Recombination and diffusion slow a discharge; attachment can stop it from ever starting. That single difference is what separates ordinary gases from the engineered insulating gases of high-voltage practice — and it is worth its own section.
Section 4-6

Electronegative Gases and Effective Ionization

Gases whose molecules snatch electrons eagerly are called electronegative. Oxygen is mildly so; the undisputed champion is sulphur hexafluoride, SF₆, whose fluorine atoms seize free electrons almost on contact. To weigh creation against this kind of loss, we define an attachment coefficient \(\eta\) — attachments per electron per unit length, the mirror image of \(\alpha\) — and fold the two into one number, the effective ionization coefficient:

Net multiplication is governed by the difference
\[ \bar{\alpha} = \alpha - \eta, \qquad n = n_{0}\,e^{(\alpha-\eta)x} \]

Net growth — and so the very possibility of breakdown — requires \(\bar{\alpha} > 0\), that is \(\alpha > \eta\). At low reduced field \(\eta\) dominates: electrons are mopped up as fast as they are bred, and the gas holds off. Only when \(E/p\) climbs past a critical value \((E/p)_{\text{lim}}\), at which \(\alpha = \eta\), does multiplication finally overtake attachment and an avalanche become possible.

α, η / p E/p → α/p (ionization) η/p (attachment) (E/p)ₗᵢₘ : α = η α > η : avalanche α < η : gas holds
Below the crossover, attachment wins and the gas holds off; above the limiting field \((E/p)_{\text{lim}}\), where \(\alpha=\eta\), net ionization turns positive and breakdown becomes possible

This crossover is the whole reason SF₆ withstands roughly three times the field of air at the same pressure: its \(\eta\) is so large that \(\alpha\) only overtakes it at a much higher reduced field. The limiting field for SF₆ is about \(89~\mathrm{kV/(cm\cdot bar)}\), against roughly \(30~\mathrm{kV/cm}\) for air at one bar — which is exactly why SF₆ is the insulating gas of choice for gas-insulated switchgear and compact high-voltage apparatus.

Section 4-7

The Current–Voltage Characteristic of a Gas Gap

Remarkably, everything above can be read off a single experiment. Take a gap between two plane electrodes, irradiate it weakly so that a steady trickle of seed electrons is always present, and raise the voltage slowly while watching the current. Three regions appear in turn.

current i voltage V → i₀ Vₛ I · ohmic II · saturation III · Townsend non-self-sustained ⟶ | ⟵ self-sustained
The gas-gap I–V curve: a linear rise as ions are collected, a plateau \(i_0\) set by background ionization, then a Townsend surge \(i=i_0 e^{\alpha d}\) up to the breakdown voltage \(V_s\)

Region I — the ohmic rise. At low voltage the current grows in step with the voltage, because a stronger field sweeps an ever-larger fraction of the background-produced ions to the electrodes before they can recombine.

Region II — saturation. Once every ion that is created is also collected, raising the voltage cannot increase the count, and the current flattens into a plateau \(i_0\). This saturation current depends only on the rate of background ionization, not on the voltage — a direct measurement of how many seed carriers the source supplies.

Region III — the Townsend rise. When the voltage is high enough that drifting electrons begin to ionize by collision, each seed electron multiplies, and the current turns sharply upward, climbing as \(i = i_0\,e^{\alpha d}\). Throughout all three regions the discharge is non-self-sustained: cut off the external irradiation and the current dies, because the gas cannot yet replace its own seed electrons. At a definite voltage \(V_s\), multiplication together with the secondary processes at the cathode becomes able to feed itself; the current runs away and the gap breaks down into a self-sustained discharge. Pinpointing that voltage is the entire object of the next chapter.

Section 4-8

Worked Examples

1 Will one free path ionize? (impact)

Problem. In a gas an electron's mean free path is \(\lambda = 1~\mu\mathrm{m}\), and the field is \(E = 100~\mathrm{kV/cm}\). Find the energy it gains over one free path and decide whether it can ionize nitrogen \((V_i = 15.6~\mathrm{V})\) in a single collision.

Solution. The energy in electron-volts is just the field in V/m times the path in metres:

Working
\[ W = eE\lambda \;\Rightarrow\; W[\mathrm{eV}] = (10^{7}~\mathrm{V/m})(10^{-6}~\mathrm{m}) = 10~\mathrm{eV} \]

\(10~\mathrm{eV} < 15.6~\mathrm{eV}\), so a single free path is not enough. The electron must run through several free paths, accumulating energy, before a collision can ionize — which is exactly why ionization needs either a strong field or a long path, i.e. a high \(E/p\).

2 Photoionization threshold (photo)

Problem. What is the longest-wavelength photon that can photoionize an oxygen molecule, \(V_i = 12.2~\mathrm{V}\)? Use \(hc = 1240~\mathrm{eV\cdot nm}\).

Solution. The photon must carry at least the ionization energy, \(h\nu \ge eV_i\), so the threshold wavelength is

Working
\[ \lambda_{\max} = \frac{hc}{eV_i} = \frac{1240~\mathrm{eV\cdot nm}}{12.2~\mathrm{eV}} \approx 102~\mathrm{nm} \]

Only vacuum-ultraviolet light (≲ 102 nm) can do it — far shorter than visible light. This is why photoionization needs the energetic UV photons emitted within a discharge itself, the seed of the streamer mechanism in Chapter 6.

3 Pressure scaling and E/p

Problem. At \(1~\mathrm{bar}\) an electron's mean free path in a gas is \(2~\mu\mathrm{m}\). (a) What is it at \(4~\mathrm{bar}\)? (b) By what factor must the field rise to keep the energy gained per free path unchanged?

Solution. Mean free path falls inversely with pressure, \(\lambda \propto 1/p\):

Working
\[ \lambda_{4} = \lambda_{1}\,\frac{p_1}{p_4} = 2\times\frac{1}{4} = 0.5~\mu\mathrm{m}; \qquad W = eE\lambda \;\text{const} \Rightarrow E \uparrow \times 4 \]

The path shrinks four-fold, so the field must rise four-fold to deliver the same \(eE\lambda\). In other words \(E/p\) is held constant — the cleanest demonstration of why \(E/p\), not \(E\), is the governing parameter of the whole subject.

4 Effective ionization and the SF₆ limit

Problem. In SF₆ the effective ionization coefficient is well described by \(\bar{\alpha}/p = 27.7\,(E/p - 88.4)\), with \(E/p\) in \(\mathrm{kV/(cm\cdot bar)}\). (a) Find the limiting reduced field. (b) At \(3~\mathrm{bar}\), what gap field is needed before net multiplication can occur?

Solution. Net multiplication needs \(\bar{\alpha} \ge 0\); the limit is where \(\bar{\alpha} = 0\):

Working
\[ (E/p)_{\text{lim}} = 88.4~\tfrac{\mathrm{kV}}{\mathrm{cm\cdot bar}}; \quad E_{\text{lim}} = 88.4\times 3 = 265~\tfrac{\mathrm{kV}}{\mathrm{cm}} \approx 26.5~\tfrac{\mathrm{kV}}{\mathrm{mm}} \]

Below about 26.5 kV/mm at 3 bar, attachment wins and the SF₆ simply holds off; only above it does \(\alpha\) overtake \(\eta\) and an avalanche become possible. This single number is what lets a GIS pack a 400-kV bus into a pipe a few hundred millimetres across.

Review

Chapter Summary

Insulator → conductor

A clean gas barely conducts; only when ionization breeds free electrons faster than they are lost does it turn conducting and break down.

Free paths & E/p

An electron wins \(eE\lambda\) between collisions, and \(\lambda\propto 1/p\), so ionization is governed by the reduced field \(E/p\), not \(E\) alone.

Four ways in

Impact ionization multiplies and drives breakdown; photo, thermal and metastable (Penning) ionization matter at the margins.

The coefficient α

\(\alpha\) is ionizing collisions per unit length; \(n=n_0 e^{\alpha x}\) makes one electron an avalanche of \(e^{\alpha d}\), with \(\alpha/p=A e^{-Bp/E}\).

Losses fight back

Recombination, attachment and diffusion remove carriers. Attachment is decisive: it can stop a discharge before it starts.

Effective ionization

\(\bar{\alpha}=\alpha-\eta\) decides the contest. \(\alpha>\eta\) is required for breakdown — the crossover \((E/p)_{\text{lim}}\) is why SF₆ is so strong.

Practice

Problems

For each item, first name the idea it tests — a loss or creation process, the energy \(eE\lambda\), the reduced field, the coefficient \(\alpha\), effective ionization, or the I–V curve — then work it through. Difficulty rises down the list.

  1. State where the few charge carriers in an otherwise un-ionized air gap come from, and roughly how much current they allow.
  2. An electron has a mean free path of \(2~\mu\mathrm{m}\) in a field of \(50~\mathrm{kV/cm}\). Find the energy gained over one free path and say whether it can ionize a molecule of ionization energy \(12~\mathrm{eV}\) in one step.
  3. Explain in one or two sentences why it is the ratio \(E/p\), and not the field \(E\) by itself, that governs whether a gas ionizes.
  4. Identify the ionization process in each case: a vacuum-UV photon freeing an electron; a 6000 K arc column; argon ionized by a neon metastable; a fast electron knocking a second electron loose.
  5. Find the longest wavelength that can photoionize a gas of ionization energy \(15.6~\mathrm{eV}\) \((hc = 1240~\mathrm{eV\cdot nm})\), and state which part of the spectrum it lies in.
  6. A single electron starts at the cathode of a \(d = 5~\mathrm{mm}\) gap in which \(\alpha = 8~\mathrm{mm^{-1}}\). How many electrons reach the anode?
  7. Classify each as recombination, attachment or diffusion: a positive ion and an electron neutralising with a flash of light; an oxygen molecule capturing a slow electron; carriers drifting out of the gap sideways at low pressure.
  8. In a gas \(\alpha = 6~\mathrm{mm^{-1}}\) and \(\eta = 9~\mathrm{mm^{-1}}\) at a given \(E/p\). Find the effective ionization coefficient and state whether the gap can break down at this field.
  9. Using \(\bar{\alpha}/p = 27.7\,(E/p - 88.4)\) for SF₆ with \(E/p\) in \(\mathrm{kV/(cm\cdot bar)}\), find the gap field that just permits net multiplication at \(2~\mathrm{bar}\), and compare it with the breakdown field of air (≈ 30 kV/cm).
  10. Sketch the current–voltage characteristic of an irradiated gas gap, label its three regions, mark the saturation current and the breakdown voltage, and identify exactly where the discharge stops being non-self-sustained.
Tip: the whole chapter turns on one running contest — carriers being made versus carriers being lost. Creation is impact ionization, summarised by \(\alpha\); loss is recombination, attachment and diffusion, with attachment summarised by \(\eta\). Breakdown is simply the moment creation outpaces loss, \(\alpha>\eta\), and the reduced field \(E/p\) is the dial that sets the balance. Hold that one picture and the Townsend criterion of Chapter 5, Paschen's curve in Chapter 6, and even the strength of SF₆ all fall out of it.