Part 7 · Chapter 22

Lightning Phenomena and Overvoltages

So far the course has asked how insulation breaks down and how its health is judged. This part turns to the stresses it must survive — the brief, violent overvoltages that tower far above normal operating voltage. They come from two great sources: the switching of the system itself, and the sky. This chapter takes the more spectacular of the two. A lightning flash delivers tens of thousands of amperes in microseconds, and when it meets a power line the result is a voltage surge of millions of volts that races along the conductors. Understanding where that surge comes from, how big it is, and how it is described by the standard impulse is the foundation for everything that follows on protection and coordination.

High-Voltage Engineering Prof. Mithun Mondal Reading time ≈ 45 min
i What you'll learn
  • How overvoltages are classified into temporary, switching and lightning by their time scale and per-unit size.
  • The physics of a lightning flash — cloud charge separation, the stepped leader, attachment and the bright return stroke.
  • The stroke as a current source: the peak-current distribution (median \(\approx 30~\mathrm{kA}\)), waveshape and steepness.
  • The standard \(1.2/50~\mu\mathrm{s}\) lightning impulse and the \(8/20~\mu\mathrm{s}\) current impulse, with their front and tail definitions.
  • Why a direct stroke to a conductor gives the enormous travelling-wave voltage \(V=\tfrac{1}{2}ZI\), and how shielding and back-flashover work.
  • How tower footing resistance, induced surges and ground-flash density set the lightning risk a line faces.
Section 22-1

The Overvoltage Problem

A power system spends its life at a steady operating voltage, but it must be built to survive brief excursions far above it. These overvoltages are measured in per unit of the normal peak phase-to-earth voltage, so that a \(3~\mathrm{p.u.}\) surge means three times that crest whatever the system voltage. They sort naturally into three families by how long they last and how they are shaped — and, helpfully, the time scale and the origin go together.

lightning ~µs · fast front switching ~100s µs · slow front temporary cycles · power freq
The three overvoltage families by time scale — a fast lightning spike (microseconds), a slow-front switching surge (hundreds of microseconds), and a sustained temporary overvoltage at power frequency (many cycles)

Temporary overvoltages are sustained, lightly damped power-frequency rises — a few cycles to seconds — from events such as load rejection, earth faults or resonance; they are modest in size (often \(1.3\)–\(1.5~\mathrm{p.u.}\)) but long enough to matter for arrester ratings. Switching overvoltages are slow-front transients of a few hundred microseconds, born inside the system when breakers operate; on long EHV lines they dominate the insulation design and are the subject of Chapter 23. Lightning overvoltages are the fast-front extreme — a steep spike over in tens of microseconds — caused by the external strike of a flash, and they govern the insulation of lower and medium transmission voltages. This chapter is devoted to that last, fiercest source.

Section 22-2

The Physics of a Lightning Flash

Lightning begins in the cumulonimbus cloud, where violent updraughts carry water and ice through the freezing level. Collisions between rising ice crystals and falling soft hail (graupel) transfer charge, and the updraught then sorts the charge by particle size, leaving the cloud with a broadly negative base, a positive top, and often a small positive pocket near the base. The negative base induces positive charge on the ground beneath, and the field between them builds until the air can no longer hold it.

+ + + + – – – – – + + + + stepped leader connecting streamer return stroke (bright, high I)
A negative downward flash — the stepped leader descends in jumps, an upward streamer rises to meet it, and at attachment the brilliant return stroke surges up the channel carrying the main current

The discharge unfolds in stages. A faint stepped leader works downward from the cloud base in a jagged series of jumps, each a few tens of metres, carving an ionised channel and lowering negative charge toward the earth. As it nears the ground the intensified field launches upward connecting streamers from tall, grounded objects. When one meets the leader — the moment of attachment — a conducting bridge is completed from cloud to ground, and the stored charge pours down it. This is the return stroke: a brilliant wave of current racing up the channel that carries the bulk of the flash's energy and is what the eye sees as the flash. A single flash often contains several strokes, later ones travelling down a re-used channel via a fast dart leader. About nine in ten cloud-to-ground flashes are negative and downward, and it is the return-stroke current that threatens a power line.

Section 22-3

The Stroke as a Current Source

For the power engineer the crucial abstraction is that a lightning return stroke behaves essentially as a current source: it injects a fixed quantity of charge almost regardless of what it strikes, and whatever it strikes develops whatever voltage that current demands. The peak current varies widely from flash to flash and is described statistically — the median first-stroke peak is about \(30~\mathrm{kA}\), a small fraction of flashes exceed \(100~\mathrm{kA}\), and the distribution of peaks is taken as roughly log-normal. Three features of the current matter for insulation:

ParameterTypical valueWhy it matters
Peak current \(I\)median \(\approx 30~\mathrm{kA}\); up to \(>100~\mathrm{kA}\)sets the peak surge voltage \(V=\tfrac12 ZI\)
Steepness \(\mathrm{d}i/\mathrm{d}t\)order of \(10\)–\(40~\mathrm{kA}/\mu\mathrm{s}\)drives inductive \(L\,\mathrm{d}i/\mathrm{d}t\) rises & induced surges
Charge / specific energyorder of a few C; \(\int i^2\,\mathrm{d}t\)governs heating, melting, arrester duty
The stroke fixes the current; the struck object fixes the voltage. This single idea is the key to the whole chapter. Lightning hands a line a near-fixed current, and Ohm's and the surge laws then decide the voltage — which is why a high surge impedance or a high footing resistance turns the same stroke into a far larger and more dangerous overvoltage.
Section 22-4

The Standard Lightning Impulse

To test and rate insulation against lightning, the messy natural surge is replaced by a standard, repeatable waveform: the \(1.2/50~\mu\mathrm{s}\) lightning impulse voltage. It rises swiftly to a crest and then decays more slowly, and two numbers define it. The front time \(T_1 = 1.2~\mu\mathrm{s}\) is a virtual rise time, defined as \(1.67\) times the interval the wave takes to climb from \(30\%\) to \(90\%\) of its peak (a construction that sidesteps the ill-defined toe of the curve). The tail time \(T_2 = 50~\mu\mathrm{s}\) is the time from the virtual origin to the point where the wave has fallen back to half its peak.

V t → peak (100%) 90% 30% 50% O₁ T₁ = 1.2 µs T₂ = 50 µs (to half value)
The standard \(1.2/50~\mu\mathrm{s}\) lightning impulse — the \(30\%\) and \(90\%\) front points fix the virtual origin \(O_1\) and the front time \(T_1\); the tail time \(T_2\) runs from \(O_1\) to the half-value point

The companion standard lightning current impulse is the \(8/20~\mu\mathrm{s}\) wave, used to rate the current-handling duty of surge arresters and to test earthing. Both waveforms are specified with tolerances (about \(\pm30\%\) on the front and \(\pm20\%\) on the tail for the voltage impulse) so that laboratories worldwide reproduce the same stress. The whole apparatus of impulse generators from the earlier high-voltage-generation chapter exists to manufacture exactly these shapes on demand.

Section 22-5

Direct Strokes and the Surge Voltage

Now join the current source to the line. A conductor in free space has a surge impedance \(Z\) — the ratio of voltage to current for a travelling wave, typically \(300\)–\(500~\Omega\) for an overhead line. When lightning strikes the conductor directly, the injected current \(I\) cannot go anywhere but along the line, splitting into two waves that travel in opposite directions. Each direction carries half the current, so the voltage that appears at the strike point is

Direct stroke to a conductor
\[ V = \tfrac{1}{2}\,Z\,I \]
conductor, surge impedance Z I (stroke) ½I → ← ½I V = ½ZI V = ½ZI
A direct stroke to a phase conductor — the current splits into two travelling waves, each carrying \(\tfrac12 I\), so a voltage \(V=\tfrac12 ZI\) is launched in both directions along the line

The numbers are alarming. Even a modest \(30~\mathrm{kA}\) stroke into a \(400~\Omega\) line raises the conductor by \(\tfrac12(400)(30{,}000)=6~\mathrm{MV}\) — vastly beyond any line's insulation. A direct stroke to a phase conductor is therefore almost always destructive, and the practical art of lightning protection is mostly about preventing such strikes from reaching the phase conductors at all, and about draining the inevitable surges harmlessly to earth. These launched waves do not stay put; they race along the line as travelling waves, reflecting and refracting at every junction — the subject taken up in detail in Chapter 23.

Section 22-6

Shielding and Back-Flashover

Because a direct hit to a phase conductor is intolerable, transmission lines are shielded by one or more earthed ground wires (shield wires) strung above the phase conductors and bonded to every tower. Their job is to intercept the descending leader so the stroke terminates on the shield wire and tower rather than on the live conductor. How well they do this is captured by the shielding angle \(\alpha\) — the angle between the vertical through the shield wire and the line to the conductor it protects. A smaller angle gives better coverage; the modern electrogeometric model refines this by recognising that the leader is "caught" by whichever earthed or live part it first comes within a striking distance of, a distance that grows with the stroke current.

shield wire phase α stroke I ↓ R_f (footing) back-flashover if V_tower > withstand
Shielding and back-flashover — an earthed shield wire intercepts the stroke (shielding angle \(\alpha\)); the current flows down the tower through the footing resistance \(R_f\), and if the tower-top voltage exceeds the insulation withstand it flashes back onto the phase conductor

Shielding creates a subtler danger of its own. When the stroke lands on the shield wire or tower, its current must flow down the steel to earth through the tower footing resistance \(R_f\). That current drives the tower top to a high potential — roughly \(I R_f\) plus an inductive \(L\,\mathrm{d}i/\mathrm{d}t\) term — and if this exceeds the insulation's withstand, the tower flashes back onto the phase conductor it was meant to protect. This back-flashover is the dominant lightning fault mechanism on shielded lines, and the chief defence against it is a low footing resistance: good earthing, counterpoise wires and ground rods that let the surge current bleed away without lifting the tower to a flashover potential. Lightning protection thus rests on two pillars — shield wires to keep strokes off the phases, and low footing resistance to keep the shielded strokes from flashing back.

Section 22-7

Induced Overvoltages

A line need not be struck at all to feel lightning. When a flash hits the ground or another object near a line, its rapidly collapsing electromagnetic field couples a surge onto the conductors by induction. These induced overvoltages are far smaller than a direct hit — usually a few hundred kilovolts at most — because they scale with the field at a distance rather than with the full stroke current. On high-voltage transmission lines, whose insulation easily withstands a few hundred kilovolts, they are usually unimportant. But on distribution lines at \(11\)–\(33~\mathrm{kV}\), where the insulation level is low and direct strikes are comparatively rare, induced surges from nearby ground flashes become the main lightning threat, and the number of nearby strokes — set by the local flash density — drives the outage rate.

Section 22-8

Ground-Flash Density and Risk

How often a line is threatened depends on how lightning-prone its territory is. The traditional measure is the keraunic level \(T_d\), the number of thunderstorm-days per year, but the modern and more useful quantity is the ground-flash density \(N_g\) — the number of cloud-to-ground flashes per square kilometre per year, now measured directly by lightning-location networks. A common empirical bridge between them is

Flash density from thunderstorm-days
\[ N_g \approx 0.04\,T_d^{\,1.25} \quad\text{(flashes / km}^2\text{/year)} \]

A line is a wide target: it collects not only the flashes that fall on it directly but those within a lateral attractive width that grows with conductor height. The expected number of strokes to a span, and hence the expected number of back-flashovers and outages, follows from \(N_g\), the line height and the footing resistance. This risk figure is the starting point for the protection and insulation-coordination design of Chapter 24: knowing how many strokes will come, and how big they are likely to be, tells the engineer how much shielding, how low a footing resistance and how many arresters the line must have to meet its target reliability.

Section 22-9

Worked Examples

1 Voltage from a direct stroke

Problem. A \(30~\mathrm{kA}\) stroke hits a phase conductor of surge impedance \(Z = 400~\Omega\). Find the surge voltage launched at the strike point.

Solution. The current splits both ways, so use \(V = \tfrac12 ZI\):

Working
\[ V = \tfrac{1}{2}(400)(30\times10^{3}) = 6\times10^{6}~\mathrm{V} = 6~\mathrm{MV} \]

Six megavolts — orders of magnitude above any line's withstand. This is exactly why phase conductors must be shielded from direct strokes rather than insulated against them.

2 Front time of the standard impulse

Problem. An impulse rises from \(30\%\) to \(90\%\) of its peak in \(0.72~\mu\mathrm{s}\). Find the virtual front time and confirm it is a standard wave.

Solution. The front time is \(T_1 = 1.67\times(t_{90}-t_{30})\):

Working
\[ T_1 = 1.67 \times 0.72~\mu\mathrm{s} \approx 1.2~\mu\mathrm{s} \]

A front time of \(1.2~\mu\mathrm{s}\) — the wave is a standard \(1.2/50\) lightning impulse (within the \(\pm30\%\) front tolerance).

3 Front steepness

Problem. A \(1.0~\mathrm{MV}\) peak, \(1.2/50~\mu\mathrm{s}\) impulse is applied. Estimate the average steepness of its front.

Solution. Steepness is peak divided by front time, \(S \approx V_p/T_1\):

Working
\[ S \approx \frac{1.0\times10^{6}}{1.2\times10^{-6}} \approx 8.3\times10^{11}~\mathrm{V/s} = 833~\mathrm{kV}/\mu\mathrm{s} \]

About 833 kV/µs — a steepness this great is why fast-front surges stress the first few turns of a winding so severely and why the wavefront, not just the peak, is part of the test specification.

4 Tower-top voltage and back-flashover

Problem. A \(30~\mathrm{kA}\) stroke terminates on a tower whose footing resistance is \(R_f = 20~\Omega\). Estimate the resistive tower-top rise and compare it with a \(550~\mathrm{kV}\) insulation withstand.

Solution. Take the dominant resistive term \(V \approx I R_f\) (ignoring the inductive part):

Working
\[ V \approx (30\times10^{3})(20) = 600\times10^{3}~\mathrm{V} = 600~\mathrm{kV} \]

At \(600~\mathrm{kV}\) the tower top exceeds the \(550~\mathrm{kV}\) withstand — a back-flashover occurs. Halving the footing resistance to \(10~\Omega\) would drop the rise to \(300~\mathrm{kV}\) and prevent it, showing directly why low footing resistance is the front-line defence.

5 Ground-flash density

Problem. A region records \(T_d = 40\) thunderstorm-days per year. Estimate its ground-flash density.

Solution. Apply \(N_g \approx 0.04\,T_d^{1.25}\) with \(40^{1.25} = 40\cdot40^{0.25}\approx 40(2.51)\):

Working
\[ N_g \approx 0.04 \times 40^{1.25} \approx 0.04 \times 100.6 \approx 4.0~\text{flashes/km}^2\text{/yr} \]

About 4 flashes per square kilometre per year — a moderately active region. Multiplied by the line's attractive width, this fixes the expected stroke count that the protection design of Chapter 24 must accommodate.

Review

Chapter Summary

Three families

Overvoltages sort by time scale into temporary (power-frequency), switching (slow-front) and lightning (fast-front), measured in per unit.

The flash

Cloud charge separation, a stepped leader, attachment, and the bright high-current return stroke; mostly negative downward flashes.

A current source

Median peak \(\approx 30~\mathrm{kA}\); the stroke fixes the current and the struck object develops the voltage.

Standard impulse

\(1.2/50~\mu\mathrm{s}\) voltage (\(T_1\) from the \(30\%\)–\(90\%\) front, \(T_2\) to half value) and \(8/20~\mu\mathrm{s}\) current.

Surge voltage

A direct stroke gives \(V=\tfrac12 ZI\) — megavolts — launched as travelling waves; phases must be shielded, not insulated.

Shielding & risk

Ground wires (angle \(\alpha\)) intercept strokes; low footing resistance stops back-flashover; \(N_g\) sets the lightning risk.

Practice

Problems

For each item, first identify what it tests — the overvoltage classification, the flash mechanism, the current-source idea, the standard impulse, the surge voltage, shielding and back-flashover, or risk — then apply it. Difficulty rises down the list.

  1. Classify overvoltages into their three families and give the approximate time scale and origin of each.
  2. Describe the stages of a negative downward flash from the stepped leader to the return stroke.
  3. Explain why a lightning stroke is treated as a current source, and what fixes the resulting voltage.
  4. Define the front time \(T_1\) and tail time \(T_2\) of the standard \(1.2/50\) impulse, and explain the role of the virtual origin.
  5. A \(45~\mathrm{kA}\) stroke hits a conductor with \(Z = 350~\Omega\). Find the surge voltage at the strike point.
  6. An impulse climbs from \(30\%\) to \(90\%\) of peak in \(0.66~\mu\mathrm{s}\). Find its virtual front time and state whether it is standard.
  7. Explain shielding by ground wires and the meaning of the shielding angle, and what the electrogeometric model adds.
  8. A \(40~\mathrm{kA}\) stroke flows to earth through a footing resistance of \(15~\Omega\). Find the resistive tower-top rise and say whether a \(700~\mathrm{kV}\) line would back-flash.
  9. Explain why induced overvoltages matter on distribution lines but rarely on EHV transmission lines.
  10. A region has \(T_d = 60\) thunderstorm-days. Estimate \(N_g\), and explain how this figure feeds into a line's protection design.
Tip: this chapter turns on one transformation and one waveform. The transformation is \(V=\tfrac12 ZI\): lightning delivers a near-fixed current, and the surge impedance (of a conductor) or the footing resistance (of a tower) turns it into a voltage — megavolts on a struck phase, hundreds of kilovolts on a struck tower. The waveform is the standard \(1.2/50\) impulse that makes that surge testable. Keep strokes off the phases with shield wires, keep struck towers from flashing back with low footing resistance, and you have the whole strategy — to be drained away by the travelling-wave analysis of Chapter 23 and the arresters and coordination of Chapter 24.