Generation of Impulse Currents and Triggering
A lightning stroke is not only a voltage — it is a torrent of current, tens of kiloamperes that a surge arrester must swallow and an earthing system must carry away. This chapter builds that current from a capacitor bank discharged through an inductor, then turns to the question that haunted the last chapter: how do you make a generator fire exactly when you want it to?
- Why impulse currents are needed to test surge arresters and earthing, and the standard 8/20 µs and 4/10 µs waveshapes.
- The RLC discharge circuit and its under-, critically- and over-damped regimes.
- The surge impedance \(\sqrt{L/C}\), the critical-damping resistance \(R = 2\sqrt{L/C}\), and the peak current \(V_0\sqrt{C/L}\).
- Why high-current generators parallel capacitors — the mirror image of the Marx's series stacking.
- Why precise triggering matters, and how a three-electrode gap fires on command.
- The trigatron and how it erects a Marx generator at a chosen instant.
Why Impulse Currents?
Chapter 13 reproduced the voltage of a lightning surge. But a stroke is equally a current event — a channel carrying tens of kiloamperes for a few microseconds. Two classes of equipment exist precisely to survive that current, and both must be tested with it. A surge arrester clamps an overvoltage by suddenly conducting, diverting the lightning current safely to earth; it must absorb that current without shattering. An earthing system must carry the same current into the ground without its potential rising dangerously. To certify either, we need a source that delivers a controlled, repeatable high-current pulse.
As with voltage, the waveshapes are standardised so results compare worldwide. The everyday workhorse is the 8/20 µs current impulse, used to rate arrester discharge behaviour; a sharper 4/10 µs wave serves high-current withstand tests; and long rectangular currents of hundreds to thousands of microseconds test the thermal and energy endurance of arrester blocks. The generator that makes them is, at heart, the dual of the voltage circuit: where the impulse-voltage generator emphasised resistance and capacitance, the current generator turns on inductance.
Standard Current Waves
An impulse current is defined just like an impulse voltage: a front time \(T_1\) (the rise, again taken from the steep 10–90% portion) and a time to half-value \(T_2\) on the tail. So "8/20" means an \(8~\mu\mathrm{s}\) front and a \(20~\mu\mathrm{s}\) time to half-value. The crucial extra requirement is that the wave be unidirectional — the current must not swing back through zero by more than a small allowed amount, or it would no longer represent a lightning surge.
Keeping the wave unidirectional turns out to be the whole design challenge, and it comes down to one circuit parameter — the damping. Get the damping wrong and the current rings back and forth like a struck bell; get it right and it makes a single clean pulse. To see why, we need the circuit.
The RLC Generator
The impulse-current generator is a capacitor bank \(C\), charged to \(V_0\), that is discharged through a series inductor \(L\) and resistor \(R\) into the test object. The inductance is no accident — it is the deliberate ingredient that controls the rate of rise and limits the peak, and the whole circuit is a textbook series RLC loop. When the switch (a triggered gap) closes, the capacitor drives a current governed by
This is the dual of the voltage generator: there, a capacitor charged a smaller capacitor through a resistor; here, a capacitor drives a current through an inductor. Its behaviour — and whether the output is the clean unidirectional pulse we need — is decided entirely by how the three elements balance, which is the story of damping.
Damping and the Waveshape
Solving the RLC loop gives a current whose character depends on a single comparison: the circuit resistance \(R\) against the surge impedance \(\sqrt{L/C}\). When \(R\) is small the discharge is underdamped and the current is a decaying sinusoid that swings negative; when \(R\) is large it is overdamped and sluggish; between them lies critical damping. The underdamped solution makes the oscillation explicit:
The boundary between ringing and not ringing is critical damping, which occurs when the resistance equals twice the surge impedance:
Peak Current and Parallel Banks
For a lightly damped circuit the first peak of the current is reached after about a quarter-cycle, and its size follows from the surge impedance directly — the stored voltage divided by \(\sqrt{L/C}\):
This formula is a design map. To reach a higher peak current we want a small surge impedance — a large capacitance and a small inductance. Capacitance is increased the obvious way: by connecting many capacitors in parallel. Here is the pleasing symmetry with the last chapter. The Marx generator chases voltage, so it charges capacitors in parallel and fires them in series; the impulse-current generator chases current, so it simply discharges its capacitors in parallel. The inductance, meanwhile, is kept low by short, wide, coaxial busbars — every nanohenry of stray inductance steals peak current.
The two great impulse generators are mirror images — the same capacitors arranged for opposite ends, voltage by series stacking, current by parallel banking and low inductance.
Why Triggering Matters
Both impulse generators — voltage and current — depend on a switch that connects the charged store to the load at a single, sharp instant. So far that switch has been "a sphere gap that fires when the voltage reaches its breakdown value." That is enough to make a pulse, but it is useless for real testing, because the firing instant is uncontrolled: the gap goes whenever the voltage happens to reach breakdown, scattered by humidity, dust and statistics.
Serious work needs the generator to fire on command, at a chosen moment, for three reasons. First, synchronisation: the measuring oscilloscope must be started a known instant before the pulse arrives, or the fast wave is missed. Second, chopped-wave tests: to test insulation against a surge truncated by a nearby flashover, a second gap must chop the wave at a precise time. Third, and most important, multistage erection: a Marx generator's stages must be made to fire together reliably, which means the first gap must be fired deliberately rather than left to chance. All three demand a gap that holds the voltage off and then breaks down the instant it is told to.
The Three-Electrode Gap and the Trigatron
The solution is to add a third electrode to the gap. The two main electrodes are set a little wider than their natural breakdown spacing, so the gap holds off the applied voltage indefinitely. A small trigger pulse applied to the third electrode then tips the gap over the edge — either by distorting the field to raise the local stress, or by injecting a burst of initiatory electrons and ultraviolet light that seeds the discharge. The main gap collapses within nanoseconds of the trigger, and the firing instant is now under our control.
The most successful design of this kind is the trigatron. A small metal pin is set into a hole bored through the centre of one main electrode, separated from it by a thin annular gap. A trigger pulse drives a spark across that small annulus; the ultraviolet light and ionised gas it produces flood the main gap with the electrons it needs to break down, and the main discharge follows immediately. The trigatron is compact, fires reliably over a wide range of main-gap voltages, and has very little jitter — which is why it became the standard triggered switch in impulse and pulsed-power systems.
Triggering the Marx
Now the loose end from Chapter 13 can be tied. A Marx generator is fired by building its first gap as a trigatron. While the stages charge in parallel, every gap — including the first — sits just below its breakdown voltage, holding the column inert. To fire, a trigger generator (usually a small pulse transformer) sends a sharp pulse to the trigatron pin in the bottom gap. That gap collapses on command, and its collapse over-volts the second gap, which fires the third, and so on up the stack in a self-propagating cascade — the erection we described before, now started at a precise instant of our choosing.
This is why the controlled first gap matters so much: it converts the Marx from a device that fires whenever its charging voltage drifts up to breakdown into one that fires exactly when the experiment requires, synchronised with the oscilloscope and repeatable shot after shot. The same trigatron principle, scaled and refined, runs through modern pulsed-power machines, where banks of triggered gaps — or fast solid-state switches doing the same job — must close within nanoseconds of one another to add their contributions cleanly.
| Generator | Capacitors arranged | Delivers | Switch / trigger |
|---|---|---|---|
| Impulse voltage (single-stage) | one C, charges load | shaped high voltage | sphere gap |
| Marx generator | parallel charge → series fire | \(nV_0\) high voltage | trigatron (first gap) |
| Impulse current | parallel bank | high current \(V_0\sqrt{C/L}\) | triggered gap |
Worked Examples
Problem. A current generator has \(C = 8~\mu\mathrm{F}\) charged to \(V_0 = 100~\mathrm{kV}\), discharged through \(L = 10~\mu\mathrm{H}\) with small resistance. Find the surge impedance, the natural frequency, and the approximate peak current.
Solution. Use \(\sqrt{L/C}\), \(f_0 = 1/(2\pi\sqrt{LC})\) and \(I_m \approx V_0\sqrt{C/L}\):
A modest \(8~\mu\mathrm{F}\) bank at \(100~\mathrm{kV}\) sources nearly 90 kA — the scale of a real lightning stroke.
Problem. For the same \(L = 10~\mu\mathrm{H}\) and \(C = 8~\mu\mathrm{F}\), find the resistance that gives critical damping, and say what happens if the total circuit resistance is only \(1~\Omega\).
Solution. Apply \(R_{\text{crit}} = 2\sqrt{L/C}\):
At only \(1~\Omega\) the circuit is underdamped, so the current rings and swings negative. To get a clean unidirectional 8/20 wave, the resistance must be raised toward \(2.24~\Omega\) — slightly below it for a fast front within tolerance.
Problem. Ten such capacitors (each \(8~\mu\mathrm{F}\), \(100~\mathrm{kV}\)) are discharged in parallel through the same \(10~\mu\mathrm{H}\). Find the total stored energy and the peak current.
Solution. Energy is \(n\cdot\tfrac12 CV_0^{2}\); the bank capacitance is \(10C = 80~\mu\mathrm{F}\), so \(I_m = V_0\sqrt{C_{\text{tot}}/L}\):
Paralleling ten banks stores 400 kJ and lifts the peak to about 283 kA — though to keep the 8/20 shape the inductance must be reduced in step, since the front lengthens with \(\sqrt{LC}\).
Problem. A circuit has \(C = 4~\mu\mathrm{F}\), \(L = 20~\mu\mathrm{H}\) and total resistance \(R = 3~\Omega\). Is the discharge unidirectional?
Solution. Compare \(R\) with \(R_{\text{crit}} = 2\sqrt{L/C}\):
Since \(R < R_{\text{crit}}\), the circuit is underdamped and the current reverses — not a valid impulse. Adding about \(1.5~\Omega\) of series resistance brings it to the critical boundary and makes the pulse unidirectional.
Chapter Summary
Lightning is a current event; arresters and earthing must carry it. Standard waves: 8/20 µs, 4/10 µs, and long rectangular for energy.
A charged bank \(C\) discharges through series \(L\) and \(R\) — a series RLC loop. Inductance shapes the rise and limits the peak.
\(i(t)=\frac{V_0}{\omega L}e^{-\alpha t}\sin\omega t\); critical at \(R=2\sqrt{L/C}\). Set just under critical for a clean unidirectional wave.
\(I_m \approx V_0\sqrt{C/L}\); for high current, parallel capacitors and minimise inductance — the mirror of the Marx.
Needed for sync, chopped waves and Marx erection. A three-electrode gap holds off then fires on command.
A trigger pin in a hole sparks an annular gap; its ionisation fires the main gap. It erects the Marx at a chosen instant.
Problems
For each item, first identify what it tests — the waveshape, the surge impedance, the peak-current formula, the damping condition, or the triggering principle — then apply it. Difficulty rises down the list.
- State the standard impulse-current waveshape used to rate surge arresters, and explain what "unidirectional" requires of it.
- Name the circuit element that chiefly limits the peak and shapes the front of an impulse current, and contrast its role with the resistors in the voltage generator.
- A generator has \(C = 5~\mu\mathrm{F}\), \(L = 8~\mu\mathrm{H}\), \(V_0 = 80~\mathrm{kV}\). Find the surge impedance and the approximate peak current.
- For that circuit, find the resistance giving critical damping.
- If the total resistance in Problem 3 is \(2~\Omega\), determine the damping regime and whether the current rings.
- A bank of six \(5~\mu\mathrm{F}\) capacitors at \(80~\mathrm{kV}\) is discharged in parallel. Find the total stored energy.
- Explain why an impulse-current generator parallels its capacitors while a Marx generator stacks them in series.
- Give three distinct reasons an impulse generator must be triggered on command rather than left to self-fire.
- Describe, in two or three sentences, how a trigatron fires its main gap.
- Explain how triggering the first gap of a Marx generator erects the whole column, and why a controlled first gap is essential for oscilloscope synchronisation.