Question 1
For the circuit shown in the figure , the Thevenin voltage and resistance looking into X-Y are:

Solution
- Thevenin Voltage (\(V_{Th}\)): By applying KCL at the output node \(V_X\), we find \(V_{Th} = 4\,V\).
- Thevenin Resistance (\(R_{Th}\)): By calculating the short-circuit current (\(I_{SC} = 2\,A\)), we get \(R_{Th} = V_{Th}/I_{SC} = 4/2 = 2\,\Omega\).
Final Answer
Correct answer: (4) \(4V\), \(2\,\Omega\).
