Part 2 · Chapter 17

The p-Block Elements

Six groups, the whole range of chemistry — metals, metalloids and non-metals from boron to the noble gases, with the trends that tie them together and the anomalies that make each group its own world

Fundamentals of Chemistry Prof. Mithun Mondal Reading time ≈ 65 min
i What you'll learn
  • Why the p-block spans metals, metalloids and non-metals, and how its trends run.
  • The inert pair effect and why lower oxidation states grow stable down a group.
  • The signature chemistry of each group — diborane, catenation, ammonia & nitric acid, ozone & sulphuric acid, the halogens, and the noble gases.
  • Key industrial processes: the Ostwald and Contact processes.
  • The oxidising power order of the halogens and the strange compounds of xenon.
  • The anomalous first members (B, C, N, O, F) and why they differ from their families.
Section 17-1

The p-Block & Its Trends

The p-block covers Groups 13–18, where the differentiating electron enters a \(p\) orbital, giving the general configuration \(ns^2np^{1\text{–}6}\). It is the only block holding all three kinds of element — metals (lower left), metalloids along the diagonal, and non-metals (upper right). Across each period non-metallic character rises; down each group metallic character returns.

1314 1516 1718 B* C N O F Ne Al Si P S Cl Ar Ga Ge As Se Br Kr non-metal metalloid metal noble
The p-block — metals, metalloids and non-metals across one block
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Two oxidation states per group
group state (using all \(ns^2np^x\)) and a lower state two less, from the inert pair

The group's highest oxidation state uses all the valence electrons. Down each group, the lower state — two units smaller — becomes increasingly favoured as the \(ns^2\) pair turns reluctant to bond.

Section 17-2

Group 13: The Boron Family

Group 13 (\(\ce{B, Al, Ga, In, Tl}\), \(ns^2np^1\)) opens with the metalloid boron and continues with metals. The usual oxidation state is \(+3\), but \(\ce{Tl+}\) (inert pair) is the most stable thallium ion. Boron is the anomalous first member: small, with a high ionization enthalpy, it forms only covalent, electron-deficient compounds.

B B bridging H: 3-centre, 2-electron "banana" bonds
Diborane B₂H₆ — two B–H–B bridges hold it together
CompoundFormulaNote
Borax\(\ce{Na2B4O7.10H2O}\)borax-bead test for coloured ions
Orthoboric acid\(\ce{H3BO3}\)weak monobasic Lewis acid (accepts \(\ce{OH-}\))
Diborane\(\ce{B2H6}\)electron-deficient; banana bonds
Alum\(\ce{KAl(SO4)2.12H2O}\)water purification, mordant
Why boric acid is monobasic. \(\ce{H3BO3}\) does not donate its own protons; instead it accepts an \(\ce{OH-}\) from water — \(\ce{B(OH)3 + H2O -> [B(OH)4]- + H+}\) — releasing one proton. It is therefore a weak Lewis acid, monobasic in effect.
Section 17-3

Group 14: The Carbon Family

Group 14 (\(\ce{C, Si, Ge, Sn, Pb}\), \(ns^2np^2\)) runs from the non-metal carbon through metalloids to the metals tin and lead. The hallmark is catenation — the ability to form long chains of self-bonds — which is supreme in carbon and fades down the group as the element–element bond weakens.

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Catenation & oxidation states
\(\ce{C} \gg \ce{Si} > \ce{Ge} \approx \ce{Sn} > \ce{Pb}\) · stable states: \(+4\) (top), \(+2\) (\(\ce{Pb^2+}\), inert pair)

Carbon's strong \(\ce{C-C}\) bonds make organic chemistry possible. Lead prefers \(+2\): \(\ce{PbCl4}\) is unstable while \(\ce{PbCl2}\) is not.

SpeciesCharacterNote
Diamond, graphite, fullereneallotropes of carbonsp³ giant, sp² layers, sp² cage (\(\ce{C60}\))
\(\ce{CO}\)neutral oxidepoisonous, strong reductant & ligand
\(\ce{CO2}\)acidic oxidegreenhouse gas, linear
\(\ce{SiO2}\)giant covalentbasis of silicates & glass
Silicones\(\ce{(R2SiO)_n}\)water-repellent polymers
Section 17-4

Group 15: The Nitrogen Family

Group 15 (\(\ce{N, P, As, Sb, Bi}\), \(ns^2np^3\)) shows the widest range of oxidation states, from \(-3\) to \(+5\). Nitrogen, locked in a triple bond \(\ce{N#N}\), is inert until fixed; phosphorus comes as reactive white (\(\ce{P4}\) tetrahedra) and stable red allotropes.

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Ammonia & nitric acid
Haber: \(\ce{N2 + 3H2 ->[Fe] 2NH3}\) · Ostwald: \(\ce{4NH3 + 5O2 ->[Pt] 4NO + 6H2O -> ... -> HNO3}\)

Ammonia (pyramidal, basic) is the gateway to nitric acid: catalytic oxidation gives \(\ce{NO}\), then \(\ce{NO2}\), which dissolves in water to \(\ce{HNO3}\) — the Ostwald process.

OxideN stateOxideN state
\(\ce{N2O}\)+1\(\ce{NO2}\)+4
\(\ce{NO}\)+2\(\ce{N2O5}\)+5
\(\ce{N2O3}\)+3\(\ce{PH3}\) (phosphine)pyramidal, weakly basic
Section 17-5

Group 16: The Oxygen Family (Chalcogens)

Group 16 (\(\ce{O, S, Se, Te, Po}\), \(ns^2np^4\)) — the chalcogens, the "ore-formers". Oxygen exists as \(\ce{O2}\) and the bent, reactive allotrope ozone \(\ce{O3}\); sulphur comes as rhombic and monoclinic forms built from \(\ce{S8}\) crown rings.

O O O ≈117°
Ozone O₃ — bent, with delocalised bonding and ≈117° angle
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Sulphuric acid — the Contact process
\(\ce{2SO2 + O2 ->[V2O5] 2SO3}\); \(\ \ce{SO3 + H2SO4 -> H2S2O7}\); \(\ \ce{H2S2O7 + H2O -> 2H2SO4}\)

\(\ce{SO3}\) is absorbed in concentrated acid (not water, to avoid a fog) as oleum, then diluted. "King of chemicals," \(\ce{H2SO4}\) is a strong acid, dehydrating agent and oxidiser.

Section 17-6

Group 17: The Halogens

Group 17 (\(\ce{F, Cl, Br, I, At}\), \(ns^2np^5\)) holds the most reactive non-metals — one electron short of a noble-gas shell, so they are powerful oxidising agents. They show the \(-1\) state throughout and positive states up to \(+7\) (except fluorine, which, being the most electronegative element, shows only \(-1\)).

Two key orders
Oxidising power: \(\ce{F2} > \ce{Cl2} > \ce{Br2} > \ce{I2}\) · Acid strength of \(\ce{HX}\): \(\ce{HF} < \ce{HCl} < \ce{HBr} < \ce{HI}\)

A halogen displaces any halide below it: \(\ce{Cl2 + 2KBr -> 2KCl + Br2}\). The hydrohalic acids strengthen down the group because the \(\ce{H-X}\) bond weakens, despite falling electronegativity.

SpeciesWhat it isNote
Interhalogens\(\ce{ClF3},\ \ce{IF7}\)more reactive than parent halogens
Bleaching powder\(\ce{CaOCl2}\)from \(\ce{Cl2}\) + slaked lime; oxidising bleach
\(\ce{HF}\)weak acidetches glass; anomalous (H-bonding)
\(\ce{HClO4}\)perchloric acidstrongest common oxoacid of Cl
Section 17-7

Group 18: The Noble Gases

Group 18 (\(\ce{He, Ne, Ar, Kr, Xe, Rn}\)) have complete octets (\(ns^2np^6\), He is \(1s^2\)), the highest ionization enthalpies in each period, and almost no chemistry. For decades they were thought wholly inert — until 1962, when xenon, the largest non-radioactive member with the lowest ionization enthalpy, was made to react with fluorine.

CompoundHybridisation / shape
\(\ce{XeF2}\)\(sp^3d\), linear
\(\ce{XeF4}\)\(sp^3d^2\), square planar
\(\ce{XeF6}\)\(sp^3d^3\), distorted octahedral
Everyday noble gases. Helium fills airships and breathing mixes for divers; neon glows in signs; argon blankets welding arcs and fills light bulbs. Their inertness — not their reactivity — is exactly what makes them useful.
Section 17-8

The Inert Pair Effect & First-Member Anomalies

Two cross-cutting ideas explain most p-block surprises. The inert pair effect is the growing reluctance of the \(ns^2\) electrons to take part in bonding as a group is descended, so the lower oxidation state (two below the group state) becomes more stable for the heaviest members.

GroupHigher stateStable lower state (heavy element)
13\(+3\)\(\ce{Tl+}\)
14\(+4\)\(\ce{Pb^2+}\)
15\(+5\)\(\ce{Bi^3+}\)

The first member of every p-block group (\(\ce{B, C, N, O, F}\)) is anomalous — it is unusually small, highly electronegative, and has no available \(d\)-orbitals. It therefore caps its covalency at four, forms strong \(p\pi\!-\!p\pi\) multiple bonds (\(\ce{N#N}\), \(\ce{O=O}\)) that its heavier congeners cannot, and often resembles the element diagonally below it.

Worked Examples

Putting It to Work

1 Inert pair stability

Problem. Which is the more stable ion, \(\ce{Tl+}\) or \(\ce{Tl^3+}\)? Explain.

Solution. The \(6s^2\) pair is reluctant to bond in the heaviest member:

Working
\[ \ce{Tl+}\ \text{is more stable (inert pair effect)} \]
2 Electron deficiency

Problem. Why is \(\ce{B2H6}\) called electron-deficient, and how does it bond?

Solution. Count: 12 valence electrons for 8 bonds — too few for normal 2-electron bonds:

Working
\[ \text{two }\ce{B-H-B}\text{ bridges = 3-centre, 2-electron (banana) bonds} \]
3 Catenation order

Problem. Arrange \(\ce{C},\ \ce{Si},\ \ce{Ge},\ \ce{Pb}\) by decreasing tendency to catenate.

Solution. Catenation falls as the element–element bond weakens down the group:

Working
\[ \ce{C} \gg \ce{Si} > \ce{Ge} > \ce{Pb} \]
4 Halogen displacement

Problem. Will chlorine displace bromine from \(\ce{KBr}\)? Write the reaction.

Solution. \(\ce{Cl2}\) is a stronger oxidant than \(\ce{Br2}\), so yes:

Working
\[ \ce{Cl2 + 2KBr -> 2KCl + Br2} \]
5 Xenon geometry

Problem. Give the hybridisation and shape of \(\ce{XeF4}\).

Solution. Xe has 4 bond pairs + 2 lone pairs → 6 electron domains:

Working
\[ sp^3d^2,\ \textbf{square planar} \]
6 Acid-strength order

Problem. Arrange \(\ce{HF},\ \ce{HCl},\ \ce{HBr},\ \ce{HI}\) by increasing acid strength and explain.

Solution. Acid strength tracks the weakening \(\ce{H-X}\) bond down the group:

Working
\[ \ce{HF} < \ce{HCl} < \ce{HBr} < \ce{HI}\quad(\text{bond enthalpy falls}) \]
Review

Chapter Summary

The block

Groups 13–18, \(ns^2np^{1\text{–}6}\); metals, metalloids and non-metals together.

Group 13–14

Electron-deficient diborane; catenation supreme in carbon; CO/CO₂, silicones.

Group 15–16

Ammonia → nitric acid (Ostwald); ozone; sulphuric acid (Contact process).

Group 17

Oxidising power \(\ce{F2}>\ce{Cl2}>\ce{Br2}>\ce{I2}\); acid strength \(\ce{HF}<...<\ce{HI}\).

Group 18

Inert octets; only xenon reacts — \(\ce{XeF2},\ \ce{XeF4},\ \ce{XeF6}\).

Two big ideas

Inert pair effect (lower state stable down group) and anomalous first members.

Practice

Problems

For each item, first decide which group or cross-cutting idea it tests, then apply the relevant rule. Difficulty rises down the list.

  1. Give the general electronic configuration of the p-block and state why it contains all three element types.
  2. Explain the inert pair effect and give one example from Group 13 and one from Group 14.
  3. Why is \(\ce{B2H6}\) electron-deficient? Describe its bridging bonds.
  4. Explain why orthoboric acid is a weak monobasic acid.
  5. Arrange \(\ce{C},\ \ce{Si},\ \ce{Sn},\ \ce{Pb}\) by tendency to catenate and justify.
  6. Distinguish \(\ce{CO}\) and \(\ce{CO2}\) in terms of bonding and acid–base character.
  7. Write the steps of the Ostwald process for manufacturing nitric acid.
  8. List the oxides of nitrogen with the oxidation state of nitrogen in each.
  9. Draw the structure of ozone and explain why it is a strong oxidising agent.
  10. Write the Contact-process reactions and explain why \(\ce{SO3}\) is absorbed in acid, not water.
  11. Arrange \(\ce{HF},\ \ce{HCl},\ \ce{HBr},\ \ce{HI}\) by acid strength and explain the trend.
  12. Give the hybridisation and shape of \(\ce{XeF2},\ \ce{XeF4}\) and \(\ce{XeF6}\).
Tip: tackle the p-block one group at a time, but carry two master keys across all of them — the inert pair effect (which lower oxidation state to expect) and the first-member anomaly (small size, no \(d\)-orbitals, strong \(p\pi\!-\!p\pi\) bonds). Almost every "exception" in this chapter is one of these two ideas in disguise.