Part 2 · Chapter 15

Hydrogen and Its Compounds

The simplest atom and the most versatile element — its split personality on the periodic table, the hydrides it forms with almost everything, and the chemistry of water and hydrogen peroxide

Fundamentals of Chemistry Prof. Mithun Mondal Reading time ≈ 48 min
i What you'll learn
  • Why hydrogen resembles both the alkali metals and the halogens, yet belongs to neither.
  • The three isotopes — protium, deuterium, tritium — and how they differ.
  • Laboratory and industrial preparation of dihydrogen, including water gas and steam reforming.
  • The three families of hydrides — ionic, covalent and metallic.
  • The structure of water, the chemistry of hardness, and how to soften it.
  • Hydrogen peroxide — its structure, dual redox role, volume strength, and uses.
Section 15-1

The Position of Hydrogen

Hydrogen has the configuration \(1s^1\) — a single electron, like an alkali metal, yet just one electron short of helium's closed shell, like a halogen. This dual character is why no single position on the table fits it perfectly. It is usually placed atop Group 1, but its resemblance to Group 17 is just as strong.

Like alkali metals (Group 1)Like halogens (Group 17)
one valence electron (\(ns^1\))one electron short of a noble gas
forms \(\ce{H+}\), electropositiveforms \(\ce{H-}\) (hydride ion)
combines with non-metalsdiatomic \(\ce{H2}\), like \(\ce{X2}\)
high ionization enthalpy
The verdict. Because it matches both families only partly — \(\ce{H+}\) is a bare proton with no parallel among metals, and \(\ce{H2}\) is far less reactive than the halogens — hydrogen is best regarded as a unique element with a place of its own.
Section 15-2

Isotopes of Hydrogen

Hydrogen has three isotopes, identical in chemistry but differing in the number of neutrons — and therefore in mass and nuclear stability.

IsotopeSymbolNeutronsAbundanceNature
Protium\(\ce{^1_1H}\)099.98 %stable
Deuterium\(\ce{^2_1H}\) (D)10.0156 %stable
Tritium\(\ce{^3_1H}\) (T)2traceradioactive (β-emitter)
Same chemistry, different mass. All three share one electron and react alike, but the threefold mass spread is the largest of any element's isotopes — large enough that deuterium reacts measurably more slowly than protium (the kinetic isotope effect).
Section 15-3

Preparation of Dihydrogen

In the laboratory, \(\ce{H2}\) comes from the action of a dilute acid — or a strong base — on a suitable metal. Industrially, the cheapest routes start from water or hydrocarbons.

🧪
Laboratory preparation
\(\ce{Zn + H2SO4 -> ZnSO4 + H2 ^}\)

Granulated zinc with dilute sulphuric acid is the standard bench reaction. Zinc also liberates \(\ce{H2}\) from hot alkali: \(\ce{Zn + 2NaOH -> Na2ZnO2 + H2 ^}\).

Industrial routeReaction
Water gas (syngas)\(\ce{C + H2O ->[1270\,K] CO + H2}\)
Water-gas shift\(\ce{CO + H2O ->[catalyst] CO2 + H2}\)
Steam reforming\(\ce{CH4 + H2O ->[Ni] CO + 3H2}\)
Electrolysis of water\(\ce{2H2O ->[electricity] 2H2 + O2}\)
Purity vs cost. Electrolysis of acidified or alkaline water gives very pure \(\ce{H2}\) but is energy-hungry; the water-gas and reforming routes are cheap and dominate industry, with the shift reaction "tuning out" the \(\ce{CO}\) to boost hydrogen yield.
Section 15-4

Properties of Dihydrogen

\(\ce{H2}\) is a colourless, odourless, tasteless gas — the lightest known — only sparingly soluble in water. Its strong \(\ce{H-H}\) bond (\(436\ \text{kJ mol}^{-1}\)) makes it fairly unreactive at room temperature, but at high temperature or with a catalyst it combines readily.

Reaction withProductEquation
Oxygenwater\(\ce{2H2 + O2 -> 2H2O}\)
Nitrogenammonia\(\ce{N2 + 3H2 ->[Fe] 2NH3}\)
Halogenhydrogen halide\(\ce{H2 + Cl2 -> 2HCl}\)
Active metalionic hydride\(\ce{2Na + H2 -> 2NaH}\)
Unsaturated oilsaturated fat\(\ce{C=C + H2 ->[Ni] C-C}\)
Section 15-5

Hydrides — Three Families

Hydrogen combines with most elements to form hydrides, sorted by bonding into three families. Which forms depends on the partner's electronegativity and position in the table.

TypeFormed withBondingExamplesBehaviour
Ionic (saline)s-block metalscontains \(\ce{H-}\)\(\ce{NaH},\ \ce{CaH2}\)react with water → \(\ce{H2}\)
Covalent (molecular)p-block non-metalsshared pairs\(\ce{CH4},\ \ce{NH3},\ \ce{H2O},\ \ce{HF}\)volatile, low mp
Metallic (interstitial)many d/f-block metalsH in lattice holes\(\ce{LaH2.87},\ \ce{TiH_{1.7}}\)often non-stoichiometric
💧
Ionic hydride + water
\(\ce{NaH + H2O -> NaOH + H2 ^}\)

The hydride ion \(\ce{H-}\) is a powerful base and reducing agent: it snatches a proton from water, liberating dihydrogen. \(\ce{CaH2}\) ("hydrolith") is used as a portable, dry source of \(\ce{H2}\) in the field.

Section 15-6

Water: Structure & Properties

The water molecule is bent, with an \(\ce{H-O-H}\) angle of about \(104.5^\circ\) and two lone pairs on oxygen. Its polarity and extensive hydrogen bonding give water a strikingly high boiling point, high specific heat, and the rare property that its solid floats on its liquid.

O H H 104.5°
Water — bent, polar, with two lone pairs and an angle of 104.5°
PropertyValue / behaviourWhy it matters
Boiling point\(100\,^\circ\text{C}\) (anomalously high)hydrogen bonding
Max. densityat \(4\,^\circ\text{C}\)ice floats, protects aquatic life
Specific heatvery highmoderates climate
Solvent power"universal solvent"dissolves ionic & polar solutes
Section 15-7

Hard Water & Its Removal

Hard water contains dissolved \(\ce{Ca^2+}\) and \(\ce{Mg^2+}\) ions, which form a scum with soap and scale in boilers. Temporary hardness (from bicarbonates) is removed simply by boiling or by Clark's method; permanent hardness (from chlorides and sulphates) needs a chemical or ion-exchange treatment.

TypeCauseRemovalReaction
Temporary\(\ce{Ca(HCO3)2},\ \ce{Mg(HCO3)2}\)boiling / Clark's method\(\ce{Ca(HCO3)2 ->[\Delta] CaCO3 v + H2O + CO2}\)
Temporary(slaked lime)Clark's method\(\ce{Ca(HCO3)2 + Ca(OH)2 -> 2CaCO3 v + 2H2O}\)
Permanent\(\ce{CaCl2},\ \ce{MgSO4}\)washing soda\(\ce{CaCl2 + Na2CO3 -> CaCO3 v + 2NaCl}\)
Permanent(ion exchange)zeolite / resin\(\ce{Na2Z + Ca^2+ -> CaZ + 2Na+}\)
Calgon and resins. Sodium hexametaphosphate (Calgon) "masks" \(\ce{Ca^2+}\) and \(\ce{Mg^2+}\) by forming a soluble complex. Modern synthetic ion-exchange resins go further — a cation resin swaps metal ions for \(\ce{H+}\) and an anion resin swaps acid radicals for \(\ce{OH-}\), giving fully demineralised water.
Section 15-8

Hydrogen Peroxide

Hydrogen peroxide (\(\ce{H2O2}\)) is a pale-blue, syrupy liquid with a non-planar "open-book" structure: an \(\ce{O-O}\) single bond with the two \(\ce{O-H}\) bonds on different planes. Its real interest is its dual redox character — it can both oxidise and reduce, in acidic or basic media.

O O H H O–O single bond; H atoms in different planes
The open-book (skew) structure of H₂O₂
⚗️
Dual redox behaviour
As oxidant: \(\ce{2I- + H2O2 + 2H+ -> I2 + 2H2O}\) · As reductant: \(\ce{2MnO4- + 5H2O2 + 6H+ -> 2Mn^2+ + 5O2 + 8H2O}\)

When peroxide is the oxidant, its oxygen goes from \(-1\) to \(-2\); when it is the reductant, oxygen goes from \(-1\) to \(0\), releasing \(\ce{O2}\). It decomposes slowly, \(\ce{2H2O2 -> 2H2O + O2}\), so it is stored cold in dark, wax-lined bottles.

PreparationReaction / method
Acidifying a peroxide\(\ce{BaO2 + H2SO4 -> BaSO4 v + H2O2}\)
Industrial (anthraquinone)auto-oxidation of 2-ethylanthraquinol
Electrolyticoxidation of acidified sulphate, then hydrolysis
Volume strength. A bottle marked "20 volume" releases 20 mL of \(\ce{O2}\) (at STP) per mL of solution on full decomposition. Convert to grams per litre with \(\text{strength (g/L)} = \dfrac{17}{5.6}\times\text{volume strength}\).
Section 15-9

Heavy Water & Hydrogen as a Fuel

Heavy water (\(\ce{D2O}\)) is water in which both hydrogens are deuterium. It is obtained by the exhaustive electrolysis of ordinary water (the lighter \(\ce{H2O}\) decomposes faster, concentrating \(\ce{D2O}\)) and serves as a moderator in nuclear reactors, slowing neutrons without absorbing them.

Hydrogen is also a clean fuel. It has the highest energy per unit mass of any chemical fuel and burns to give only water. In a hydrogen–oxygen fuel cell the energy of \(\ce{2H2 + O2 -> 2H2O}\) is converted directly to electricity, and the hydrogen economy envisions storing and transporting energy as \(\ce{H2}\) rather than as fossil fuels.

The catch. Hydrogen's promise is offset by storage and production hurdles — it is bulky to store, and most industrial \(\ce{H2}\) still comes from fossil-based reforming that releases \(\ce{CO2}\). "Green" hydrogen from renewable-powered electrolysis is the goal that makes the fuel truly clean.
Worked Examples

Putting It to Work

1 Classify the hydride

Problem. Classify \(\ce{CaH2},\ \ce{NH3}\) and \(\ce{TiH_{1.7}}\) by hydride type.

Solution. Partner element fixes the family — s-metal, p-non-metal, d-metal:

Working
\[ \ce{CaH2}\text{: ionic};\quad \ce{NH3}\text{: covalent};\quad \ce{TiH_{1.7}}\text{: metallic} \]
2 Hydride + water

Problem. Write the balanced reaction when calcium hydride reacts with water.

Solution. Each \(\ce{H-}\) takes a proton from water to give \(\ce{H2}\):

Working
\[ \ce{CaH2 + 2H2O -> Ca(OH)2 + 2H2 ^} \]
3 Removing temporary hardness

Problem. Write the reaction by which boiling removes temporary hardness due to \(\ce{Ca(HCO3)2}\).

Solution. Heat decomposes the bicarbonate to insoluble carbonate:

Working
\[ \ce{Ca(HCO3)2 ->[\Delta] CaCO3 v + H2O + CO2 ^} \]
4 Volume strength → g/L

Problem. Express the strength of a "10 volume" \(\ce{H2O2}\) solution in grams per litre.

Solution. Apply \(\text{strength}=\dfrac{17}{5.6}\times\text{vol. strength}\):

Working
\[ \text{strength}=\frac{17}{5.6}\times10\approx 30.4\ \text{g L}^{-1} \]
5 Oxidant or reductant?

Problem. In \(\ce{2KMnO4 + 5H2O2 + 3H2SO4 -> 2MnSO4 + K2SO4 + 5O2 + 8H2O}\), is \(\ce{H2O2}\) the oxidant or reductant?

Solution. Oxygen in \(\ce{H2O2}\) rises from \(-1\) to \(0\) (loses electrons):

Working
\[ \ce{H2O2}\ \text{is the reducing agent (it reduces }\ce{MnO4-}\text{)} \]
6 Identify the isotope

Problem. An isotope of hydrogen has mass number 3 and is radioactive. Name it and give its symbol and neutron count.

Solution. Mass 3 with \(Z=1\) means 2 neutrons:

Working
\[ \textbf{tritium},\ \ce{^3_1H}\ (\text{T}),\ 2\ \text{neutrons} \]
Review

Chapter Summary

Position

Resembles both alkali metals and halogens; best treated as a unique element.

Isotopes

Protium, deuterium, tritium (radioactive) — same chemistry, very different masses.

Preparation

Lab: \(\ce{Zn + acid}\). Industrial: water gas, shift reaction, steam reforming, electrolysis.

Hydrides

Ionic (s-block), covalent (p-block), metallic/interstitial (d/f-block).

Water

Bent, 104.5°, H-bonded; hardness from \(\ce{Ca^2+}/\ce{Mg^2+}\) — temporary vs permanent.

Peroxide

Open-book structure; both oxidant and reductant; volume strength \(=\tfrac{17}{5.6}\times\) (g/L).

Practice

Problems

For each item, first decide which idea it tests — position, preparation, hydrides, water or peroxide — then apply the relevant rule. Difficulty rises down the list.

  1. Give two ways hydrogen resembles alkali metals and two ways it resembles halogens.
  2. Name the three isotopes of hydrogen and state which is radioactive.
  3. Write the laboratory preparation of dihydrogen from zinc and dilute sulphuric acid.
  4. What is water gas? Write the reaction and the water-gas shift that follows.
  5. Classify as ionic, covalent or metallic: \(\ce{NaH},\ \ce{HCl},\ \ce{PdH_{0.6}}\).
  6. Write the reaction of sodium hydride with water and explain why \(\ce{H-}\) acts as a base.
  7. Why does ice float on water? Relate your answer to hydrogen bonding.
  8. Distinguish temporary and permanent hardness, giving the salt responsible for each.
  9. Describe Clark's method and write the reaction it relies on.
  10. Draw the structure of \(\ce{H2O2}\) and explain why it is called "open-book".
  11. A sample of \(\ce{H2O2}\) is labelled "30 volume". Calculate its strength in g/L.
  12. Explain how heavy water is obtained and why it is used in nuclear reactors.
Tip: the whole chapter hangs on one idea — hydrogen's single electron makes it flexible. Lose it and you get \(\ce{H+}\) (acids, water); gain one and you get \(\ce{H-}\) (ionic hydrides); share it and you get covalent hydrides and water itself. Ask "what is hydrogen's electron doing here?" and most reactions explain themselves.