The Solid State
Order made visible — how atoms stack into lattices, how we count and weigh a unit cell, and how the tiny flaws inside crystals decide colour, conduction and magnetism
- The difference between crystalline and amorphous solids, and why glass is a "pseudo-solid".
- The four classes of crystalline solids — molecular, ionic, covalent and metallic.
- Lattices, unit cells, the seven crystal systems and the 14 Bravais lattices.
- How to count atoms in simple, body-centred and face-centred cubic cells.
- Close packing (hcp/ccp), tetrahedral/octahedral voids, and packing efficiency.
- The density formula, the radius ratio rule, and point defects: Schottky and Frenkel.
Crystalline vs Amorphous Solids
A solid has a fixed shape and volume because its particles are locked in place, vibrating about fixed points. But not all solids are built the same. A crystalline solid has long-range order: its particles repeat in a regular, three-dimensional pattern that extends across the whole crystal. An amorphous solid (from Greek a-morphē, "no form") has only short-range order — orderly in small patches but disordered overall, like a frozen snapshot of a liquid.
| Property | Crystalline | Amorphous |
|---|---|---|
| Order | long-range, regular | short-range only |
| Melting point | sharp, definite | softens over a range |
| Shape on cleaving | clean flat faces | irregular fracture |
| Heat of fusion | definite | not definite |
| Anisotropy | anisotropic | isotropic |
| Nature | true solid | pseudo-solid / supercooled liquid |
| Examples | \(\ce{NaCl}\), diamond, quartz | glass, rubber, plastic |
Classes of Crystalline Solids
Crystalline solids are sorted by the kind of particle at the lattice points and the force holding them together. Four classes cover almost everything, and the binding force predicts every bulk property — hardness, melting point and conductivity.
| Type | Particles | Force | Properties | Example |
|---|---|---|---|---|
| Molecular | molecules | van der Waals / H-bond | soft, low mp, insulator | ice, dry ice \(\ce{CO2}\) |
| Ionic | ions | electrostatic | hard, brittle, high mp | \(\ce{NaCl}\), \(\ce{ZnS}\) |
| Covalent | atoms | covalent network | very hard, very high mp | diamond, \(\ce{SiC}\), quartz |
| Metallic | cations + e⁻ sea | metallic bond | malleable, conducting | \(\ce{Cu}\), \(\ce{Fe}\), \(\ce{Ag}\) |
Lattice, Unit Cell & the Seven Crystal Systems
A crystal lattice is the regular three-dimensional array of points that represents the repeating pattern of a crystal. The smallest repeating block that, stacked in three dimensions, reproduces the whole lattice is the unit cell. A unit cell is defined by three edge lengths \(a,\,b,\,c\) and three angles \(\alpha,\,\beta,\,\gamma\) between them.
By choosing different combinations of edges and angles, only seven distinct shapes are possible — the seven crystal systems. Adding face-, body- and end-centring gives the 14 Bravais lattices.
| System | Edges | Angles | Example |
|---|---|---|---|
| Cubic | \(a=b=c\) | \(\alpha=\beta=\gamma=90^\circ\) | \(\ce{NaCl}\), \(\ce{Cu}\) |
| Tetragonal | \(a=b\ne c\) | \(\alpha=\beta=\gamma=90^\circ\) | white \(\ce{Sn}\), \(\ce{TiO2}\) |
| Orthorhombic | \(a\ne b\ne c\) | \(\alpha=\beta=\gamma=90^\circ\) | rhombic \(\ce{S}\), \(\ce{BaSO4}\) |
| Hexagonal | \(a=b\ne c\) | \(\alpha=\beta=90^\circ,\ \gamma=120^\circ\) | graphite, \(\ce{ZnO}\) |
| Rhombohedral | \(a=b=c\) | \(\alpha=\beta=\gamma\ne90^\circ\) | calcite, \(\ce{HgS}\) |
| Monoclinic | \(a\ne b\ne c\) | \(\alpha=\gamma=90^\circ\ne\beta\) | monoclinic \(\ce{S}\) |
| Triclinic | \(a\ne b\ne c\) | \(\alpha\ne\beta\ne\gamma\ne90^\circ\) | \(\ce{CuSO4.5H2O}\) |
Cubic Unit Cells & Counting Atoms
The three cubic cells dominate the syllabus. To count how many atoms a cell "owns", remember that atoms are shared with neighbouring cells. The share depends on position:
| Position | Shared between | Contribution |
|---|---|---|
| Corner | 8 cells | \(1/8\) |
| Edge | 4 cells | \(1/4\) |
| Face centre | 2 cells | \(1/2\) |
| Body centre | 1 cell | \(1\) |
The corners always supply one whole atom; the body centre adds one more for BCC, and the six face centres add three more for FCC.
| Cell | Atoms (Z) | Coordination no. | \(r\)–\(a\) relation |
|---|---|---|---|
| Simple cubic | 1 | 6 | \(a=2r\) |
| Body-centred | 2 | 8 | \(\sqrt3\,a=4r\) |
| Face-centred (ccp) | 4 | 12 | \(\sqrt2\,a=4r\) |
Close Packing & the Voids Between
To pack spheres as tightly as possible, lay down a hexagonal first layer (A), nest the second layer (B) into its hollows, then choose where the third goes. Stacking ABAB… gives hexagonal close packing (hcp); stacking ABCABC… gives cubic close packing (ccp), which is identical to the face-centred cubic lattice. Both reach a coordination number of 12 and the same packing efficiency.
Wherever spheres meet, empty pockets — voids — remain. A pocket touched by four spheres is a tetrahedral void; one touched by six spheres is an octahedral void. For \(N\) close-packed spheres there are exactly \(N\) octahedral voids and \(2N\) tetrahedral voids. Which voids the smaller ions occupy fixes the structure of an ionic compound.
| Void | Surrounded by | Number (for N spheres) | Limiting radius ratio |
|---|---|---|---|
| Tetrahedral | 4 spheres | \(2N\) | \(0.225\) |
| Octahedral | 6 spheres | \(N\) | \(0.414\) |
Packing Efficiency
Packing efficiency is the fraction of a unit cell's volume actually filled by spheres. It rises as the coordination number rises — close packing wastes the least space.
Substitute the \(r\)–\(a\) relation for each cell. SC gives \(52.4\%\), BCC gives \(68\%\), and ccp/hcp both give \(74\%\) — the densest possible packing of equal spheres.
| Structure | \(Z\) | Packing efficiency | Void space |
|---|---|---|---|
| Simple cubic | 1 | 52.4 % | 47.6 % |
| Body-centred cubic | 2 | 68 % | 32 % |
| ccp / fcc & hcp | 4 (fcc) | 74 % | 26 % |
Density of a Unit Cell
Because a unit cell's mass and volume are both known once we know the structure, a crystal's density links directly to atomic mass and edge length. This single formula lets you find Avogadro's number, the type of cell, or an unknown atomic mass from X-ray data.
\(Z\) = atoms per cell, \(M\) = molar mass (g mol⁻¹), \(a\) = edge length (cm), \(N_A=6.022\times10^{23}\). Keep units consistent: if \(a\) is in cm, \(\rho\) comes out in g cm⁻³.
Radius Ratio & Ionic Solids
For an ionic crystal, the ratio of the cation radius to the anion radius decides which void the cation fits into, and therefore its coordination number. A cation must be just large enough to touch its surrounding anions without rattling — that lower limit is the radius ratio rule.
| \(r_+/r_-\) | Coordination | Geometry | Example |
|---|---|---|---|
| 0.155 – 0.225 | 3 | trigonal planar | \(\ce{B2O3}\) |
| 0.225 – 0.414 | 4 | tetrahedral | \(\ce{ZnS}\) |
| 0.414 – 0.732 | 6 | octahedral | \(\ce{NaCl}\) |
| 0.732 – 1.000 | 8 | cubic | \(\ce{CsCl}\) |
Imperfections & Point Defects
No real crystal is perfect. Above absolute zero, thermodynamics demands some disorder. Point defects are irregularities around a single lattice point. Stoichiometric defects keep the formula intact; non-stoichiometric defects change the ratio of ions.
| Defect | What happens | Effect on density | Favoured when | Example |
|---|---|---|---|---|
| Schottky | equal cation + anion vacancies | decreases | similar ion sizes, high coord. | \(\ce{NaCl}\), \(\ce{KCl}\), \(\ce{CsCl}\) |
| Frenkel | ion shifts to interstitial site | unchanged | large size difference | \(\ce{AgCl}\), \(\ce{ZnS}\), \(\ce{AgBr}\) |
Electrical & Magnetic Properties
The same lattice that fixes a solid's shape also fixes how it carries current and responds to a magnet. Band theory sorts solids by the gap between the filled valence band and the empty conduction band: no gap → conductor, small gap → semiconductor, large gap → insulator.
A pure intrinsic semiconductor like silicon conducts feebly. Doping transforms it: adding a group-15 element (P, As) donates extra electrons to give an n-type semiconductor; adding a group-13 element (B, Al) creates electron "holes" to give a p-type semiconductor. Joining the two builds the p–n junction at the heart of every diode and transistor.
| Magnetic class | Behaviour | Cause | Example |
|---|---|---|---|
| Diamagnetic | weakly repelled | all electrons paired | \(\ce{NaCl}\), \(\ce{H2O}\) |
| Paramagnetic | weakly attracted | unpaired electrons | \(\ce{O2}\), \(\ce{Cu^2+}\) |
| Ferromagnetic | strongly attracted, permanent | aligned domains | \(\ce{Fe}\), \(\ce{Co}\), \(\ce{Ni}\) |
| Antiferromagnetic | no net moment | oppositely aligned spins cancel | \(\ce{MnO}\) |
| Ferrimagnetic | net moment, but weaker | unequal opposite spins | \(\ce{Fe3O4}\) |
Putting It to Work
Problem. How many atoms belong to a face-centred cubic unit cell?
Solution. Add the corner and face-centre contributions:
Problem. An element crystallises in a BCC lattice with atomic radius \(r=125\ \text{pm}\). Find the edge length \(a\).
Solution. For BCC the body diagonal carries four radii, \(\sqrt3\,a=4r\):
Problem. Copper (\(M=63.5\ \text{g mol}^{-1}\)) is FCC with \(a=361\ \text{pm}\). Find its density.
Solution. Use \(\rho=ZM/(a^3N_A)\) with \(Z=4\) and \(a=3.61\times10^{-8}\ \text{cm}\):
Problem. Show that body-centred cubic packing fills \(68\%\) of space.
Solution. With \(Z=2\) and \(r=\sqrt3\,a/4\), substitute into the P.E. formula:
Problem. A ccp lattice contains \(0.5\ \text{mol}\) of spheres. How many octahedral and tetrahedral voids are present?
Solution. Octahedral voids \(=N\), tetrahedral voids \(=2N\):
Problem. In \(\ce{AgCl}\) a small \(\ce{Ag+}\) ion leaves its site and lodges in an interstitial position while no anion moves. Name the defect and state its effect on density.
Solution. An ion displaced to an interstitial — no mass leaves the crystal:
Chapter Summary
Crystalline = long-range order, sharp mp, anisotropic; amorphous = pseudo-solid, isotropic.
Molecular, ionic, covalent, metallic — the binding force sets every bulk property.
Corner \(\tfrac18\), edge \(\tfrac14\), face \(\tfrac12\), body \(1\): SC=1, BCC=2, FCC=4.
SC 52.4 %, BCC 68 %, ccp/hcp 74 %; voids: \(N\) octahedral, \(2N\) tetrahedral.
\(\rho=ZM/(a^3N_A)\) — links structure to mass and edge length.
Schottky lowers density; Frenkel leaves it unchanged; F-centres colour crystals.
Problems
For each item, first decide which idea it tests — structure, packing, density, or defects — then apply the relevant rule. Difficulty rises down the list.
- State three differences between crystalline and amorphous solids.
- Why are amorphous solids described as isotropic while crystals are anisotropic?
- Classify as molecular, ionic, covalent or metallic: dry ice, diamond, \(\ce{MgO}\), brass.
- Calculate the number of atoms in a body-centred cubic unit cell, showing each contribution.
- An element is FCC with edge length \(400\ \text{pm}\). Find the atomic radius.
- Distinguish hexagonal close packing from cubic close packing in terms of stacking and coordination number.
- How many octahedral and tetrahedral voids accompany \(1\ \text{mol}\) of close-packed atoms?
- Derive the packing efficiency of a simple cubic lattice.
- A metal (\(M=56\ \text{g mol}^{-1}\)) is BCC with \(a=287\ \text{pm}\). Calculate its density.
- Using the radius ratio rule, predict the coordination number when \(r_+/r_-=0.52\).
- Explain why a Schottky defect lowers density but a Frenkel defect does not.
- What is an F-centre, and why does it give a crystal colour?