Electronic Devices & Circuits · Lecture 11

Full-Wave Rectifiers

Diodes & Basic Applications

Dr. Mithun Mondal BITS Pilani, Hyderabad Campus
  • Circuit Configuration (Figure a)

    • Grounded center tap on secondary winding

    • Equivalent to two half-wave rectifiers

    • Each rectifier receives half the secondary voltage

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  • Operation

    • Diode D1: Conducts on positive half-cycle

    • Diode D2: Conducts on negative half-cycle

    • Rectified load current flows during both half-cycles

  • Positive Half-Cycle (Figure b)

    • D1 is forward biased

    • Positive load voltage across load resistor

  • Negative Half-Cycle (Figure c)

    • D2 is forward biased

    • Positive load voltage

  • Output Characteristics

    • Same load voltage polarity during both half-cycles

    • Load current direction remains constant

    • Converts AC input to pulsating DC output (Figure d)

DC or Average Value

  • \[V_{\mathrm{dc}} = \frac{2 V_p}{\pi}\]
    Full-wave rectifier average value:
  • \[V_{\mathrm{dc}} \approx 0.636 V_p\]
    Approximate form:
  • Example:

    • Peak voltage, \(V_p = 100\text{ V}\)

    • DC voltage: \(V_{\mathrm{dc}} \approx 63.6\text{ V}\)

Output Frequency

  • Half-wave rectifier: Output frequency = Input frequency

  • Full-wave rectifier: Output frequency is double the input frequency

  • Input frequency: \(f_{\text{in}} = 60\text{ Hz}\)

  • \[T_{\text{in}} = \frac{1}{f_{\text{in}}} = \frac{1}{60\text{ Hz}} = 16.7\text{ ms}\]
    Input period:
  • \[T_{\text{out}} = 0.5 \times T_{\text{in}} = 8.33\text{ ms}\]
    Output period:
  • \[f_{\text{out}} = \frac{1}{T_{\text{out}}} = 120\text{ Hz}\]
    Output frequency:
  • \[f_{\text{out}} = 2 f_{\text{in}}\]
    General relation:

Second Approximation

  • Full-wave rectifier \(\approx\) Two back-to-back half-wave rectifiers

  • \[V_{\text{peak,approx}} = V_p - 0.7\text{ V}\]
    Approximate peak output voltage:
  • Example to illustrate the idea.

SECTION 01

LAB example of full-wave rectifier

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\[\begin{aligned} V_m & = \sqrt{2} \cdot V_{rms} = \sqrt{2} \times 120 = 170 \mathrm{~V} \\ V_{p(2)} &=\frac{V_{p(1)}}{N_1 / N_2}=\frac{170 \mathrm{~V}}{10}=17 \mathrm{~V}\\ V_{p(\mathrm{in})} & =0.5(17 \mathrm{~V})=8.5 \mathrm{~V} \\ V_{p(\text { out })} & =8.5 \mathrm{~V}\\ V_{p(\text { out })} & =8.5 \mathrm{~V}-0.7 \mathrm{~V}=7.8 \mathrm{~V} \end{aligned}\]
Bridge Rectifier
  • Bridge Rectifier Circuit

    • Produces a full-wave output voltage

    • Diodes D1 and D2 conduct on positive half-cycle

    • Diodes D3 and D4 conduct on negative half-cycle

    • Rectified load current flows during both half-cycles

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  • Positive Half-Cycle

    • D1 and D2 are forward biased

    • Produces positive load voltage

    • Visualize D2 shorted: Circuit resembles half-wave rectifier

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  • Negative Half-Cycle

    • D3 and D4 are forward biased

    • Produces positive load voltage

    • Visualize D3 shorted: Circuit resembles half-wave rectifier

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  • Output Characteristics

    • Same load voltage polarity during both half-cycles

    • Load current direction remains constant

    • Converts AC input to pulsating DC output

    • Advantage: Uses entire secondary voltage

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  • Average Value:

    • 63.6% of peak value

    • Example: \(V_{\mathrm{dc}} = 63.6\text{ V}\) for \(V_p = 100\text{ V}\)

  • \[V_{\mathrm{dc}} = \frac{2 V_p}{\pi}\]
  • Output Frequency:

    • Example: \(f_{\mathrm{out}} = 120\text{ Hz}\) for \(f_{\mathrm{in}} = 60\text{ Hz}\)

  • \[f_{\mathrm{out}} = 2 f_{\mathrm{in}}\]
  • Advantage:

    • Uses entire secondary voltage

    • Twice as much peak voltage and DC voltage compared to center-tap full-wave rectifier

  • Terminology:

    • Full-wave rectifier may refer to:

      • Conventional full-wave rectifier

      • Two-diode full-wave rectifier

      • Center-tapped full-wave rectifier

  • Peak Output Voltage:

    • Subtract 1.4 V (two diode drops) for accurate peak load voltage

  • \[V_{p(\text{out})} = V_{p(\text{in})} - 1.4\text{ V}\]
  • Summary Table:

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