Part 3 · Chapter 11

Magnetostatic Fields

Moving charge makes magnetism. With electrostatics behind us, the whole structure reappears in a magnetic key: Biot–Savart plays the role of Coulomb, Ampère's law mirrors Gauss's, and a current-carrying wire wraps space in circular field lines.

Electromagnetic Field Theory Prof. Mithun Mondal Reading time ≈ 55 min
i What you'll learn
  • Why moving charge (current) is the source of the magnetic field.
  • The Biot–Savart law — the magnetic analogue of Coulomb's law.
  • Ampère's circuital law and how to use an Amperian loop for symmetric problems.
  • The fields of an infinite wire, coaxial cable, current sheet, solenoid and toroid.
  • Magnetic flux and Gauss's law for magnetism, \(\nabla\cdot\vec{B}=0\).
  • The point form of Ampère's law, \(\nabla\times\vec{H}=\vec{J}\).
Section 11-1

Magnetism from Moving Charge

A stationary charge makes only an electric field. Set it moving — a current — and a new field appears around it: the magnetic field. We describe it with two vectors, just as electrostatics used \(\vec{E}\) and \(\vec{D}\). The magnetic field intensity \(\vec{H}\) (A/m) depends only on the currents; the magnetic flux density \(\vec{B}\) (tesla) includes the medium:

B and H in free space
\[ \vec{B} = \mu_0\vec{H}, \qquad \mu_0 = 4\pi\times10^{-7}\ \text{H/m} \]

The parallel with electrostatics is exact: \(\vec{H}\) mirrors \(\vec{D}\) (source-only), \(\vec{B}\) mirrors \(\vec{E}\) (medium-dependent), and \(\mu_0\) mirrors \(\varepsilon_0\). Keeping this dictionary in mind makes the whole of Part 3 feel like familiar territory seen in a mirror.

Section 11-2

The Biot–Savart Law

The Biot–Savart law is the magnetic Coulomb's law: it gives the field \(d\vec{H}\) produced by a small current element \(I\,d\vec{l}\). Like Coulomb's law it falls off as \(1/R^2\), but a cross product makes the field circle the current rather than point away from it:

Biot–Savart law
\[ d\vec{H} = \frac{I\,d\vec{l}\times\hat{a}_R}{4\pi R^2} \]
I dl â_R dH (into page)
Biot–Savart: dH is perpendicular to both the current element and âR

The cross product encodes the right-hand rule: point the thumb along the current and the fingers curl in the direction of \(\vec{H}\). Integrating Biot–Savart along a whole circuit gives the total field — the magnetic counterpart of summing Coulomb contributions.

Section 11-3

Ampère's Circuital Law

Just as Gauss's law shortcut the Coulomb integral, Ampère's circuital law shortcuts Biot–Savart when symmetry allows. It states that the line integral of \(\vec{H}\) around any closed loop equals the total current threading that loop:

Ampère's circuital law (integral form)
\[ \oint_L \vec{H}\cdot d\vec{l} = I_{\text{enc}} \]
🔑
The magnetic mirror of Gauss's law
\[ \oint_L \vec{H}\cdot d\vec{l} = I_{\text{enc}} \]

Choose an Amperian loop on which \(\vec{H}\) is constant and tangential, and the integral becomes \(H\times(\text{loop length})\). Where Gauss used a surface enclosing charge, Ampère uses a loop enclosing current — the same symmetry shortcut, one dimension down.

Applying Stokes' theorem (Chapter 3) to the left side converts it to the point form — Ampère's law as a local statement, and the magnetostatic member of Maxwell's equations:

Ampère's law (point form)
\[ \nabla\times\vec{H} = \vec{J} \]
The deep contrast with statics. A static electric field is irrotational (\(\nabla\times\vec{E}=0\)); the magnetic field is the opposite — it curls around its source current (\(\nabla\times\vec{H}=\vec{J}\)). Electric field lines start and stop on charges; magnetic field lines close on themselves. This curl-versus-divergence distinction is the heart of why the two fields behave so differently.
Section 11-4

The Infinite Wire & Coax

The cleanest application: an infinite straight wire carrying current \(I\). By symmetry \(\vec{H}\) circles the wire with constant magnitude on any circle of radius \(\rho\). An Amperian circle of circumference \(2\pi\rho\) gives the field in one line:

Field of an infinite wire
\[ H\,(2\pi\rho) = I \;\Rightarrow\; \vec{H} = \frac{I}{2\pi\rho}\,\hat{a}_\phi \]
I (out) H circles the wire
Circular H field around a wire; magnitude falls as 1/ρ (mirror of the line charge)

Notice the \(1/\rho\) falloff — identical in form to the infinite line charge of Chapter 4, but now the field circles rather than radiates. For a coaxial cable, nested Amperian circles give a field that rises inside the inner conductor, falls as \(1/\rho\) between conductors, and vanishes outside — the magnetic version of coaxial shielding.

Section 11-5

Solenoid & Toroid

Winding wire into coils concentrates the field. Inside a long solenoid of \(n\) turns per metre, the field is uniform and axial; outside it is nearly zero. A rectangular Amperian loop gives:

Solenoid (interior field)
\[ H = nI \qquad (n = N/L \text{ turns per metre}) \]

Bending the solenoid into a doughnut makes a toroid of \(N\) total turns, which traps the field entirely inside the core. A circular Amperian loop of radius \(\rho\) through the core gives:

Toroid (field in the core)
\[ H = \frac{NI}{2\pi\rho} \]

Solenoids and toroids are the workhorses of inductors and transformers — the field-concentrating structures whose stored magnetic energy we quantify in Chapter 14, and which sit at the core of the pulsed-power magnetics in real high-voltage systems.

Section 11-6

Magnetic Flux & ∇·B

Magnetic flux \(\Psi_m\) is the amount of \(\vec{B}\) crossing a surface — the magnetic counterpart of electric flux, measured in webers:

Magnetic flux
\[ \Psi_m = \int_S \vec{B}\cdot d\vec{S} \quad (\text{Wb}) \]

Here the mirror with electrostatics finally breaks, in the most important way. There are no magnetic charges — no isolated north or south poles — so magnetic field lines never start or stop; they always close into loops. The net flux out of any closed surface is therefore exactly zero. This is Gauss's law for magnetism, Maxwell's second equation:

🔑
No magnetic monopoles
\[ \oint_S \vec{B}\cdot d\vec{S} = 0, \qquad \nabla\cdot\vec{B} = 0 \]

Where \(\nabla\cdot\vec{D}=\rho_v\) (electric charge is a source), \(\nabla\cdot\vec{B}=0\) (no magnetic charge exists). The magnetic field is purely solenoidal — exactly the field type defined back in Chapter 3.

Section 11-7

Worked Examples

1 Field of a wire

Problem. A long wire carries \(10\ \text{A}\). Find \(\vec{H}\) and \(\vec{B}\) at \(\rho=5\ \text{cm}\).

Solution. Use \(H=I/2\pi\rho\), then \(B=\mu_0 H\):

Working
\[ H = \frac{10}{2\pi(0.05)} = 31.8\ \text{A/m}, \qquad B = \mu_0 H = 40\ \mu\text{T} \]
2 Field on a wire's axis (finite)

Problem. Find \(\vec{H}\) at the centre of a circular loop of radius \(a\) carrying current \(I\).

Solution. Biot–Savart with every element at distance \(a\), perpendicular to the radius:

Working
\[ H = \frac{I}{4\pi a^2}\oint dl = \frac{I(2\pi a)}{4\pi a^2} = \frac{I}{2a} \]
3 Solenoid field

Problem. A solenoid has \(500\) turns over \(25\ \text{cm}\) and carries \(2\ \text{A}\). Find \(B\) inside.

Solution. Use \(H=nI\) with \(n=N/L\):

Working
\[ n = \frac{500}{0.25} = 2000\ \text{/m}, \quad B = \mu_0 nI = \mu_0 (2000)(2) = 5.03\ \text{mT} \]
4 Toroid field

Problem. A toroid has \(N=1000\) turns, mean radius \(10\ \text{cm}\), and \(I=0.5\ \text{A}\). Find \(H\) in the core.

Solution. Use \(H=NI/2\pi\rho\):

Working
\[ H = \frac{1000(0.5)}{2\pi(0.10)} = 796\ \text{A/m} \]
5 Coaxial cable, inside the inner conductor

Problem. An inner conductor of radius \(a\) carries uniformly distributed current \(I\). Find \(\vec{H}\) for \(\rho

Solution. The Amperian loop encloses only a fraction of the current:

Working
\[ H(2\pi\rho) = I\frac{\rho^2}{a^2} \;\Rightarrow\; \vec{H} = \frac{I\rho}{2\pi a^2}\,\hat{a}_\phi \]

Inside the conductor \(H\) grows linearly with \(\rho\) — the magnetic twin of the uniformly charged sphere.

6 Current from a field's curl

Problem. Given \(\vec{H} = 2y\,\hat{a}_x + 3x\,\hat{a}_y\ \text{A/m}\), find the current density \(\vec{J}\).

Solution. Apply \(\vec{J}=\nabla\times\vec{H}\):

Working
\[ \vec{J} = \left(\frac{\partial(3x)}{\partial x} - \frac{\partial(2y)}{\partial y}\right)\hat{a}_z = (3-2)\hat{a}_z = \hat{a}_z\ \text{A/m}^2 \]
Review

Chapter Summary

Sources

Moving charge (current) makes \(\vec{H}\); \(\vec{B}=\mu_0\vec{H}\); \(\mu_0\) mirrors \(\varepsilon_0\).

Biot–Savart

\(d\vec{H}=\dfrac{I\,d\vec{l}\times\hat{a}_R}{4\pi R^2}\); the magnetic Coulomb's law, field circles current.

Ampère's law

\(\oint\vec{H}\cdot d\vec{l}=I_{\text{enc}}\); point form \(\nabla\times\vec{H}=\vec{J}\).

Standard fields

Wire \(I/2\pi\rho\); solenoid \(nI\); toroid \(NI/2\pi\rho\); loop centre \(I/2a\).

Flux

\(\Psi_m=\int\vec{B}\cdot d\vec{S}\) in webers; field lines always close.

No monopoles

\(\nabla\cdot\vec{B}=0\) — Maxwell's second equation; \(\vec{B}\) is solenoidal.

Practice

Problems

For each item, decide whether Ampère's law (high symmetry) or Biot–Savart (finite geometry) is the right tool, then apply it. Difficulty rises down the list.

  1. A wire carries \(25\ \text{A}\). Find \(\vec{H}\) at \(\rho=10\ \text{cm}\).
  2. Find \(\vec{B}\) at the centre of a \(20\)-turn circular coil of radius \(4\ \text{cm}\) carrying \(3\ \text{A}\).
  3. A solenoid has \(800\) turns over \(40\ \text{cm}\) and carries \(1.5\ \text{A}\). Find \(B\) inside.
  4. A toroid (\(N=600\), mean radius \(8\ \text{cm}\)) carries \(2\ \text{A}\). Find \(H\) in the core.
  5. An infinite sheet in the \(z=0\) plane carries surface current \(\vec{K}=K\,\hat{a}_x\). Find \(\vec{H}\) above and below.
  6. For a coaxial cable, find \(\vec{H}\) in all four regions (inside inner, between, inside outer, beyond).
  7. Use Biot–Savart to find \(\vec{H}\) on the axis of a circular loop at height \(z\) above its centre.
  8. Two parallel wires a distance \(d\) apart carry currents \(I\) in the same direction. Find \(\vec{H}\) midway between them.
  9. Given \(\vec{H} = \rho^2\,\hat{a}_\phi\ \text{A/m}\), find \(\vec{J}\) using the cylindrical curl.
  10. Verify that the wire field \(\vec{H}=(I/2\pi\rho)\hat{a}_\phi\) satisfies \(\nabla\cdot\vec{B}=0\).
  11. Show that the field outside an ideal solenoid is zero using an Amperian loop straddling the winding.
  12. Contrast the field of an infinite line charge with that of an infinite line current: same falloff, different direction. Explain the geometric reason.
Tip: the magnetic toolkit mirrors the electric one almost line for line — Biot–Savart for Coulomb, Ampère for Gauss, \(\vec{H}\) for \(\vec{D}\). When you meet a magnetostatics problem, ask the same question you asked in Part 2: is there enough symmetry to draw a loop on which \(\vec{H}\) is constant and tangential? If yes, Ampère gives the answer in three lines; if not, fall back on the Biot–Savart integral. The one place the mirror cracks — \(\nabla\cdot\vec{B}=0\) instead of \(\rho_v\) — is worth remembering: there is no magnetic charge.