Definition: A closed path through which magnetic flux flows.
Key Components:
Magnetic core (iron, steel, ferrite)
Coil/winding carrying current
Air gaps (if any)
Applications:
Transformers
Electric motors & generators
Relays & solenoids
Inductors
Definition: Total number of magnetic field lines passing through a surface.
Mathematical Expression \[\Phi = B \cdot A \cdot \cos\theta\]
Where:
\(\Phi\) = Magnetic flux (Wb)
\(B\) = Flux density (T or Wb/m 2)
\(A\) = Cross-sectional area (m 2)
\(\theta\) = Angle between \(\vec{B}\) and normal
Unit: Weber (Wb)
Definition: Magnetic flux per unit area perpendicular to the field.
Formula \[B = \frac{\Phi}{A}\]
Physical Meaning:
Measures “concentration” of flux
Higher \(B\) \(\Rightarrow\) stronger field in region
Also called magnetic induction
Units:
SI: Tesla (T) = Wb/m2
CGS: Gauss (G), where \(1\,\text{T} = 10^4\,\text{G}\)
Definition: Measure of magnetizing force that creates the magnetic field.
From Ampère’s Law \[\oint \vec{H} \cdot d\vec{l} = NI\] For uniform field in mean path \(l\): \[H = \frac{NI}{l}\]
Where:
\(H\) = Field intensity (A/m or At/m)
\(N\) = Number of turns
\(I\) = Current (A)
\(l\) = Mean path length (m)
Definition: The “driving force” that establishes magnetic flux in a circuit.
MMF Formula \[\mathcal{F} = NI\]
Analogy with Electric Circuits:
| Electric | Magnetic |
|---|---|
| EMF \((V)\) | MMF \((\mathcal{F})\) |
Unit: Ampere-turns (At)
Note Think of MMF as the “magnetic pressure” pushing flux through the circuit.
Definition: Opposition offered by a magnetic circuit to the flow of flux.
Reluctance Formula \[\mathcal{R} = \frac{l}{\mu_0 \mu_r A} = \frac{l}{\mu A}\]
Where:
\(l\) = Length of magnetic path (m)
\(A\) = Cross-sectional area (m 2)
\(\mu_0 = 4\pi \times 10^{-7}\) H/m
\(\mu_r\) = Relative permeability
Unit: At/Wb or H−1
Analogy:
Higher \(\mu_r\) \(\Rightarrow\) Lower \(\mathcal{R}\)
Definition: Measure of a material’s ability to support magnetic flux.
Relationship \[B = \mu H = \mu_0 \mu_r H\]
Types:
\(\mu_0\) = Permeability of free space
\(= 4\pi \times 10^{-7}\) H/m
\(\mu_r\) = Relative permeability (dimensionless)
\(\mu = \mu_0 \mu_r\) = Absolute permeability
| Material | \(\mu_r\) |
|---|---|
| Air/Vacuum | 1 |
| Soft Iron | 2000–8000 |
| Silicon Steel | 5000–10000 |
| Cast Iron | 100–300 |
| Electric | Magnetic | Relation |
|---|---|---|
| EMF (\(V\)) | MMF (\(\mathcal{F} = NI\)) | Driving force |
| Current (\(I\)) | Flux (\(\Phi\)) | Flow quantity |
| Resistance (\(R\)) | Reluctance (\(\mathcal{R}\)) | Opposition |
| Quantity | Electric | Magnetic | Unit (Mag) |
|---|---|---|---|
| Driving Force | EMF (\(V\)) | MMF (\(\mathcal{F}=NI\)) | At |
| Response | Current (\(I\)) | Flux (\(\Phi\)) | Wb |
| Opposition | Resistance (\(R\)) | Reluctance (\(\mathcal{R}\)) | At/Wb |
| Intensity | Current density (\(J\)) | Flux density (\(B\)) | T |
| Field | Electric field (\(E\)) | Field intensity (\(H\)) | At/m |
| Material property | Conductivity (\(\sigma\)) | Permeability (\(\mu\)) | H/m |
| Ohm’s Law | \(V = IR\) | \(\mathcal{F} = \Phi\mathcal{R}\) | – |
Important Note Unlike electric current, magnetic flux does not actually “flow” — it is a static field pattern. The analogy is for calculation convenience only!
Key Points:
Same flux \(\Phi\) through all sections
MMF drops add up
Series Reluctance \[\mathcal{R}_{eq} = \mathcal{R}_1 + \mathcal{R}_2 + \mathcal{R}_3 + \cdots\]
MMF Equation \[\mathcal{F} = \Phi(\mathcal{R}_1 + \mathcal{R}_2 + \cdots)\] \[NI = H_1 l_1 + H_2 l_2 + \cdots\]
Key Points:
Flux divides: \(\Phi = \Phi_1 + \Phi_2\)
Same MMF across parallel paths
Parallel Reluctance \[\frac{1}{\mathcal{R}_{eq}} = \frac{1}{\mathcal{R}_1} + \frac{1}{\mathcal{R}_2}\]
For Two Parallel Paths \[\mathcal{R}_{eq} = \frac{\mathcal{R}_1 \cdot \mathcal{R}_2}{\mathcal{R}_1 + \mathcal{R}_2}\]
Why Air Gap Matters:
\(\mu_r\) of air \(= 1\) (vs. iron \(\approx\) 5000)
Air gap has very high reluctance
Small gap \(\Rightarrow\) large MMF drop
Air Gap Reluctance \[\mathcal{R}_g = \frac{l_g}{\mu_0 A_g}\]
Fringing Effect:
Flux spreads out at air gap
Effective area increases
Often neglected for small gaps
Fringing Factor (\(k_f\)):
Flux spreads beyond core area
Effective gap area \(>\) core area
Rule of Thumb For small gaps, add \(l_g\) to each linear dimension of the gap area.
Empirical Correction For rectangular core (\(a \times b\)): \[A_{eff} = (a + l_g)(b + l_g)\]
Fringing factor: \[k_f = \frac{A_{eff}}{A_{core}} = \frac{(a+l_g)(b+l_g)}{ab}\]
Corrected Gap Reluctance: \[\mathcal{R}_g = \frac{l_g}{\mu_0 A_{eff}} = \frac{l_g}{\mu_0 k_f A}\]
Total Reluctance: \[\mathcal{R}_{total} = \mathcal{R}_{core} + \mathcal{R}_{gap}\] \[\mathcal{R}_{total} = \frac{l_c}{\mu_0 \mu_r A_c} + \frac{l_g}{\mu_0 A_g}\]
Total MMF Required: \[NI = \Phi \cdot \mathcal{R}_{total}\] \[NI = H_c l_c + H_g l_g\]
Since \(B_g = \mu_0 H_g\): \[H_g = \frac{B_g}{\mu_0} = \frac{B}{\mu_0}\]
(Assuming no fringing: \(B_g = B_c = B\))
Typical Values For a circuit with:
\(l_c = 0.5\) m (core)
\(l_g = 1\) mm (gap)
\(\mu_r = 5000\)
Ratio of reluctances: \[\frac{\mathcal{R}_g}{\mathcal{R}_c} = \frac{l_g \cdot \mu_r}{l_c}\] \[= \frac{0.001 \times 5000}{0.5} = 10\]
A 1 mm gap has 10\(\times\) the reluctance of 0.5 m of iron!
Definitions:
Useful flux (\(\Phi_u\)): Flux linking both coils or passing through intended path
Leakage flux (\(\Phi_l\)): Flux that takes path through air
Total Flux \[\Phi_{total} = \Phi_u + \Phi_l\]
Leakage Factor (\(\lambda\)) \[\lambda = \frac{\Phi_{total}}{\Phi_u} = \frac{\Phi_u + \Phi_l}{\Phi_u}\] \[\lambda = 1 + \frac{\Phi_l}{\Phi_u} > 1\]
Typical values: \(\lambda = 1.1\) to \(1.25\)
Why Leakage Matters:
Reduces useful flux available
Lowers transformer/machine efficiency
Causes voltage drops in transformers
Affects coupling between windings
Design Consideration MMF required at source: \[\mathcal{F} = \Phi_u \cdot \mathcal{R}_{core} \cdot \lambda\]
Or accounting for leakage: \[NI = \lambda \cdot \Phi_u \cdot \mathcal{R}\]
Minimizing Leakage:
Use high-permeability core
Minimize air gaps
Place windings close together
Use interleaved windings
Proper core geometry design
Leakage Coefficient \[\sigma = 1 - \frac{1}{\lambda} = \frac{\Phi_l}{\Phi_{total}}\] Represents fraction of flux that leaks.
Machines designed to operate at knee for efficiency.
Three Regions:
1. Linear Region:
\(B \propto H\) (constant \(\mu\))
Domains align gradually
2. Knee Region:
Transition zone
\(\mu\) starts decreasing
3. Saturation Region:
All domains aligned
\(B\) increases very slowly
\(\mu \rightarrow \mu_0\)
Key Parameters:
Retentivity (\(B_r\)):
Residual flux when \(H = 0\)
Material “remembers” magnetization
Coercivity (\(H_c\)):
\(H\) needed to demagnetize
Reverse field to make \(B = 0\)
Loop Area = Energy Loss
Dissipated as heat per cycle
Hysteresis loss \(\propto\) frequency
Energy lost per cycle = Area of hysteresis loop
Steinmetz Equation \[P_h = \eta \cdot B_{max}^n \cdot f \cdot V\]
Where:
\(P_h\) = Hysteresis loss (W)
\(\eta\) = Steinmetz coefficient
\(B_{max}\) = Maximum flux density (T)
\(n\) = Steinmetz exponent ( \(\approx 1.6\)–\(2.0\))
\(f\) = Frequency (Hz)
\(V\) = Volume of core (m 3)
What are Eddy Currents?
Circulating currents induced in conductor
Caused by changing magnetic flux
Follow Lenz’s Law (oppose change)
Effects:
Power loss (\(I^2R\) heating)
Useful in induction heating
Useful in electromagnetic braking
Eddy Current Loss \[P_e = K_e \cdot B_{max}^2 \cdot f^2 \cdot t^2 \cdot V\] where \(t\) = thickness of lamination
Laminations oriented parallel to flux direction.
Why Laminations Work:
Core divided into thin sheets
Each sheet insulated (varnish/oxide)
Eddy current paths broken
Smaller loops \(\Rightarrow\) higher resistance
Key Points:
\(P_e \propto t^2\) (thickness squared)
Thinner laminations = less loss
Typical: 0.35–0.5 mm thick
Used in transformers, motors
Separation Method: \[\frac{P_{core}}{f} = k_h B_{max}^n + k_e B_{max}^2 f \cdot t^2\] Plot \(\frac{P_{core}}{f}\) vs \(f\) \(\Rightarrow\) straight line
Total Core Loss \[P_{core} = P_h + P_e\] \[P_{core} = k_h B_{max}^n f + k_e B_{max}^2 f^2 t^2\]
Key Observations:
At low frequency: \(P_h\) dominates
At high frequency: \(P_e\) dominates
Crossover depends on lamination thickness
To Reduce Hysteresis Loss:
Use soft magnetic materials
Choose materials with narrow B-H loop
Silicon steel (3–4% Si) preferred
Grain-oriented steel for transformers
To Reduce Eddy Current Loss:
Use laminated cores
Thinner laminations for higher frequency
Add silicon to increase resistivity
Use ferrites at very high frequencies
Typical Lamination Thickness
| Application | Thickness |
|---|---|
| Power transformers | 0.35–0.5 mm |
| (50/60 Hz) | |
| Small motors | 0.35–0.65 mm |
| High-speed motors | 0.2–0.35 mm |
| Aircraft (400 Hz) | 0.1–0.2 mm |
| High frequency | Ferrite cores |
| (\(>\) 10 kHz) | (no laminations) |
Thinner = less eddy loss but higher cost
For Electrical Machines: Ferromagnetic materials are essential!
High permeability concentrates flux
Enables strong magnetic fields with less current
Soft Magnetic Materials Properties:
Easy to magnetize/demagnetize
Low coercivity (\(H_c\))
Narrow hysteresis loop
Low hysteresis loss
Examples:
Silicon steel, soft iron, permalloy
Applications:
Transformer cores, motor cores, electromagnets
Hard Magnetic Materials Properties:
Difficult to demagnetize
High coercivity (\(H_c\))
Wide hysteresis loop
High retentivity (\(B_r\))
Examples:
Alnico, ferrites, NdFeB, SmCo
Applications:
Permanent magnets, speakers, hard drives
A magnetic circuit has a mean length of 50 cm and cross-sectional area of 4 cm2. It includes an air gap of 1 mm. The core has \(\mu_r = 2000\). Find the current required in a 500-turn coil to produce a flux of 0.4 mWb.
Given: \(l_c = 0.5 - 0.001 = 0.499\) m, \(l_g = 0.001\) m, \(A = 4 \times 10^{-4}\) m 2
\(\mu_r = 2000\), \(N = 500\), \(\Phi = 0.4 \times 10^{-3}\) Wb
Solution: \[\begin{aligned} \mathcal{R}_{core} &= \frac{l_c}{\mu_0 \mu_r A} = \frac{0.499}{4\pi \times 10^{-7} \times 2000 \times 4 \times 10^{-4}} = 4.97 \times 10^5 \text{ At/Wb}\\[0.2cm] \mathcal{R}_{gap} &= \frac{l_g}{\mu_0 A} = \frac{0.001}{4\pi \times 10^{-7} \times 4 \times 10^{-4}} = 1.99 \times 10^6 \text{ At/Wb}\\[0.2cm] \mathcal{R}_{total} &= 4.97 \times 10^5 + 1.99 \times 10^6 = 2.49 \times 10^6 \text{ At/Wb}\\[0.2cm] NI &= \Phi \times \mathcal{R}_{total} = 0.4 \times 10^{-3} \times 2.49 \times 10^6 = 996 \text{ At}\\[0.2cm] I &= \frac{996}{500} = \boxed{1.99 \text{ A}} \end{aligned}\]
A ring-shaped iron core has a mean circumference of 80 cm and a cross-sectional area of 5 cm 2. It has two air gaps, each 1.5 mm wide. A coil of 600 turns is wound on the core. The relative permeability of iron is 1500. Neglecting leakage and fringing, calculate:
The total reluctance of the magnetic circuit
The current required to produce a flux of 0.5 mWb
The flux density in the core and air gap
Hints:
Core length \(l_c = 0.8 - 2(0.0015) = 0.797\) m
Two air gaps in series: \(\mathcal{R}_{gap,total} = 2\mathcal{R}_{gap}\)
Use \(\Phi = \mathcal{F}/\mathcal{R}_{total}\) to find current
Answers: (a) \(5.84 \times 10^6\) At/Wb (b) 4.87 A (c) 1 T
| Quantity | Formula | Unit |
|---|---|---|
| Magnetic Flux | \(\Phi = BA\) | Wb |
| Flux Density | \(B = \mu H = \mu_0 \mu_r H\) | T |
| Field Intensity | \(H = \dfrac{NI}{l}\) | A/m |
| MMF | \(\mathcal{F} = NI\) | At |
| Reluctance | \(\mathcal{R} = \dfrac{l}{\mu_0 \mu_r A}\) | At/Wb |
| Ohm’s Law (Mag) | \(\Phi = \dfrac{\mathcal{F}}{\mathcal{R}} = \dfrac{NI}{\mathcal{R}}\) | – |
| Series Reluctance | \(\mathcal{R}_{eq} = \mathcal{R}_1 + \mathcal{R}_2 + \cdots\) | At/Wb |
| Parallel Reluctance | \(\dfrac{1}{\mathcal{R}_{eq}} = \dfrac{1}{\mathcal{R}_1} + \dfrac{1}{\mathcal{R}_2}\) | At/Wb |
Magnetic circuits are analogous to electric circuits — MMF drives flux through reluctance.
Permeability determines how easily a material supports magnetic flux.
Air gaps dramatically increase reluctance — even small gaps dominate the circuit.
B-H curve shows nonlinear behavior; saturation limits maximum flux density.
Hysteresis loss occurs due to domain realignment; minimized using soft magnetic materials.
Eddy current loss reduced by using laminated cores.
Core losses = Hysteresis loss + Eddy current loss (important for efficiency).