Electrical Machines · Synchronous Machines

Synchronous Motor Under Load: Constant Excitation Impact

Dr. Mithun Mondal BITS Pilani, Hyderabad Campus Electrical Machines

Demonstrative Video

SECTION 01

Effect of Increased Load with Constant Excitation

Keep excitation constant and vary the load. \(R_a << X_s\), hence phase angle between \(E_R\) and \(I_a\), i.e. \(\theta = 90^{\circ}\)

  • At light-load:

    • \(\alpha_1\) small \(\Rightarrow\) \(E_{R1}\) small \(\Rightarrow\) \(I_{a1}\) small

    • \(\phi_1\) small \(\Rightarrow\) \(\cos \phi_1\) large

  • Load increased:

    • motor must develop more \(T\) by drawing more \(I_a\)

    • unlike dc motor, syn motor cannot \(I_a \uparrow\) by \(N \downarrow\) and hence \(E_b\) because both are constants

    • What happens?

      • rotor falls back in phase i.e. \(\alpha_2 \uparrow\)

      • \(E_R\) increased considerably

      • result \(I_{a} \uparrow \Rightarrow T \uparrow\)

      • \(\phi \uparrow \rightarrow \cos\phi \downarrow\)

    • \((I_a \uparrow) >> (\cos\phi \downarrow) \Rightarrow T \uparrow\)

Normal ExcitationComparatively much greater increase inthan in

normal excitation
Normal Excitation
Comparatively much greater increase in \(I_a\) than in \(\phi\)

Small loadsmalllagsby\(\phi_1 \uparrow\)poor pf
    • Small load \(\Rightarrow\) small \(\alpha_1\) \(\Rightarrow\) \(I_{a1}\) lags \(V\) by \(\phi_1 \uparrow\) \(\Rightarrow\) poor pf

    • Unlike normal excitation, \(I_a \uparrow \uparrow\) for developing same power because of poor pf

    • Load \(\uparrow \Rightarrow E_R \uparrow \Rightarrow I_a \uparrow \Rightarrow \phi \downarrow \Rightarrow \cos\phi \uparrow\)

    • Both \(I_a \uparrow\) and \(\cos\phi \uparrow\) \(\Rightarrow\) \(P_d \uparrow\) to meet the load

    • Change in pf is more than the change in \(I_a\)

under excitation
Under Excitation
Over Excitation
    • Light load \(\Rightarrow \alpha_1\) small but \(I_{a1} \uparrow \uparrow\) and leads \(V\) by larger \(\phi_1\)

    • Like under-excited more load, pf improves and approaches unity

    • \(I_a \uparrow\) to give more power to meet the load

    • \(\phi \downarrow\) or pf increases at a faster rate than \(I_a\) to meet the load

over excitation
Over Excitation
With increase in load:
  • With increase in load:

    • For

      • p.f. tends to approach unity

      • change in p.f. is greater than \(I_a\)

    • With ,

      • change in \(I_a\) is greater than p.f. which tends to become increasingly lagging