DC Motor: Speed, Torque, & Power | Electrical Machines

Demonstrative Video

Dc Motor Basic Operational Video

Back EMF in DC Motor

Back Emf	\(I\) carrying conductor \(\Rightarrow\) \(B\) \(\Rightarrow\) \(T\) induce \(\Rightarrow\) rotates conductor \(\Rightarrow\) cuts \(\Phi\) \(\Rightarrow\) EMF induce Direction of induced EMF is opposite to \(V\) \(\Rightarrow\) Counter or Back EMF \(E_b\) series with \(V\) but opposite in direction, i.e. oppose \(I\) which causes it

Advantage of Back EMF

Electrical to Mechanical energy (\(E_bI_a\)) conversion is possible only because of \(E_b\).
\(E_b\) makes dc motor self-regulating \(\Rightarrow\) \(I=\dfrac{V-E_b}{R_a}\)
- No load \(\Rightarrow\) requires small \(T\) \(\Rightarrow\) for controlling friction and windage loss \(\Rightarrow\) withdraws less \(I\) \(\Rightarrow\) \(E_b \downarrow\)
- load \(\uparrow\) \(\Rightarrow\) \(\left(T_m<T_L\right)\) \(\Rightarrow\) \(N \downarrow\) \(\Rightarrow\) \(E_b \downarrow\) \(\Rightarrow\) \(I \uparrow\) \(\Rightarrow\) \(T \uparrow\)
- load \(\downarrow\) \(\Rightarrow\) \(\left(T_m>T_L\right)\) \(\Rightarrow\) \(N \uparrow\) \(\Rightarrow\) \(E_b \uparrow\) \(\Rightarrow\) \(I \downarrow\) \(\Rightarrow\) \(T \downarrow\)

SECTION 03

Condition for Maximum Power, \(P_m\)

\[\begin{aligned} P_{m} & =VI_{a}-I_{a}^{2}R_{a}\nonumber\\ \Rightarrow\dfrac{dP_{m}}{dI_{a}} & =V-2I_{a}R_{a}=0 \Rightarrow I_{a}R_{a} =\dfrac{V}{2} \\ \therefore V & = E_{b}+ I_{a}R_{a} = E_{b}+\dfrac{V}{2} \Rightarrow \boxed{E_{b} =\dfrac{V}{2}}\nonumber \end{aligned}\]

Torque Equation of a DC Motor

\[\begin{aligned} P_{m} & \Rightarrow E_{b}I_{a}=T_{a}\omega\\ & \Rightarrow\left(\dfrac{\Phi PN}{60}\times\dfrac{Z}{A}\right)I_{a}=T_{a}\left(\dfrac{2\pi N}{60}\right)\\ & \Rightarrow T_{a}=\dfrac{1}{2\pi}\times\dfrac{\Phi PZ}{A}\times I_{a}\\ & \boxed{T_{a} =K_{a}\phi I_{a}}\\ T_{sh} & =T_{a}-\mbox{mechanical losses} \end{aligned}\]

For series motor: \(\Phi \propto I_a \Rightarrow T_a \propto I_a^2\)

For shunt motor: \(\Phi =\) constant \(\Rightarrow T_a \propto I_a\)

Speed of a DC Motor

\[\begin{aligned} E_{b} & =V-I_{a}R_{a}\\ \Rightarrow\dfrac{\Phi PN}{60}\times\left(\dfrac{Z}{A}\right) & =V-I_{a}R_{a}\\ \Rightarrow N & =\dfrac{V-I_{a}R_{a}}{\Phi}\times\left(\dfrac{60A}{ZP}\right)\\ \Rightarrow N & =\dfrac{E_{b}}{\Phi}\times\left(\dfrac{60A}{ZP}\right)\\ \Rightarrow & \boxed{N =K\dfrac{E_{b}}{\Phi}} \end{aligned}\]

and

Relation between Torque and Speed

\[\begin{aligned} & \boxed{N =K\dfrac{E_{b}}{\Phi}}\\ & \boxed{T_{a} \propto\Phi I_{a}} \end{aligned}\]

\(T_a\) is function of \(\Phi\) and \(I_a\) but independent of \(N\)
\(N\) depends on \(T\) and not vice-versa
\(\Phi \uparrow \Rightarrow N \downarrow\) but \(T_a \uparrow\) not possiblebecause \(T\) always tends to produce rotation. If \(T \uparrow\), \(N\) must \(\uparrow\) rather than \(\downarrow\)

Following Sequence happens:

Suppose \(\Phi\) is \(\downarrow\) by \(I_f \downarrow\)
\(\left[E_b \propto N\Phi\right] \downarrow\), \(N\) = constant (inertia of heavy armature)
\(E_b \downarrow \Rightarrow \left[I_a = (V-E_b)/R_a\right] \uparrow\). Moreover, \(\Phi \downarrow \Rightarrow I_a \uparrow \uparrow\)
\(T_a \propto \Phi I_a\), \(\Phi \downarrow\) is counterbalanced by \(I_a \uparrow \uparrow\), result \(T_a \uparrow\)
\(T_a \uparrow \Rightarrow N \uparrow\)

Speed Regulation

\[\% \mbox{speed regulation} = \dfrac{N.L~speed - F.L~speed}{F.L~speed} \times 100\]

Change in speed when the load on the motor is reduced from rated value to zero, expressed as percent of the rated load speed