Single-Phase Induction Motors

Comprehensive Study of Theory, Operation, and Applications

1. Introduction

Single-phase induction motors are widely used in domestic and light commercial applications where three-phase supply is not available. These motors are simple, robust, and economical, making them ideal for fans, pumps, refrigerators, and small machine tools.

Key Characteristics:
  • Power rating: typically up to 1 kW
  • Not self-starting (requires auxiliary mechanism)
  • Lower efficiency compared to three-phase motors
  • Simple construction and maintenance

2. Double Revolving Field Theory

The fundamental principle explaining single-phase induction motor operation is the Double Revolving Field Theory, proposed by Ferraris. According to this theory, a stationary pulsating magnetic field can be resolved into two rotating magnetic fields of equal magnitude but rotating in opposite directions.

Pulsating MMF Expression

The magnetomotive force produced by a single-phase winding:

$$F = F_m \cos(\omega t) \cos(\theta)$$

where \(F_m\) is the maximum MMF, \(\omega\) is the angular frequency, and \(\theta\) is the spatial angle.

Resolution into Forward and Backward Fields

$$F = \frac{F_m}{2}\cos(\omega t - \theta) + \frac{F_m}{2}\cos(\omega t + \theta)$$

The first term represents the forward rotating field, and the second represents the backward rotating field.

Forward and Backward Slip

For the forward rotating field:

$$s_f = s = \frac{N_s - N}{N_s}$$

For the backward rotating field:

$$s_b = 2 - s = \frac{N_s - (-N)}{N_s} = \frac{N_s + N}{N_s}$$

where \(N_s\) is the synchronous speed and \(N\) is the rotor speed.

3. Equivalent Circuit

The equivalent circuit of a single-phase induction motor represents the motor as two separate motors connected in parallel - one representing the forward field and one representing the backward field.

Forward Field Impedance

$$Z_f = r_f + jx_f = \frac{(r_2'/s) + jx_2'}{2}$$

Backward Field Impedance

$$Z_b = r_b + jx_b = \frac{(r_2'/(2-s)) + jx_2'}{2}$$

Total Input Impedance

$$Z_{in} = r_1 + jx_1 + \frac{Z_f \cdot jx_m}{Z_f + jx_m} + \frac{Z_b \cdot jx_m}{Z_b + jx_m}$$

where:

  • \(r_1\) = stator resistance
  • \(x_1\) = stator leakage reactance
  • \(r_2'\) = rotor resistance referred to stator
  • \(x_2'\) = rotor leakage reactance referred to stator
  • \(x_m\) = magnetizing reactance

4. Torque Analysis

Forward Field Torque

$$T_f = \frac{1}{\omega_s} \cdot \frac{I_f^2 \cdot r_2'}{2s}$$

where \(I_f\) is the forward field current and \(\omega_s\) is the synchronous angular velocity.

Backward Field Torque

$$T_b = \frac{1}{\omega_s} \cdot \frac{I_b^2 \cdot r_2'}{2(2-s)}$$

where \(I_b\) is the backward field current. This torque opposes the motor rotation.

Net Torque

$$T_{net} = T_f - T_b$$

At standstill (s = 1):

$$T_{net} = T_f - T_b = 0$$

This explains why single-phase induction motors are not self-starting.

Note: At standstill, both forward and backward fields produce equal and opposite torques, resulting in zero net starting torque. Once the rotor starts moving (by external means), the net torque becomes positive in the direction of rotation.

5. Power Relations

Input Power

$$P_{in} = V_1 I_1 \cos\phi_1$$

where \(V_1\) is the supply voltage, \(I_1\) is the input current, and \(\phi_1\) is the power factor angle.

Stator Copper Loss

$$P_{cu1} = I_1^2 r_1$$

Air Gap Power (Forward and Backward)

$$P_{ag,f} = I_f^2 \cdot \frac{r_2'}{2s}$$ $$P_{ag,b} = I_b^2 \cdot \frac{r_2'}{2(2-s)}$$

Rotor Copper Loss

$$P_{cu2} = s \cdot P_{ag,f} + (2-s) \cdot P_{ag,b}$$

Mechanical Power Developed

$$P_{mech} = (1-s) P_{ag,f} - (1-s) P_{ag,b}$$

Output Power

$$P_{out} = P_{mech} - P_{rot}$$

where \(P_{rot}\) represents rotational losses (friction and windage).

Efficiency

$$\eta = \frac{P_{out}}{P_{in}} \times 100\%$$

6. Types of Single-Phase Induction Motors

6.1 Split-Phase Motor

Uses two windings: a main winding and an auxiliary (starting) winding. The auxiliary winding has higher resistance and lower inductance, creating a phase difference.

Phase Angle Difference

$$\alpha = \tan^{-1}\left(\frac{X_a}{R_a}\right) - \tan^{-1}\left(\frac{X_m}{R_m}\right)$$

where subscripts 'a' and 'm' denote auxiliary and main windings respectively.

Typical phase difference: 25° - 30°

Starting Torque

$$T_{start} = K \cdot V^2 \cdot \sin\alpha$$

where K is a constant depending on motor design, V is the supply voltage, and \(\alpha\) is the phase angle between the two winding currents.

6.2 Capacitor-Start Motor

A capacitor is connected in series with the auxiliary winding to achieve a larger phase displacement (approximately 90°).

Optimum Capacitance for Maximum Starting Torque

$$C = \frac{1}{2\pi f X_a}$$

For maximum torque per ampere:

$$C = \frac{1}{\omega} \sqrt{\frac{R_m^2 + X_m^2}{R_a^2 + X_a^2}} \cdot \frac{1}{X_a + \sqrt{R_a^2 + X_a^2}}$$

where \(f\) is the supply frequency and \(\omega = 2\pi f\).

6.3 Capacitor-Start Capacitor-Run Motor

Uses two capacitors: a large starting capacitor (disconnected after starting) and a smaller running capacitor (permanently connected).

Running Capacitor Value

$$C_{run} = \frac{P_{out}}{2\pi f V^2 \sin\phi}$$

where \(P_{out}\) is the output power and \(\phi\) is the desired power factor angle.

6.4 Shaded-Pole Motor

A portion of each pole is surrounded by a short-circuited copper band called a shading coil, creating a time lag in the magnetic field.

Shading Angle

$$\delta = \tan^{-1}\left(\frac{\omega L_{sh}}{R_{sh}}\right)$$

where \(L_{sh}\) and \(R_{sh}\) are the inductance and resistance of the shading coil.

Typical values: \(\delta\) = 20° - 40°

7. Performance Characteristics

Synchronous Speed

$$N_s = \frac{120f}{P}$$

where \(f\) is the frequency in Hz and \(P\) is the number of poles.

Rotor Speed

$$N = N_s(1-s)$$

where \(s\) is the slip.

Torque-Slip Relationship

$$T \propto \frac{s}{r_2'^2 + (sx_2')^2}$$

For small values of slip (normal running condition):

$$T \propto s$$

Maximum Torque (Breakdown Torque)

$$T_{max} = \frac{3V_1^2}{2\omega_s\left(r_1 + \sqrt{r_1^2 + (x_1+x_2')^2}\right)}$$

Slip at maximum torque:

$$s_{max} = \frac{r_2'}{\sqrt{r_1^2 + (x_1+x_2')^2}}$$
Motor Type Starting Torque (% of FL) Starting Current (% of FL) Efficiency
Split-Phase 100-150% 600-800% Low
Capacitor-Start 200-350% 450-550% Medium
Capacitor-Start Capacitor-Run 200-350% 400-500% High
Shaded-Pole 50-75% 200-400% Very Low

8. Starting Methods and Switching

Centrifugal Switch

Automatically disconnects the starting winding when the motor reaches approximately 75-80% of synchronous speed.

Cut-out Speed

$$N_{cutout} = (0.75 \text{ to } 0.80) \times N_s$$

Current Relay

Operates based on the reduction in starting current as the motor accelerates.

Pick-up Current

$$I_{pickup} = (1.2 \text{ to } 1.5) \times I_{rated}$$

Drop-out Current

$$I_{dropout} = (0.8 \text{ to } 0.9) \times I_{rated}$$

9. Losses and Efficiency

Total Losses

$$P_{loss} = P_{cu1} + P_{cu2} + P_{core} + P_{rot}$$

where:

  • \(P_{cu1}\) = Stator copper loss = \(I_1^2 r_1\)
  • \(P_{cu2}\) = Rotor copper loss = \(s \times P_{ag}\)
  • \(P_{core}\) = Core loss (hysteresis + eddy current)
  • \(P_{rot}\) = Rotational losses (friction + windage)

Core Loss Components

Hysteresis loss:

$$P_h = \eta B_{max}^{1.6} f V$$

Eddy current loss:

$$P_e = K_e B_{max}^2 f^2 t^2 V$$

where \(B_{max}\) is maximum flux density, \(t\) is lamination thickness, and \(V\) is volume.

10. Applications and Selection Criteria

Application Guidelines

Motor Type Typical Applications
Split-Phase Fans, blowers, small pumps, washing machines
Capacitor-Start Compressors, conveyors, machine tools, refrigerators
Capacitor-Start Capacitor-Run Air conditioners, high-performance fans, pumps
Shaded-Pole Small fans, toys, record players, low-power applications
Selection Criteria:
  • Starting Torque Requirement: High starting load requires capacitor-start or capacitor-start capacitor-run motors
  • Running Efficiency: For continuous operation, choose capacitor-run motors
  • Cost: Shaded-pole motors are cheapest, capacitor motors are more expensive
  • Power Rating: Match motor rating to load requirement with appropriate service factor
  • Duty Cycle: Consider continuous vs. intermittent operation

11. Speed Control Methods

1. Voltage Control

Since torque is proportional to the square of voltage:

$$T \propto V^2$$

Reducing voltage reduces torque and speed. Common methods include:

  • Autotransformer
  • Thyristor voltage controller
  • Tapped stator winding

2. Frequency Control

Speed is directly proportional to frequency:

$$N \propto f$$

For constant V/f ratio (constant flux):

$$\frac{V}{f} = \text{constant}$$

This method requires variable frequency drive (VFD).

3. Pole Changing

$$N_s = \frac{120f}{P}$$

Provides discrete speed steps (e.g., 2-speed or 4-speed motors).

12. Testing and Performance Evaluation

12.1 No-Load Test

Motor run at rated voltage without mechanical load.

Measurements: \(V_0\), \(I_0\), \(P_0\)

Core Loss and Rotational Loss

$$P_0 = P_{cu1,0} + P_{core} + P_{rot}$$ $$P_{core} + P_{rot} \approx P_0 - I_0^2 r_1$$

12.2 Blocked Rotor Test

Rotor is locked, reduced voltage applied to limit current to rated value.

Measurements: \(V_{sc}\), \(I_{sc}\), \(P_{sc}\)

Equivalent Impedance

$$Z_{eq} = \frac{V_{sc}}{I_{sc}}$$

Equivalent Resistance

$$r_{eq} = \frac{P_{sc}}{I_{sc}^2} = r_1 + r_2'$$

Equivalent Reactance

$$x_{eq} = \sqrt{Z_{eq}^2 - r_{eq}^2} = x_1 + x_2'$$

13. Important Design Considerations

Magnetic Circuit Design

Air Gap Flux Density

$$B_g = \frac{\phi}{A_g}$$

where \(\phi\) is the flux per pole and \(A_g\) is the air gap area.

Turns per Phase

$$T_{ph} = \frac{V}{4.44 f \phi K_w}$$

where \(K_w\) is the winding factor.

Thermal Design

Temperature Rise

$$\Delta T = \frac{P_{loss}}{A \cdot h}$$

where \(A\) is the cooling surface area and \(h\) is the heat transfer coefficient.

Current Density

$$J = \frac{I}{A_c}$$

Typical values: 3-6 A/mm² for naturally cooled motors

14. Summary of Key Formulas

Parameter Formula
Synchronous Speed \(N_s = \frac{120f}{P}\)
Slip \(s = \frac{N_s - N}{N_s}\)
Rotor Frequency \(f_r = s \cdot f\)
Forward Slip \(s_f = s\)
Backward Slip \(s_b = 2 - s\)
Efficiency \(\eta = \frac{P_{out}}{P_{in}} \times 100\%\)
Power Factor \(\cos\phi = \frac{P_{in}}{V_1 I_1}\)
Torque \(T = \frac{P_{mech}}{\omega_m} = \frac{P_{mech}}{2\pi N/60}\)
Rotor Copper Loss \(P_{cu2} = s \cdot P_{ag}\)

15. Cross-Field Theory (Alternative Analysis)

An alternative approach to analyzing single-phase induction motors, particularly useful for understanding motors with auxiliary windings.

Main Field MMF

$F_m = F_{m,max} \cos(\omega t) \cos(\theta)$

Cross Field MMF (in quadrature)

$F_c = F_{c,max} \cos(\omega t) \sin(\theta)$

The cross-field is produced by the auxiliary winding and is displaced 90° in space from the main field.

Resultant Rotating Field

$F_{res} = \sqrt{F_m^2 + F_c^2}$

For balanced two-phase operation (when \(F_m = F_c\)):

$F_{res} = F_m\sqrt{2}$

This creates a true rotating field, similar to a three-phase motor.

16. Capacitor Calculations in Detail

16.1 Starting Capacitor Design

Capacitor Value for 90° Phase Shift

$C_s = \frac{1}{2\pi f \left(X_a + \sqrt{\left(\frac{R_m Z_a}{R_a Z_m}\right)^2 - R_a^2}\right)}$

where:

  • \(Z_m = \sqrt{R_m^2 + X_m^2}\) - Main winding impedance
  • \(Z_a = \sqrt{R_a^2 + X_a^2}\) - Auxiliary winding impedance

Current Relationship

$\frac{I_a}{I_m} = \frac{N_m}{N_a} \cdot \frac{Z_m}{Z_a}$

For balanced operation:

$I_a \cdot N_a = I_m \cdot N_m$

16.2 Running Capacitor Design

Capacitor for Unity Power Factor

$C_r = \frac{P_{out} \tan\phi}{2\pi f V^2}$

For improved power factor from \(\cos\phi_1\) to \(\cos\phi_2\):

$C_r = \frac{P(\tan\phi_1 - \tan\phi_2)}{2\pi f V^2}$

Capacitor Voltage Rating

$V_C = I_a \cdot X_C = \frac{I_a}{2\pi f C}$

Typical safety factor: Select capacitor with voltage rating 1.5 to 2 times calculated value.

17. Advanced Performance Analysis

17.1 Circle Diagram

The circle diagram is a graphical method to determine motor performance at various loads.

Key Points on Circle Diagram

No-load point:

$I_0 = \frac{V}{Z_0}$

Blocked rotor point:

$I_{sc} = \frac{V}{Z_{sc}}$

Maximum torque occurs when the line from origin is tangent to the circle.

17.2 Stability Analysis

Stability Criterion

$\frac{dT}{ds} < 0$

The motor operates stably when torque decreases with increasing slip (normal operating region).

Pull-out Torque Point

$s_{pullout} = \frac{r_2'}{\sqrt{r_1^2 + (x_1 + x_2')^2}}$

Beyond this slip, the motor becomes unstable.

18. Special Operating Conditions

18.1 Plugging (Reverse Braking)

Plugging Slip

$s_{plug} = 2 - s = \frac{N_s + N}{N_s}$

For reverse rotation with slip \(s_r\):

$s_r = \frac{N_s - (-N)}{N_s} = \frac{N_s + N}{N_s}$

Braking Torque

$T_{brake} = \frac{3V^2 r_2' s_{plug}}{\omega_s(r_1 + r_2'/s_{plug})^2 + (x_1 + x_2')^2}$

18.2 Dynamic Braking

DC Injection Braking

DC current injected into stator winding creates stationary field.

$I_{dc} = \frac{V_{dc}}{R_1}$

Braking Torque with DC

$T_b = K \cdot I_{dc}^2 \cdot \omega \cdot \frac{r_2'}{r_2'^2 + (\omega x_2')^2}$

where \(\omega\) is the rotor angular velocity.

19. Effect of Voltage and Frequency Variations

Voltage Variation Effects

Torque variation:

$T \propto V^2$ $T_2 = T_1 \left(\frac{V_2}{V_1}\right)^2$

Current variation (approximately):

$I \propto V$

Efficiency change:

$\eta_2 \approx \eta_1 - k\left(1 - \frac{V_2}{V_1}\right)$

where \(k\) is a constant (typically 0.01-0.02).

Frequency Variation Effects

Synchronous speed:

$N_{s2} = N_{s1} \cdot \frac{f_2}{f_1}$

For constant V/f operation:

$\frac{V_2}{V_1} = \frac{f_2}{f_1}$

Flux remains approximately constant:

$\phi_2 \approx \phi_1$

Torque capability:

$T_{max} \approx \text{constant}$
Standard Tolerances (NEMA):
  • Voltage variation: ±10% of rated voltage
  • Frequency variation: ±5% of rated frequency
  • Combined voltage and frequency variation: ±10%

20. Motor Protection and Safety

20.1 Thermal Protection

Thermal Time Constant

$\tau_{th} = \frac{m \cdot c_p}{A \cdot h}$

where:

  • \(m\) = mass of motor
  • \(c_p\) = specific heat capacity
  • \(A\) = cooling surface area
  • \(h\) = heat transfer coefficient

Temperature Rise Over Time

$T(t) = T_{\infty}(1 - e^{-t/\tau_{th}})$

where \(T_{\infty}\) is the steady-state temperature rise.

20.2 Overcurrent Protection

Full Load Current Estimation

$I_{FL} = \frac{P_{rated} \times 1000}{V \times \eta \times \cos\phi}$

Fuse/Breaker Rating

$I_{protection} = (1.15 \text{ to } 1.25) \times I_{FL}$

For motors with high starting current:

$I_{protection} = (2.0 \text{ to } 2.5) \times I_{FL}$

21. Harmonic Analysis

Space Harmonics in MMF

$F(\theta) = \sum_{n=1,3,5,...}^{\infty} F_n \cos(n\theta)$

where the nth harmonic amplitude:

$F_n = \frac{4F_m}{n\pi} \cdot K_{wn}$

\(K_{wn}\) is the winding factor for nth harmonic.

Harmonic Torques

For nth space harmonic:

$T_n = \frac{P_n}{\omega_s/n}$

Synchronous speed of nth harmonic:

$N_{sn} = \frac{120f}{n \cdot P}$

Effects of Harmonics

  • Additional heating due to harmonic currents
  • Torque pulsations causing noise and vibration
  • Reduced average torque and efficiency
  • Crawling phenomenon at 1/7th of synchronous speed (7th harmonic)
  • Cogging or locking at standstill due to harmonic interaction

22. Worked Example Problem

Example: Capacitor-Start Motor Analysis

Given:

  • Power rating: 0.5 HP (373 W)
  • Supply: 230 V, 50 Hz
  • Main winding: \(R_m = 8\,\Omega\), \(X_m = 10\,\Omega\)
  • Auxiliary winding: \(R_a = 12\,\Omega\), \(X_a = 8\,\Omega\)

Solution Steps:

1. Calculate impedances:

$Z_m = \sqrt{R_m^2 + X_m^2} = \sqrt{8^2 + 10^2} = 12.81\,\Omega$ $Z_a = \sqrt{R_a^2 + X_a^2} = \sqrt{12^2 + 8^2} = 14.42\,\Omega$

2. Phase angles:

$\theta_m = \tan^{-1}\left(\frac{X_m}{R_m}\right) = \tan^{-1}\left(\frac{10}{8}\right) = 51.34°$ $\theta_a = \tan^{-1}\left(\frac{X_a}{R_a}\right) = \tan^{-1}\left(\frac{8}{12}\right) = 33.69°$

3. Phase difference without capacitor:

$\alpha = \theta_m - \theta_a = 51.34° - 33.69° = 17.65°$

4. Starting capacitor for 90° phase shift:

$X_C = \sqrt{\left(\frac{R_m Z_a}{R_a Z_m}\right)^2 - R_a^2} - X_a$ $X_C = \sqrt{\left(\frac{8 \times 14.42}{12 \times 12.81}\right)^2 - 12^2} - 8 = 28.5\,\Omega$ $C_s = \frac{1}{2\pi f X_C} = \frac{1}{2\pi \times 50 \times 28.5} = 112\,\mu F$

5. Starting currents:

$I_m = \frac{V}{Z_m} = \frac{230}{12.81} = 17.96\,A$ $Z_a' = \sqrt{R_a^2 + (X_a - X_C)^2} = \sqrt{12^2 + (8-28.5)^2} = 23.77\,\Omega$ $I_a = \frac{V}{Z_a'} = \frac{230}{23.77} = 9.68\,A$

23. Maintenance and Troubleshooting

Common Problems and Diagnosis

Symptom Possible Cause Diagnostic Test
Motor won't start Faulty starting mechanism, open winding Check continuity, test centrifugal switch
Low starting torque Failed capacitor, wrong capacitor value Measure capacitance, check ESR
Overheating Overload, poor ventilation, voltage imbalance Measure current, check voltage, inspect cooling
Excessive vibration Unbalanced rotor, misalignment, worn bearings Check mechanical alignment, bearing condition
Humming without rotation Locked rotor, single-phasing, high load Check mechanical freedom, starting circuit

Insulation Resistance Test

Minimum acceptable insulation resistance:

$R_{ins} = \frac{V_{rated}}{1000} + 1\,\text{M}\Omega$

For example, for 230 V motor:

$R_{ins} = \frac{230}{1000} + 1 = 1.23\,\text{M}\Omega$

24. Energy Efficiency and Standards

Efficiency Classes (IEC 60034-30)

Standard efficiency (SE): \(\eta_{SE} = \eta_{nominal} - 15\%\)

High efficiency (HE): \(\eta_{HE} = \eta_{nominal} - 10\%\)

Premium efficiency (PE): \(\eta_{PE} = \eta_{nominal} - 5\%\)

Energy Savings Calculation

Annual energy consumption:

$E_{annual} = \frac{P_{rated} \times t_{operation} \times L}{\eta}$

Energy savings by upgrading efficiency:

$\Delta E = P_{rated} \times t \times L \times \left(\frac{1}{\eta_1} - \frac{1}{\eta_2}\right)$

where:

  • \(P_{rated}\) = rated power in kW
  • \(t\) = operating hours per year
  • \(L\) = load factor (0 to 1)
  • \(\eta_1, \eta_2\) = old and new efficiencies

25. Conclusion and Summary

Key Takeaways

  • Operating Principle: Single-phase induction motors operate on the principle of double revolving field theory, requiring auxiliary means for starting
  • Starting Methods: Various starting methods (split-phase, capacitor-start, shaded-pole) provide different torque-speed characteristics for different applications
  • Performance: Performance is analyzed using equivalent circuit, considering both forward and backward rotating fields
  • Efficiency: Generally lower than three-phase motors, but adequate for fractional horsepower applications
  • Applications: Widely used in residential and light commercial applications up to 1-2 HP

Design Trade-offs

Parameter Improvement Method Trade-off
Starting Torque Use capacitor-start design Increased cost and complexity
Efficiency Use capacitor-run design Higher initial cost
Power Factor Optimize capacitor value May reduce torque capability
Cost Use shaded-pole design Lower efficiency and torque

26. Quick Reference Formulas

Category Formula Units
Speed \(N_s = \frac{120f}{P}\) RPM
Slip \(s = \frac{N_s - N}{N_s}\) -
Torque \(T = \frac{9.55 \times P_{mech}}{N}\) N-m
Power \(P = V I \cos\phi\) W
Efficiency \(\eta = \frac{P_{out}}{P_{in}}\) %
Capacitance \(C = \frac{1}{2\pi f X_C}\) F