A two-bus system shown in the below figure has the incremental fuel characteristics given by,
When 100 MW of power is transmitted from plant 1 to the load, a transmission loss of 10 MW is incurred. If the incremental cost is Rs. 25/ MWh, then find the required generation for each power plant.
System Data:
Calculating Loss Coefficient \(B_{11}\)
\[ P_L = B_{11} \times P_{G1}^2 \implies 10 = B_{11} \times 100^2 \implies B_{11} = \dfrac{10}{10,000} = 1 \times 10^{-3}\, \text{MW}^{-1} \]Economic Dispatch with Loss Coordination
Adjusts generation to account for transmission losses using penalty factors:
\[ L_i = \dfrac{1}{1 - \dfrac{\partial P_L}{\partial P_{Gi}}} \]Optimality Condition:
\[ \dfrac{dF_i}{dP_{Gi}} \cdot L_i = \lambda \]With Coordination:
Without Coordination:
Like choosing between a traffic-aware GPS (with coordination) vs. shortest path (without).
With Coordination
\[ \begin{cases} \dfrac{0.02P_1 + 16}{1 - 2 \times 10^{-3}P_1} = 25 \\ 0.04P_2 + 20 = 25 \end{cases} \]Solution:
\[ P_1 = 128.57\, \text{MW}, \quad P_2 = 125\, \text{MW} \]Loss = 16.53 MW
Without Coordination
\[ \begin{cases} 0.02P_1 + 16 = 0.04P_2 + 20 \\ P_1 + P_2 = 237.04 \end{cases} \]Solution:
\[ P_1 = 275.17\, \text{MW}, \quad P_2 = 37.59\, \text{MW} \]Loss = 75.72 MW
Cost Savings for G1:
\[ \int_{128.57}^{275.17} \!\!\!\! (0.02P_1 + 16)\, dP_1 \] \[ = \text{Rs } 2937.69/\text{h} \]Cost Increase for G2:
\[ \int_{37.59}^{125} \!\!\!\! (0.04P_2 + 20)\, dP_2 \] \[ = \text{Rs } 2032.43/\text{h} \]Net Savings
\[ 2937.69 - 2032.43 = \text{Rs } 905.26/\text{h} \]